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@moigithub
function whatIsInAName(collection, source) {
// What's in a name?
// Only change code below this line
var ArrWithSource = collection.filter((function(objects){
// Return the array that has the following condition:
var sourceProp = source[Object.keys(source)];
// Property of the source key in source args
var sourceKey = [Object.keys(source)];
// Key of the source value in collection args
if (sourceProp != sourceKey) {
return false;
} else { return true;}
return objects[sourceKey] === sourceProp;
// Filter the array where the requested property is equal to the one inside the source argument
}));
return ArrWithSource;
}
// Only change code above this line
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
Kind of like this?
@Burinson source can have more than one key
u need aloop to check ALL sources properties, like the example above.....
@moigithub Okay... a loop...
function whatIsInAName(collection, source) {
// What's in a name?
// Only change code below this line
var ArrWithSource = collection.filter((function(objects){
// Return the array that has the following condition:
var sourceProp = source[Object.keys(source)];
// Property of source args
var sourceKey = [Object.keys(source)];
// Key of the source value in collection args
var i = -1;
while (i < sourceKey[0].length-1) {
i++;
return objects[sourceKey[0][i]] === sourceProp;
}
// Filter the array where the requested property is equal to the one inside the source argument
}));
return ArrWithSource;
}
// Only change code above this line
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
its NOT ONLY a loop.. re-READ the pseudocode above...
@Burinson why do you have a return statement inside a while loop?
I'm getting so stressed
putting a return statement inside a while loop will immediately execute the loop and not go through any more increments
Perhaps you are looking to return if you hit a certain value?
@moigithub I literally don't even understand anymore
@DarrenfJ ty sir
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@moigithub thank you XD
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@DarrenfJ thanks
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@heroiczero @daddycardona @DarrenfJ @thekholm80 ty
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Hey all!
@TeddyHugs buddy
@TeddyHugs ty
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@Manish-Giri ty
how's it going
It's okay. And you? :D
I've been too busy with new projects at work >_<
Not fun at all
lol
fun times
@Manish-Giri thank you for that xD
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@daddycardona @DarrenfJ @thekholm80 ty @Manish-Giri
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Hiiii
So I am stuck in a bit of a sticky situation, trying to make a person by myself (ba dum cha!) and I don't fully understand the error I am getting.
var Person = function(firstAndLast) {
var name = firstAndLast;
this.getFullName = function() {
return "name";
};
this.getLastName = function() {
name = name.split(" ");
return name[1];
};
this.getFirstName = function() {
name = name.split(" ");
return name[0];
};
this.setFirstName = function(str) {
name.split(" ");
name[0] = str;
name.join(" ");
return name;
};
return firstAndLast;
};
var bob = new Person('Bob Ross');
bob.setFirstName(dan); //returns error at this line saying "dan is not defined"
bob.getFullName();
@rscales02 You are trying to pass a variable called dan that doesn't exist.
I guess what you want is
bob.setFirstName("dan")
stupid little details :smile: thanks @Pethaf
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with that fixed, if I just run
bob.setFirstName("dan") it returns "dan ross" but then when I run bob.getFullName() immediately after it returns name any idea why?
@DarrenfJ hello, and ty for the brownies
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Is there a way to auto-size a box around the random text that will be displayed?
I've been looking for a way to autosize the message that I'm going to display.
What do I need to do?
@rscales02 did you even look at the fuction you are complaiing about?
this.getFullName = function() {
return "name";
};
Maybe because it literally returns "name" every time?
remove the "name" and change it to return your variable.
Hey guys
girls...
@MWBauer :wave:
@MWBauer If you don't give it height or width it should size to content (plus padding)
How do you return only the true statements in a for loop?
Ex
true,
false,
true
Only return the first and third result
@Burinson if you return inside of a loop, you leave the loop instantly. Instead, collext the data inside of the loop and return after it.
Storing it in a variable?
And calling it outside of the loop?
Store it in a variable, yes. You cannot call a variable though, you can only call functions.
You can return the contents of a variable from a function though - which i meant to do after the loop
@alpox Mind giving me an example? Thanks
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An example where you call the var from a function
@Burinson thats exactly what you cannot do. You cannot call a variable. You can only call functions.
Well, an example where you return the contents of a variable from a function
@Burinson
function foo() {
return 5;
}
foo(); // Function callfunction foo() {
var bar = "baz";
return bar;
}
Here i return the contents of the variable
bar from the function foo
This function can be used as follows:
var newVar = foo();
console.log(newVar);
This logs
baz
Interesting, let me try a sex
sec*
@alpox
function whatIsInAName(collection, source) {
var ArrWithSource = collection.filter((function(objects){
for (var i = 0; i < [Object.keys(source)][0].length; i++) {
// For checking each source property
var sourceKey = [Object.keys(source)];
// Key of the source arguments. Ex: a, b
var sourceProp = source[sourceKey[0][i]];
// Property of source args. Ex: source.a = 1
console.log(objects[sourceKey[0][i]] === sourceProp);
// Filter the array where the requested property is equal to the one inside the source argument
}
}));
return ArrWithSource;
}
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
Should I store
objects[sourceKey[0][i]] === sourceProp inside a variable
And make a function before the for loop?
