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Corey Lewis
@cursiv3
asyncUtil is creating a closure, so the function passed to it will "initialize" the func, returning asyncUtilWrap with whatever fn was passed to it; but it'd have to invoked
did you place a console.log inside the node_modules file? If that's the case and you didn't see anything, it might be because you put the log into the unbuilt file rather than the built file; you'd need to find the built file usually in like lib which will be the transpiled code actually being used from the packag
Corey Lewis
@cursiv3
so looks like express.get initializes asyncHandler with the callback you give it, then when the route gets hit I'd expect that asyncUtilWrap to fire
Jake Giri
@jakegiri
do i need/should learn sql if i'm planning to learn/use graphql in the end?
Corey Lewis
@cursiv3
@JakeDVirus graphql isnt a database, it's an alternative to REST database queries, you can use graphql with sql or NoSQL databases
divyajeetsingh
@divyajeetsingh
Hi , everyone
Zerka1982
@Zerka1982

I got a question please, I have built a react application with MongoDB. In the structure of my project I have 2 folders one is for the Front-end and the other for Backend. In order for me to see the actual result, I run nodemon server.js within the backend folder, and then I run on the project level npm start. My application is working perfectly.

My question to you guys, Would I face any issue if I deploy my project to Netlify ?

Zerka1982
@Zerka1982
Solved!
dmnkvd
@dmnkvd
Hi everyone! I have just finished building my VueJS (frontend) and Strapi (backend) project... In two main folders, "frontend", and "backend", each with their own NodeJS / yarn configurations. I am completely stuck trying to deploy it on cPanel with Namecheap... Currently, the Vue part runs on localhost:8080, and Strapi on localhost:1337; I have no idea what these URLs become once on the server?
buiphuking
@buiphuking_twitter
image.png

hi guys,
i code website using laravel,
i set up mysql is my first database, mongodb is my second database
my .env:
DB_CONNECTION=mysql
DB_HOST=127.0.0.1
DB_PORT=3306
DB_DATABASE=source
DB_USERNAME=root
DB_PASSWORD=

DB_CONNECTION_SECOND=mongodb
DB_HOST_SECOND=127.0.0.1
DB_PORT_SECOND=27017
DB_DATABASE_SECOND=demo
DB_USERNAME_SECOND=null
DB_PASSWORD_SECOND=null
and i query builder, i get this error:
i have fixed everything i can, please help me

