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John Nunns
@johnnunns
but with the knowledge gained from the recent codewars problem I just did, I was hoping for some direction
function getCount(str) {
var sum=0
var i = str.split('');
for(var x=0; x<i.length; x++){
if (i[x] === 'a' || i[x] === 'e' || i[x] === 'i' || i[x] === 'o' || i[x] === 'u'){
sum ++;
};

};

return sum;

}
so I just wrote this function in order to count the vowels
it works well, it could be condensed I saw from the other answers, but it works
Now, back to that prep course challenge, I'm hoping to apply this knowledge to it
JD Tadlock
@jdtdesigns
@zarruk All the very high margins are screwing with your layout. I cleaned up some of the html and changed some css http://codepen.io/jdtadlock/pen/wgeyeB?editors=0100
John Nunns
@johnnunns
Instructions from your teacher:
Write a function called "countAllCharacters".

Given a string, "countAllCharacters" returns an object where each key is a character in the given string. The value of each key should be how many times each character appeared in the given string.

Notes:
* If given an empty string, countAllCharacters should return an empty object.

var output = countAllCharacters('banana');
console.log(output); // --> {b: 1, a: 3, n: 2}

Starter Code :
function countAllCharacters(str) {
  // your code here
}
JD Tadlock
@jdtdesigns
lol
still doesn't work i see
do you have a link to the challenge?
@johnnunns
John Nunns
@johnnunns
so the code I just posted above was the answer to a codewars problem
different but similar
that one works to count vowels
but after doing that I thought why not give a go at the prep course one, which I have not written code for as yet
Coding Machine
@EphremL
Hello, I am recruiting people to work a project with the skills of HTML and CSS also Javascript. If you think your the right canidate, join : https://gitter.im/Project-Awesome-1/Lobby?utm_source=share-link&utm_medium=link&utm_campaign=share-link
JD Tadlock
@jdtdesigns
@johnnunns My answer is still failing or are you wanting to solve it yourself? @johnnunns
John Nunns
@johnnunns
well when i looked at your answer, I realized I was pretty far from solving it myself
I may be a little closer now
I believed you used regex correct?
JD Tadlock
@jdtdesigns
@johnnunns Yep
and .reduce()
and .map() i believe
John Nunns
@johnnunns
you know what, let me rewatch those higher level function vids you showed me. and then also watch one on regex
JD Tadlock
@jdtdesigns
for regex, you'll just google 'match blah blah' most of the time
John Nunns
@johnnunns
is match and regex the same method?
JD Tadlock
@jdtdesigns
i google regex all the time cause i'm not going to spend time figuring out the expression myself if i know it's been done 1000 times
.match() uses regex to 'match' a certain pattern in a string
Johnny
@JohnnyBizzel
@zarruk I had a go at your code too: http://codepen.io/JohnnyBizzel/pen/qRjxWp
alexbuster
@alexbuster
How can I import a picture from facebook can anybody help me please.
John Nunns
@johnnunns
@jdtdesigns alright jd
gonna need some clarification :)
so I'm trying to apply map to my function
function countAllCharacters(str){
    var i = str.split('')
    var x = i.map(function(str){

    })
    return i
}

countAllCharacters('banana')
I'm really not sure if this is even close
alex can you save your facebook picture in facebook and then use that to make it your profile picture here @alexbuster
JD Tadlock
@jdtdesigns
@johnnunns the argument in the .map() callback refers to the current value in the array as the map iterates through it
John Nunns
@johnnunns
.map(countAllCharacters(str)?
is that what I should set it to
I think I'm confused on how to put map inside of a function
J.S.
@jspeda
you wouldn't use map in this situation
map is for when you have an array, and you want to perform some type of transformation on that array
good video^
John Nunns
@johnnunns
just watched it haha @jspeda
which higher order function would you use to solve the problem then?
J.S.
@jspeda
you can just call .length on the string
and call it a day
or wait
John Nunns
@johnnunns
nah it's way more complicated unfortunately :)