get help in general - we have more specialized help rooms here: https://gitter.im/FreeCodeCamp/home
Is it me or some challenges in Javascript are really confusing
@bestintown23 The image is taking 100% of the width in my guess which is why the paragraph can't filled the place
try to put image and text in a container after that a id for the image and P
try width 30% on image 65% on the P
@bestintown23 https://codepen.io/EngjellBislimi/pen/JrRdMd
there is many ways to actually put it but just remember that if you don't fix the width of your element he will take all the width page.
even better putting the text at margin: auto;
Hi guys! I’m on the task “Check for palindromes”. It asks me to remove all the non-alphanumeric characters and turn things into lower case in order to check for palindromes. Here’re the codes I’ve put but they don’t work…
function palindrome(str) {
// Good luck!
if (str.replace(/[^\w\s]/gi, '').toLowerCase())
return true;
else {
return false;
}
}
palindrome("not a palindrome”);
Does anyone know what’s wrong with my codes?
@crystalclea
str.replace(/[^\w\s]/gi, '').toLowerCase()
this returns a value
but you're not using it anywhere
@Manish-Giri what do you mean by that?
@crystalclea don't you want to compare that value with something?
it asks me to return “true” if the string is a palindrome and return “false” after testing that it’s not
@Manish-Giri however, after typing the conditions, i tested the strings and no matter what i put, they return “true"
and how do you check if something is a palindrome?
@crystalclea
by removing all the weird symbols and turning them all to lowercase? then if the string reverse and it’s still spelt the same, it’s a palindrome
yea
but you only did the first part
where's this part?
then if the string reverse and it’s still spelt the same,
oh yeah ! let me rethink about it
and it's returning true always because of this lineif (str.replace(/[^\w\s]/gi, '').toLowerCase())
this just checks if what's inside the if is a truthy value, and unless you enter an empty string, it will always return true
oh…they don’t have taking out the symbols and turning to lowercase?
um
this line does that
example - if your input was
Wo$rD
this if would return the value
word
and
if(word) is always true
ohhh!! i get what u mean
after removing all the weird stuff, it doesn’t help validate thevakue
nope
you need to write more code for that
i'd recommend starting with saving the lowercased value first
var cleanedUp = str.replace(/[^\w\s]/gi, '').toLowerCase();
then you can compare this to it's reversed value
and check if it's equal or not
if equal -> palindrome
else no palindrome
ohhhhhhh!!! ur tips are super useful
:+1:
And finnally i have internet back :D that was long
Hello everyone
@Gersho hello
@Gersho wb
Oh Eric, lost power when we were talking the overday xD and when power went back on internet didn't
how's your tictactoe going ?
@Manish-Giri i’ve passed the challenge!!! Thank you so much!!!
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@crystalclea niice!
i didnt do the no win thing, since it wasnt a requirement anymore
didn't either, i feel like it should be easy since it's a children game
your tictactoe looks cool, only bad thing i have to say is that you can't play twice
you can
just give it a sec
i can lower the time
oh i see it
@ericmiller777 - nice styling on the tic-tac-toe - I like that! They removed the "no win" requirement? That's good (I think)
yea, its not even a bonus staory anymore
story
i should start on simon but i been lazy
Simon's CSS drove me crazy
can someone help? I am on Pairwise challenge, I can't find the mistake on my code
function pairwise(arr, arg) {
if (arr.length == 0) return 0;
var objarr = [];
var final = 0;
for (i=0;i<arr.length;i++) {
objarr.push({
"id":i,
"value":arr[i],
"canused": true
});
}
for (j=0;j<arr.length;j++) {
if (objarr[j].canused) {
for (k=1;k<arr.length;k++) {
if (objarr[j].canused && objarr[k].canused && objarr[j].value + objarr[k].value == arg) {
final = final + j+k;
objarr[j].canused = objarr[k].canused = false;
console.log(objarr[j].canused + objarr[k].canused);
}
}
}
}
return final;
}
pairwise([1, 1, 1], 2);
yea, if i want it to look like simon looks hard
is pairwise the name of the challenge ?
havnt dont that one yet, gl and congrtas on finishing
done
its the last advanced algorithm
oh that's why i couldn't find it in my profile page, haven't done it yet xD
nevermind @Gersho i've fixed my mistake, i should have written j !== k . yes pairwise is the challenge's name.