Ashref
@Asher2016
HI , i want to duplicate entitis but in same time i want to know the original entity of duplicated entities , does Someone have any idea ? thx :)
Drewsive01010101
@Drewsive01010101
Has anybody tried to download the git repository Xuggler at https://github.com/artclarke/xuggle-xuggler? I installed MinGW to be able to configure and compile xuggler. When I followed the INSTALL Readme file, I was able to do "./configure", but am still unable to execute the "make" command on the makeFile without getting an error. Also, I got the "make" command by Chocolatey if that is of any good information. But my error is of the following:
Drewsive01010101
@Drewsive01010101
Makefile:813: /c/Users/NICK/Desktop/XugglerFolder/xuggle-xuggler/mk/Makefile.global: No such file or directory
make: * No rule to make target '/c/Users/NICK/Desktop/XugglerFolder/xuggle-xuggler/mk/Makefile.global'. Stop.
FYI I created the "XugglerFolder" in which the "xuggle-xuggler" repos folder is in. So what exactly does the error mean and how do I fix it? Thanks
Riadh
@KWFE
hey great community
MohameddAli
@MohameddAli
hello
any one can help ??
when i go for change password he tell me Failed to Change Password !!
  // Check whether the Submit Button is Clicked or not
  if(isset($_POST['submit']))
  {
    //echo "Cliked";
    //1. Get the Data From Form
    $id=$_POST['id'];
    $current_password = md5($_POST['current_password']);
    $new_password =md5($_POST['new_password']);
    $confirm_password  = md5($_POST['confirm_password']);
    //2.Check whether the user with current id and password exist or not
    $sql = "SELECT * FROM tbl_admin WHERE id=$id AND password='$current_password'";
    // Execute the Query
    $res = mysqli_query($conn,$sql);
    if($res==true)
    {
      //Check whether data is avilable or not
      $count = mysqli_num_rows($res);
      if($count==1)
      {
        //User Exist and Password Can be Changed
        //echo "User Found";
        //Check whether the new password and confirm match or not
        if($new_password==$confirm_password)
        {
          //Update the Password
          //echo "Password Match";
          $sql2 = "UPDATE tbl_admin SET passowrd = '$new_password' WHERE id=$id";
          //Execute the Query
          $res2 = mysqli_query($conn, $sql2);
          //Check whether the query executed or not
          if($res2==true)
          {
            //Display Succes Message
            //Redirect to MNG Admin Page with Success Message
            $_SESSION['change-pwd'] = "<div class='success'>Password Changed Successfully.</div>";
            //Redirect the User
            header('location:'.SITEURL.'admin/mng-admin.php');
          }else{
            //Display Erorr Message
            //Redirect to MNG Admin Page with Erorr Message
            $_SESSION['change-pwd'] = "<div class='error'>Failed to Change Password.</div>";
            //Redirect the User
            header('location:'.SITEURL.'admin/mng-admin.php');
            }
         }
         else
         {
          //Redirect to MNG Admin Page with Erorr Message
          $_SESSION['pwd-not-match'] = "<div class='error'>Password Did Not Match.</div>";
          //Redirect the User
          header('location:'.SITEURL.'admin/mng-admin.php');
        }
      }else{
        //User Does not Exist Set Message and Redirect
        $_SESSION['user-not-found'] = "<div class='error'>User Not Found.</div>";
        //Redirect the User
        header('location:'.SITEURL.'admin/mng-admin.php');
      }

    }
    //3. Check whether the New Password and Confirm Password Match or Not

    //4. Change Password if all above is true

  }


?>
Rok Z
@Rock-son
@MohameddAli error in UPDATE tbl_admin SET passowrd
-> password
rajirashed2010
@rajirashed2010
hello everyone
i'm new here pls i have a problem about my coding
can someone help me out pls pls
Uncaught SyntaxError: Identifier 'tittle' has already been declared
javascript
Vanessa Correia
@wordlesspirate
not entirely sure without a snippet of code to look at, @rajirashed2010 , but if I had to guess, there must be a variable in our code that you are reusing. something along these lines:
let name = "a"

let name = "b"
let name = "b"
    ^

SyntaxError: Identifier 'name' has already been declared
rajirashed2010
@rajirashed2010
thanks @wordlesspirate not that ma.
@wordlesspirate pls how can i sent my code to you so u can play around it together please
Vanessa Correia
@wordlesspirate
if it is not too long of a piece of code, i would say you can paste here. just make sure to use quotations code inside so your code formats into a snippet, makes it a little easier to read.
quotations i mean these: ```. at the start and end of your code block.
Ashref
@Asher2016
guys anyone has experience with apache tomcat !
John Melody Me
@johnmelodyme

Hey guys I use cheerio to scrape this table but it return nothing. Did I somehow did wrong ?

<table class="table trackTable">
                    <thead>
                            <tr>
                                <th colspan="4">Consignment No: MY37011088606</th>
                            </tr>
                        <tr>
                            <th>Consignment No</th>
                            <th>Date &amp; Time</th>
                            <th>Status</th>
                            <th>Location</th>
                        </tr>
                    </thead>
                    <tbody>
                                <tr>
                                    <td>MY37011088606</td>
                                    <td>03/07/2020 14:58:43</td>

                                        <td><b>Delivered</b></td>

                                    <td>Butterworth</td>
                                </tr>
                          .....
                </table>

and my code was

$ = cheerio.load(response['data']);

            $.html();

            $('.table#trackTable').each((index, element) => {
                if (index === 0) return (true);

                console.log(element)
            });

Any idea ? is the naming of the selctor wrong?