@Burinson Oh... multiple things here. Let me explore
@Burinson 1. Thing:
[Object.keys(source)][0] is totally redundant. Its the same as just: Object.keys(source)
Yep, I'm stuck since yesterday with this one
Then,
var sourceKey = [Object.keys(source)]; that sure does not give you a key, it gives you an array with one element - another array which holds all keys of the source.
I believe what you were going for is:
Object.keys(source)[i] to get the key at index i
Whereas the actual property would be in
source[sourceKey]
Ofc. you get the right
sourceProp with your code too, but you make a long way around :D
function whatIsInAName(collection, source) {
var ArrWithSource = collection.filter((function(objects){
for (var i = 0; i < [Object.keys(source)].length; i++) {
// For checking each source property
var sourceKey = [Object.keys(source)[i]];
// Key of the source arguments. Ex: a, b
var sourceProp = source[sourceKey[0][i]];
// Property of source args. Ex: source.a = 1
console.log(source[sourceKey]);
// Filter the array where the requested property is equal to the one inside the source argument
}
}));
return ArrWithSource;
}
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
Like this?
@Burinson Not exactly :-) why do you make
[] around Object.keys(source)?
Hm...
I barely noticed that
Hehehe
If you do:
var foo = [1, 2, 3, 4];
var bar = [foo];What is the value of bar?
[[1,2,3,4]]?
yep
Oh, nice
So you just wrap an array into an array
I think I copied it from somewhere in my code and forgot to remove them
You did the same thing with
Object.keys(source) so you always needed to go through [0]
So if you remove the brackets, you don't need [0] anymore?
Actually in this case though, you can just return from inside of the for - because if you found the attribute, you can stop searching
But i don't remember the exact question of that challenge anymore
@Burinson Yes, exactly
It's like if I'm creating an array just to seach inside it again
LOl
If you access in my example the
3 how would you access it?
@Burinson Yea exactly thats what you did ;-)
I guess bar[0][2]?
:thumbsup:
You're really helpful
Let me see
so if you would instead do:
var bar = foo; // Without the []you could do:
bar[2]Directly
@alpox
function whatIsInAName(collection, source) {
var ArrWithSource = collection.filter((function(objects){
for (var i = 0; i < Object.keys(source).length; i++) {
// For checking each source property
var sourceKey = Object.keys(source)[i];
// Key of the source arguments. Ex: a, b
var sourceProp = source[sourceKey];
// Property of source args. Ex: source.a = 1
console.log(objects[sourceKey] === sourceProp);
// Filter the array where the requested property is equal to the one inside the source argument
}
}));
return ArrWithSource;
}
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
@Burinson Looks much cleaner :D
Yep :)
Now, what was the question of the challenge?
Make a function that looks through an array of objects (first argument) and returns an array of all objects that have matching property and value pairs (second argument). Each property and value pair of the source object has to be present in the object from the collection if it is to be included in the returned array.
It returns "true, false, true", and that's correct, it should only return the first and third array
Now I need a way of returning those arrays
@Burinson Okay then. Because of
Each property and value pair of the source object has to be present in the object you have to loop through all of the source properties before you can tell if they are all there or not.
Hm...
So you have to make a variable before the loop to "collect", or you return inside of the loop in a
false case and return true after the loop.
That are two possibilities
- one looks about like:
var everyIsTrue = true; for(...) { if(...) { everyIsTrue = false; } } return everyIsTrue;
second one looks about like:
for(...) {
if(...) {
return false;
}
}
return true;
Same outcome, second one performs better
I hope you see whats going on :D
...looks pretty much the same i wrote yesterday :P
one way
loop on all sources if (source prop !== collection prop) return false; //one prop dont match return true; //all matchesanther way is using .every method
@moigithub Yup :D pretty much xD
I was also almost going to tell about
.every but i newcomers have hard times with such things :D
@alpox
function whatIsInAName(collection, source) {
var ArrWithSource = collection.filter((function(objects){
for (var i = 0; i < Object.keys(source).length; i++) {
// For checking each source property
var sourceKey = Object.keys(source)[i];
// Key of the source arguments. Ex: a, b
var sourceProp = source[sourceKey];
// Property of source args. Ex: source.a = 1
if (objects[sourceKey] != sourceProp) {return false;}
// Filter the array where the requested property is equal to the one inside the source argument
} return true;
}));
return ArrWithSource;
}
whatIsInAName([{ "a": 1, "b": 2 },
{ "a": 1 },
{ "a": 1, "b": 2, "c": 2 }],
{ "a": 1, "b": 2 });
It worked!
@Burinson :thumbsup:
@moigithub Thanks, but I didn't understand what was going on yesterday
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@Burinson I hope you see whats going on with it now :D
I needed a more detailed explanation