@Gersho did you make a circle simon or a square, square seems simple
circle, i did it with 4 square (1 each color) and making it round with border radius
@ericmiller777
i see
@Gersho thanks
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with that method i had to use z-index so the center interface is visible
evening fCC
:wave:
@thekholm80 hey thanks for the thanks!
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camperbot was down earlier
@Gersho hye brutha what up?
my internet was down for the last few days
also water
but everything's back we can be humans again
yer water was off too?
we had stock ^^
nothing quite like being human again ;)!~
on a more funny note, Canal + building was damaged a bit, the C fell of the main display
oh yah! i forgot yer in the path of that latest hurricane
:O
all good?
well apart from the water and internet yeah
@DarrenfJ TY :cookie: for you :)
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minimal damage in town, mostly stuff that we're glad it broke down so the town will be forced to deal with it
oh thanks man for the brownies :D
and some back atcha
thanks @Gersho @heroiczero
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@Gersho honestly, i am glad you are ok :D
thanks @DarrenfJ :)
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ok gonna sneak off and watch vids/podcasts :D
@DarrenfJ ty
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@Gersho good to hear you're safe..
@Manish-Giri :wave: Hello Cookie to you TY
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@heroiczero :wave: ty
(@&$@#&$@#&$)@##@$
\o/ thanks @Manish-Giri
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@heroiczero thx
oh ffs
@heroiczero ty
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Hi everyone
:wave:
@dsandeepchary - hey there...
khaduch @khaduch - signing off for the night - happy coding everyone!
@khaduch good night
hello
@camperbot sup
Hello
Is there anyone from UK here working as a developer?
function sumPrimes(num) {
var arr = [];
var newArr;
for (var i =2; i<= num; i++){
arr.push(i);
}
for (var x = 2; x < arr.length; x++){
var m = Math.sqrt(arr[x]);
for (var y = 2; y<= m; y++){
if (arr[x]%y === 0){
arr.splice(x,1);
}
}
}
console.log(newArr);
return arr;
}
sumPrimes(20); //[2,3,5,7,9,11,13,16,17,19]
@rscales02 Is't problem here?
var m = Math.sqrt(arr[x]);
I don't think so... that decreases the number of iterations for my for(y) loop by half, I shouldn't need to test anything above the square root of
arr[x]... for the example of 9: m=3 meaning 'for(y)would test 2 and 3. givingif (9%3 == 0) {splice(9)}`
@rscales02 Your loop doesn't run for numbers 5, 7, 9, 16
Any idea why?
you need x--; after splice
ah!
thanks!
because you remove element, but don't move counter and one element is skipped
Thanks @korzo !
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@rscales02 Rule of thumb is to not use splice inside for loop. It introduces bugs like this.
Also you can clean your code a bit by using filter or extracting part of the code to function isPrime
Also you can clean your code a bit by using filter or extracting part of the code to function isPrime
as in making a new
function isPrime(){}? Or is that built in?
function isPrime(){}
It's easier to process true/false inside loop
Why make things easier on myself lol :smile: let me see if I can implement that...
Because you have to return sum of primes.
If you extract
var m = Math.sqrt(arr[x]);
for (var y = 2; y<= m; y++){
if (arr[x]%y === 0){
arr.splice(x,1);
}
}to function and the just test if arr[x] is prime and add it to sum
or use reduce as you have numbers in array
I am not clear on what you are suggesting... If I take that out of the loop and place it into another function x becomes an undefined variable unless I also include
var x = ;
I am also not sure how
true and false results could be turned back on the sumPrime() function usefully...
