get help in general - we have more specialized help rooms here: https://gitter.im/FreeCodeCamp/home
@sjames1958gm @daddycardona @Manish-Giri @khaduch @GitHub-Henry @Gersho @DarrenfJ TY for the usual people helping people out.
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@sjames1958gm @daddycardona @Manish-Giri @khaduch @GitHub-Henry @Gersho @DarrenfJ @heroiczero thank you to all my sweet hearts LOL is it February yet LOL
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@ericmiller777 thank you too :)
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tomorrow I will take on the Binary Agents I had someone help explain recursion better :) and finished up steam roller :)
@daddycardona thanks
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@daddycardona hello, and ty for the brownies
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@gishy1 sorry, did you figure it out? Try resetting your code.
@ericmiller777 ya bro was that the longest word challenge eventually, now the title challenge is the next.
hello wanted to ask can you pop individual characters of a string in an array?
Hi, need help with countryapi json data, anyone care to help?
@shutupchigo what api?
Hi @sorinr , this one http://countryapi.gear.host/v1/Country/getCountries?pName=china
how would I display Name: China and so forth?
help？how to删除所有的注释标记
@shutupchigo data.Response[0].Name
@shutupchigo where data is what you get from JSON.parse
@daddycardona - thanks for the cheers, and good luck with the recursion - it's tricky to understand that concept sometimes!
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@heroiczero - to you and @DarrenfJ and the "regulars" - have a great day and thanks for keeping the rooms going!
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@gishy1 You return from inside the loop
not understanding @korzo
you mean i remove the return a ?
@gishy1 No
@gishy1
return arr[a][0].toUpperCase();
@korzo i remove it ?
@gishy1 It will return first letter from first word
You have to replace it
You have to replace it
arr[a] is current word. And you have to modify it and uppercase first letter
@korzo im not unuderstanding you because
@gishy1
function titleCase(str) {
var arr = str.split(' ');
for (var a = 0; a < arr.length; a++) {
arr[a] = arr[a].toLowerCase();
arr[a] = arr[a][0].toUpperCase() + arr[a].substr(1);
}
return arr.join(' ');
}
@gishy1
arr[a] = arr[a].toLowerCase(); lower case the word
@gishy1
then uppercase first letter of word , add rest of the word and assign it back to arr[a]
arr[a] = arr[a][0].toUpperCase() + arr[a].substr(1);then uppercase first letter of word , add rest of the word and assign it back to arr[a]
i thought the for loop would run through and capitalise the first letters in each of the strings?
@gishy1
return returns from function.
@gishy1 toLowerCase and to UpperCase return new string, so you have to assign it
str.toLowerCase() does nothing
you have to assign it back:
str.toLowerCase() does nothing
you have to assign it back:
str = str.toLowerCase()
@korzo bro im sorry im not fully getting it
@korzo t
arr[a] = arr[a].toLowerCase();
arr[a] = arr[a][0].toUpperCase() + arr[a].substr(1);
arr[a] = arr[a][0].toUpperCase() + arr[a].substr(1);
part is confusing me
@gishy1
function titleCase(str) {
var arr = str.split(' ');
for (var a = 0; a < arr.length; a++) {
var word = arr[a];
word = word.toLowerCase();
var firstLetter = word[0].toUpperCase();
var restOfTheWord = word.substr(1);
var finalWord = firstLetter + restOfTheWord;
arr[a] = finalWord;
}
return arr.join(' ');
}
@alpox thanks
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@korzo np :D
(Where (here is the title and the answer, you can refer to this website to see the meaning of the whole sentence)? -----> includes (inputs [inputs.length-1] === true https://stackoverflow.com/questions/40630580/javascript-to-fixed-method)))
inputs.length-1 ----> Why subtract 1?
inputs.length-1 ----> Why subtract 1?
