Where communities thrive


  • Join over 1.5M+ people
  • Join over 100K+ communities
  • Free without limits
  • Create your own community
People
Activity
  • Aug 17 09:32
    User @bjorno43 unbanned @linkin-park
  • Jun 20 21:19
    @bjorno43 banned @shenerd140
  • Apr 25 17:13
    @mstellaluna banned @cmal
  • Jan 08 22:05
    @mstellaluna banned @dertiuss323
  • Nov 07 2018 04:42
    User @texas2010 unbanned @ows-ali
  • Nov 02 2018 16:25
    @texas2010 banned @ows-ali
  • Oct 12 2018 05:50
    @bjorno43 banned @NACH74
  • Oct 05 2018 23:02
    @mstellaluna banned @JomoPipi
  • Sep 16 2018 12:21
    @bjorno43 banned @yash-kedia
  • Sep 16 2018 12:16
    @bjorno43 banned @vnikifirov
  • Sep 05 2018 08:12
    User @bjorno43 unbanned @androuino
  • Sep 05 2018 07:38
    @bjorno43 banned @androuino
  • Aug 23 2018 16:57
    User @bjorno43 unbanned @rahuldkjain
  • Aug 23 2018 16:23
    @bjorno43 banned @rahuldkjain
  • Jul 29 2018 14:13
    User @bjorno43 unbanned @jkyereh
  • Jul 29 2018 01:00
    @bjorno43 banned @jkyereh
  • Jul 10 2018 22:09
    @bjorno43 banned @manafn
  • Jul 06 2018 15:20
    @texas2010 banned @imlegend19
  • Jul 03 2018 12:28
    @bjorno43 banned @vbvmatta
  • Jun 29 2018 13:54
    @bjorno43 banned @OGTechnoBoy
trying to get this to iterate over the object
Daniel
@DanielMW34

@khaduch
"the thing is that you have some variables in that function and they might not be in scope if you define the click handlers outside?" ---- do you mean this might be the case if I change the design to have each <div> clicker call an individual function?

"The main thing is that you do not want to create multiple click handlers." ----- I'm not 100% clear on what multiple click handlers are...?

"You aren't disabling any of them at this point, are you?" ---- correct, I am not disabling anything at this point. (even some of the things I thought I was disabling are not disabling). In order to disable something, the example below should work AND, the line beneath would "re-enable" the clicking correct?

$("#playX").attr("disabled", "disabled");
$("#playX").removeAttr("disabled");
Ken Haduch
@khaduch
@DanielMW34 - I'll get back to you soon, okay?
Daniel
@DanielMW34
@khaduch yes, I am going to head out for 20 mins to print out some of this code on paper so I can look at it in it's entirety.
@khaduch just message me whenever you are ready, and thank you
CamperBot
@camperbot
danielmw34 sends brownie points to @khaduch :sparkles: :thumbsup: :sparkles:
:warning: danielmw34 already gave khaduch points
Risa Fletcher
@risafletcher
@laceyIrvin I'm on mobile; can you S/s me the desktop? The appeal seems to be mostly the typeface he is using
Rafael Mateo
@rafaelmateo
hello
Howdo I put a navigation bar in the front end project?
Ghost
@ghost~56c733f2e610378809c24d2c
Rafael Mateo
@rafaelmateo
The thing about that is that I dont wanna use links, I want people to click on it and go do THAT section down the page, because it is just 1 page
@travisboss
@travisboss but thanks!
CamperBot
@camperbot
rafaelmateo sends brownie points to @travisboss :sparkles: :thumbsup: :sparkles:
:cookie: 286 | @travisboss |http://www.freecodecamp.com/travisboss
Ghost
@ghost~56c733f2e610378809c24d2c
@rafaelmateo you would be looking at #tags this is done with bootstrap
Rafael Mateo
@rafaelmateo
okks
Ill google it!
thanks for the info!!
Rafael Mateo
@rafaelmateo
hahahha I love this! thnks @travisboss
Ghost
@ghost~56c733f2e610378809c24d2c
its a big complicated to explain over gitter so it is usually easier to give a link to. so you can see you are using div classes and calling those out within nav. I have it on an old site and is pretty easy.
Yaroslav Newman
@YaroNew
Guys
Help with assignment pls.
CamperBot
@camperbot
no wiki entry for: with assignment pls
Yaroslav Newman
@YaroNew
function multiplyAll(arr) {
  var product = 1;
  // Only change code below this line

for ( var i=1; i> arr.lenght; i+5) {
  for (var j=0; j< arr[i].lenght; j++);
}

  // Only change code above this line
  return product;
}

// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
Modify function multiplyAll so that it multiplies the product variable by each number in the sub-arrays of arr
Ken Haduch
@khaduch
@YaroNew - you have misspelled ".length" in two places... And you are not doing any multiplications - you should be multiplying the individual array elements (in your inner loop) times the product variable to get a value to return. Because the provided code does return product;
Yaroslav Newman
@YaroNew
@khaduch can you give an example
Ken Haduch
@khaduch
@YaroNew - a couple questions - do you have an explanation why your outer for loop has a variable that is initialized to 1, and then adds 5 as the iteration value? (There is a problem there, in my opinion.) Secondly - how would you access the elements of the two-dimensional array - there should be a lesson that describes and teaches that. "Access MultiDimensional Arrays With Indexes " is the lesson. The hint is that in your inner loop, you would need a statement that uses the syntax arr[ something1 ][ something2 ]; where the two different somethings are values that you generate to index into the multi-dimensional array.
Walid Ashri
@walidashri
@YaroNew
var arr=[[1,2],[3,4],[5,6,7]];
arr[0][1]= 2;
Yaroslav Newman
@YaroNew
@khaduch Yeap. Thanks for reminding.
CamperBot
@camperbot
yaronew sends brownie points to @khaduch :sparkles: :thumbsup: :sparkles:
:star2: 1843 | @khaduch |http://www.freecodecamp.com/khaduch
Yaroslav Newman
@YaroNew
@khaduch so I need to turn all code in else\if statements
?
@khaduch

function multiplyAll(arr) {
  var product = 1;
  // Only change code below this line


for ( var i=0; i < arr.length; i++) {
  for (var j=0; j< arr[i].length; j++);
}

  // Only change code above this line
  return product;
}

// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
here is how my code looks like now
Walid Ashri
@walidashri
@YaroNew inside 2nd for loop
product *=arr[i][j]
Yaroslav Newman
@YaroNew
@walidashri
function multiplyAll(arr) {
  var product = 1;
  // Only change code below this line


for ( var i=0; i < arr.length; i++) {
  for (var j=0; j< arr[i].length; j++);
  product *=arr[i][j];
}

  // Only change code above this line
  return product;
}

// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
Walid Ashri
@walidashri
@YaroNew :+1:
Yaroslav Newman
@YaroNew
Doen't wokr
work
multiplyAll([[1],[2],[3]]); should return 6
multiplyAll([[1,2],[3,4],[5,6,7]]) should return 5040
multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]]);) should return 54
it returns null
Yaroslav Newman
@YaroNew
@walidashri any ideas?
Walid Ashri
@walidashri
@YaroNew
for ( var i=0; i < arr.length; i++) {
  for (var j=0; j< arr[i].length; j++){
  product *=arr[i][j];
}
}
u are missing some {}