function sumPrimes(num) {
var arr = [];
var newArr;
for (var i = 2; i <= num; i++) {
arr.push(i);
}
for (var x = 2; x < arr.length; x++) {
if (isPrime() === false) {
arr.splice(x, 1);
x--;
}
}
function isPrime() {
var m = Math.sqrt(arr[x]);
for (var y = 2; y <= m; y++) {
if (arr[x] % y === 0) {
return false;
} else {
return true;
}
}
}
console.log(arr);
}
sumPrimes(20);
@rscales02 You need to be careful about
if return else return inside a loop or it won't loop - your true condition is probably not valid until the loop completes
@rscales02 Pass a value to the isPrime function and test that value
function isPrime(v) {
var m = Math.sqrt(v);
@rscales02
function sumPrimes(num) {
var arr = [];
var newArr;
for (var i =2; i<= num; i++){
arr.push(i);
}
return arr.reduce((a,e) => isPrime(e) ? a+e : a , 0);
}
function isPrime(n) {
var m = Math.sqrt(n);
for (var y = 2; y<= m; y++){
if (n%y === 0){
return false;
}
}
return true;
}
ok... wow...
@rscales02 Or with for loop
function sumPrimes(num) {
var sum = 0;
for (var i =2; i<= num; i++){
if(isPrime(i)) {
sum +=i;
}
}
return sum;
}
function isPrime(n) {
var m = Math.sqrt(n);
for (var y = 2; y<= m; y++){
if (n%y === 0){
return false;
}
}
return true;
}
That one I understand and I see what you mean by cleaning it up
why don't you have to specify
if(isPrime(i) == true?
@rscales02 because isPrime return boolean (true or false)
OK, I think I understand... although my brain hurts now... thanks @korzo
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@rscales02 if you compare to true ( === true) you don't have to specify it.
Javascript will convert expression to boolean automatically
Javascript will convert expression to boolean automatically
@rscales02 Try reading the code in natural language.
start sum at zero
for each number from 2 to num
if number isPrime
add number to sum
I am still trying to get google translate to work that out for me into javascript lol, thanks @sjames1958gm I will try that out...
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@rscales02 lol :)
How to search a question in stackoverflow using api?
Hey guys, can't understand why my bars are drawen from the wrong side instead of 1950 being the lowest value, highest GDP is drawen in 1950 instead of 2015.
https://codepen.io/artbohr/pen/mMKxKg?editors=1010
https://codepen.io/artbohr/pen/mMKxKg?editors=1010
also if you see any clear bug in there, would be much appreciated apparts of the stated main problem
@artbohr Possibly reverse the range
([0, height]);
.range([0, height]);
@sjames1958gm that does it, but why is it working tho? I mean in all the tutorial examples it's like I had it because of the Y axis being drawn from above, do I probably have something reversed in the code? thanks
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hmm, not sure
Yeah you're numbers are backwards, the bars should increase
@cmccormack ye, but where? xD
I remember having trouble with that as well haha
Jeeze just realized how bad my code was for that project, you sure learn a lot as you go
So i have a function that ends with
return a and the result is d, but when I try return a.match(/a-z/) it returns null shouldn't it return 0 since the string is only one letter long?
nevermind brackets apparently make a difference :smile:
@cmccormack haha, usual thing ^^, so didn't find the mystery reverse?
@artbohr in your code?
@cmccormack ye
@artbohr you're using
const y = d3.scaleLinear()
.domain([0,20000])
.range([height,0]);Which means when you pass a value to the scaling function you're going to return a number for the range. So if 0 goes in, height will come out. You just need to swap that
honestly you can do it a few different ways, it all depends on how you draw it
@rscales02 Yes /a-z/ means a then dash then z
Its always the little things :smile:
Hello, I'm working on seek and destroy exercise and I am so close to finishing it but I am stuck on the part where
return word !== array[i]; only inspect the 2nd argument and not the 3rd argument. I can't think of any other ways for the filter to check the third argument. Any help is appreciated!function destroyer(arr) {
// Remove all the values
var array = [];
for(var i = 1; i<arguments.length; i++) {
array.push(arguments[i]);
}
return arr.filter(function(word){
for(var i = 0; i < arguments.length; i++) {
// console.log(word !== arguments[i]);
return word !== array[i];
}
});
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
You could also do it like you have it now but then draw it like this:
.attr("height", d => {
return height - y(d[1]);
})
...