in the browser i did

$(".table > tbody:nth-child(2)").each(function(i,item) { console.log(item.innerText) });

and it return something , but cheerio doesn't

2 replies
Zerka1982
@Zerka1982
Hi guys !
Anybody here to support me on one task
If user inputs an email for example@gmail.com , I would like to force the user not to add any extra letters after the .com
is there a way to do this please?
1 reply
schawnnara jiri
@schawnnaraj_gitlab
hi
need help
michaelnicol
@michaelnicol
What websites do you guys develop code in? I use repl.it unless I am working with webpages, then I use codepen. Repl.it always seems to have server issues and I seem to loose work often due to frequent down times
Tunde Oretade
@tundeiness
hi guys. I need help. I have this Api that I am trying to consume: https://torre.bio/api/bios/ and I usually get this error Access to XMLHttpRequest at 'https://torre.bio/api/bios/john' from origin 'http://localhost:3000' has been blocked by CORS policy: No 'Access-Control-Allow-Origin' header is present on the requested resource. on close investigation at the network tab I found out that any time I hit the above url I am being redirected to https://bio.torre.co/api/bios. Which seems to show that I may need a proxy server backend to handle access to this url. I have searched and nothing comes close to a solution. A stackoverflow respose "https://stackoverflow.com/questions/70114502/access-to-xmlhttprequest-at-from-origin-http-localhost4200-has-been-bloc " is a close answer but it was implemented with .Net. My app codebase is in react and I need help on setting up a proxy server to consume the API above. Thanks.
Nicolas Ramirez
@kamatheuska
Hey everyone! I would like to get deep knowledge of nodejs and backend concepts. I have been working as a software dev for a 5 years already, but mostly focusing on frontend. Can you give me some hints on what I need to know to become a really good backend/nodejs developer?
Dan Stockham
@DanStockham
@kamatheuska the best thing I can suggest is getting an understanding how the http web server frameworks for nodejs work and getting comfortable building things with them
@kamatheuska NodeSchool is a good place to start but FCC has a pretty good course that immerses you enough that you can start building things efficiently
@tundeiness It is very possible that the api you're trying to reach doesn't allow for http or unsecured connections (hence, your localhost instance is unsecure)
Dan Stockham
@DanStockham
@tundeiness Either I would find way to put your local instances on port 443 which means self-signing a certificate or setup a secure backend server that acts as a façade to your api you're trying to consume.
Chris Cullen
@123xylem
Hi Guys.
Wondering how to take variable set by Ajax in functions.php and use it as an argument in my page.php onclick function
Tunde Oretade
@tundeiness

@tundeiness Either I would find way to put your local instances on port 443 which means self-signing a certificate or setup a secure backend server that acts as a façade to your api you're trying to consume.

true. Solved it.

Matthew
@ChaplainsBud
Hi all, has anyone handled an exception with a template language? I'm using Freemarker, and my goal is to handle a null exception if there is no image to be rendered. However, I don't know what I'd return if it is null -- should I create a statement, "No image provided?"
Nevermind, I didn't realize I should do nothing in response.
Ozenzamy-Spark
@Ozenzamy-Spark

Hi all , please i have a question about the Iterative implementation of Binary Search

This is the function i create in c:

int BinarySearch(int arr[], int l, int r, int x) { while(l <= r) { int mid = l + (r - l) / 2; printf("%d\n", mid); if(arr[mid] == x) return mid; if(arr[mid] > x) r = mid - 1; else l = mid + 1; } return -1; }

This is my main function :

int main() { int arr[] = {1,2,3,5,16,15,20}; int n = sizeof(arr) / sizeof(arr[0]); int x = 16; int result = BinarySearch(arr, 0, n-1, x); (result == -1) // WE CALL THIS ternary operator. ? printf("Element is not present in array") : printf("Element is present at index %d", result); return 0; }

The question is: when i search 16 the function return -1.
If you see the number 16 is on the list any help please ??

Stephen James
@sjames1958gm
Your algorithm depends on a sorted array and 15 is out of order
Ozenzamy-Spark
@Ozenzamy-Spark
Thanks for your replay