@korzo thanks bro let me try and work through it
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@georgiawang5332 cuz array indices start counting from 0
but length counts from 1
soo
and element 4 is on
but length counts from 1
soo
arr= [1,2,3,4] <-- u have 4 elements (length)and element 4 is on
arr[3] (index 3)
I am getting an error message for so many days on the beta.freecodecamp.org maps section
And this is the same error I am getting on my friend's laptop too
FREEDOM
onto backend api and microservice projects.
Soon I shall be one of the 5% who completed everything buwahaha
@knight2 congrats
@GitHub-Henry the journey has just begun :P
@mukul23 beta course is quite buggy. But the first four sections should be fine. Just hit control + enter, or manually select the next part in the menu on the left. If you google your section header + freecodecamp when you think you are right but getting an error, there is almost always some post about what is right/wrong on some github issue
This is only for the first 4 sections
also sometimes errors can be fixed for submission by just adding a query string with any random input after can have a section submit when it isn't submitting before.
hello everyone what built in function thats returns a "number" or "string" or "array"?
@artoodeeto could you explain what your trying to do, and link the challenge.
Hey guys, does anyone here know how to properly convert a string to double?
Been playing around with 'std::stod' but I can't figure it out :(
Greetings.
Hey
Never mind solved it
@ericmiller777 nvm bro. i got. thanks for the reply though
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@Burinson
I need some help with a challenge
function whatIsInAName(collection, source) {
// What's in a name?
// Only change code below this line
for (let prop in collection) { // prop = arr[#]
var ArrWithSource = collection.filter((function(objects){
// Return the array that has the following condition:
var sourceProp = source[Object.keys(source)];
// Property of the source key
var sourceKey = [Object.keys(source)];
// Key of the source value
return objects[sourceKey] === sourceProp;
// Filter the array where the requested property is equal to the one inside the source argument
}));
return ArrWithSource;
}
// Only change code above this line
}
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });My code only works when the source argument only has 1 object
It passed the challenges where it only has 1 object (the first 2)
But I don't know how to make it work with 2 objects (a and b)
When I console.log(sourceKey) it returns 0
:
(2) ["a", "b"]
length
:
1
__proto__
:
Array(0)
And that's how it's supposed to work, the problem is that console.log(objects[sourceKey]); returns undefined because it can't check both at the same time
I need a way to first check a, then b and so on...
returning too soon.. u need to check all source props first @Burinson
u can also remove that
u can also remove that
for..in statement
@moigithub What statement?
@moigithub Oh, you're right, I don't need the for..in because filter is a looper, right?
ye
Hi All,
I'm working on implementing jQuery into my Quote Generator project. I want to have the color of my twitter button, body background, and button background change when I click the button. I've gotten the twitter button and body background to work but the button won't change color! Here is a link to my codepen https://codepen.io/MattUnderwood/pen/ZJjjOb
any feedback is appreciated!
evening fCC
kudos and thank you's to the regulars who keep this place alive
@moigithub
function whatIsInAName(collection, source) {
// What's in a name?
// Only change code below this line
var ArrWithSource = collection.filter((function(objects){
// Return the array that has the following condition:
var sourceProp = source[Object.keys(source)];
// Property of the source key
var sourceKey = [Object.keys(source)];
// Key of the source value
return objects[sourceKey] === sourceProp;
// Filter the array where the requested property is equal to the one inside the source argument
}));
return ArrWithSource;
}
// Only change code above this line
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
Which return statement is the one that is too soon?
the one inside filter
@moigithub You mean it should go outside?
Wouldn't that take everything out of scope?
nope.. it should return ONLY after checking ALL source properties
thanks @artoodeeto @ericmiller777 @GitHub-Henry @knight2 @khaduch @GitHub-Henry @heroiczero @daddycardona @sjames1958gm @thekholm80 @Manish-Giri
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off to watch bad tv
@moigithub :worried:
@DarrenfJ ohh. i got my first cookie. thank you too bro
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@moigithub An... if statement?
How can I do that?
one way
loop on all sources
if (source prop !== collection prop)
return false; //one prop dont match
return true; //all matchesanther way is using .every method