.attr("y", d => {
return y(d[1]);
});
@cmccormack that's the thing I was looking for, thank you very much!
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@artbohr I would also recommend using your extents for your domain as well:
.domain(d3.extent(data.data, (d)=>d[1]))
@cmccormack got it, ty
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api offline
@artbohr thank you for forcing me to evaluate my own code and make it better :D
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@cmccormack you are welcome! haha
@quickspeedy https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/arguments a little down there is a shown a way to store arguments in an array (Array.from(arguments). In this case also the array passed into the function would be included but you can use the shift method to get rid of that array. So you'll have arr, which is the array passed in, and you'll have an array with the 2 and 3 in this case. Then you can filter arr with indexOf on last array.
Ok thanks for the advice! @alexanderkopke
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How to center a div, and to be responsive at the same time? plss pleaseeee <3
@razvanlikespizza Depends on the content in the div, but for most you can start with:
margin-left: auto;
margin-right: auto;
max-width: 100%;
fam im setting up a new value for the first name but it not returing the value from the parameter that i set.
var Person = function(firstAndLast) {
// Complete the method below and implement the others similarly
// this.getFullName = function() {
// return "";
// };
var first = firstAndLast.split(' ')[0];
var last = firstAndLast.split(' ')[1];
var fullName = first + ' ' + last;
return {
getFullName: function() {
return fullName;
},
getFirstName: function() {
return first;
},
getLastName: function() {
return last;
},
setFirstName: function(newFirst) {
first = newFirst;
},
setLastName: function(newLast) {
last = newLast;
},
setFullName: function(newFullname) {
firstAndLast = newFullname;
}
};
};
var bob = new Person('Bob Ross');
bob.setFirstName('check');
bob.getFullName();
@razvanlikespizza I suggest taking a look at flexbox, using their justification and alignment. But otherwise try
margin: 0 auto;
@artoodeeto still there?
@artoodeeto The reason is because your getFullName() is calling your var fullName which is set as soon as the function is called.
@artoodeeto and isn't changed by calling setFirstName();
@artoodeeto if you do something like this:
getFullName: function(){
fullName = first + ' ' +last;
return fullName;
}
Yeah it was answered in Help JavaScript as well and he never responded
damn, been a while since i've been on here, sticky fingers.
ah okay.
@ehutchllew I agree with your solution though
or just return the interpolation without creating a variable, either way
yeah, I haven't used that type of function syntax in a minute
been mainly working with React.
Yeah weird how with React you stop writing normal code haha
it's almost all declarative
yeah, I do like components and classes though :D
@ehutchllew yow bro
@ehutchllew broooo??
@artoodeeto what's up
The challenge is to remove all elements in the array [1, 2, 3, 1, 2, 3] that match the arguments outside the array (2, 3). Trying to iterate through arr and args, then filtering and returning whatever isn't equal.
Am I in the ballpark here?
Am I in the ballpark here?
function destroyer(arr) {
// Remove all the values
var args = Array.prototype.slice.call(arguments);
var newArray;
newArray=arr.filter(function(arr){
for (var i=0; i < arr.length; i++) {for (var j=1; j < args.length; j++)
return arr[i] != args[j]; }
});
return args[1];
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
I'm on my phone , waisting time, what should I read?
Hey! I'm trying to make a gradient background (going diagonal). This works: background: linear-gradient(to right, red, yellow); but this doesn't: background: linear-gradient(to bottom right, red, yellow); when I try this, the backgorund just starts repeating.
@keanusuasuasuasuasuas :point_up: I answered you over here
@ravikishorethella :smile:
@korzo :smile: that is a good thing to read right?
@ravikishorethella it is, but probably not something to read nonchalantly on mobile
@korzo yes, you are right. I should have suggested him to read
YDKJS book. That would be a good option and infact that is quite interesting as well
@ravikishorethella yes, this is much better option. or JS the right way
ECMA is extremely hard to read and you need to have open several pages for references.
ECMA is extremely hard to read and you need to have open several pages for references.
Yes