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Sweet Coding :)
@SweetCodingInc
@eabg it should be $('.btn').on('click'....
you're missing . before btn
Ehidin
@eabg
oh man really? let me check it out
Sweet Coding :)
@SweetCodingInc
and also, in your html, there is no element that has class="btn"
so it's not going to work either way
Do you want to attach event handlers to all your buttons?
From the html you've shared, you need to do
$('button').on('click'....
Ehidin
@eabg
I orginally had button with no luck
so I tried that out and nothing
Sweet Coding :)
@SweetCodingInc
what do you want to happen when you click the button?
The event handler doesn't look right to me
Ehidin
@eabg
so im just trying to add some css changes to boxes..later do animate
Sweet Coding :)
@SweetCodingInc
With your code, let's say you click on the button 1. Then the clickButtonId will be btn1
and your selector will be#box1btn1
and there is no element with id="box1btn1"
Ehidin
@eabg
let me show you this. this was an earlier test and it was working before:
Screen Shot 2018-04-03 at 12.38.45 AM.png
I wanted to start over cause an element got lost and i couldnt get it working again
Sweet Coding :)
@SweetCodingInc
@eabg you're better off using data attribute to target specific box
I'll show you an example
Ann Kaniga
@annkaniga
@eabg did u try any debug?
Ehidin
@eabg
in the console? or....
Ann Kaniga
@annkaniga
yes, is there any red line in console?
i mean browser console
Sweet Coding :)
@SweetCodingInc
@eabg Check this out
Ehidin
@eabg
yeah.. so its just having a problem with the ending script tag
ill check it out and let you know
Ehidin
@eabg
okay yeah I will start over using this method. it seems a lot easier to manage and read
Ehidin
@eabg
@SweetCodingInc :+1:
Sweet Coding :)
@SweetCodingInc
@eabg :+1:
John Hawke
@lolativiwe_twitter
function diffArray(arr1, arr2) {
    var newArr = arr1.concat(arr2);
    newArr.filter(function(index) {
        if (!arr1.includes(index) || !arr2.includes(index)) {
            return newArr;
        }
    });
    console.log(newArr);
}

diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]);
can someone tell me whats wrong with this?
it always returns the concatenated array of the two
Aditya
@ezioda004
@lolativiwe_twitter .filter() returns a new array and doesnt mutate the original one so you're returning the concatenated array from the 2nd line
John Hawke
@lolativiwe_twitter

oh lol...

newArr = newArr.filter(....

this worked

thanks @ezioda004
CamperBot
@camperbot
lolativiwe_twitter sends brownie points to @ezioda004 :sparkles: :thumbsup: :sparkles:
:cookie: 522 | @ezioda004 |http://www.freecodecamp.org/ezioda004
Stephen James
@sjames1958gm
@lolativiwe_twitter Since the function should return the new array
return newArr.filter(... would probably be the "best" solution as it makes it clear that the filter is the function result.
steve84
@raynor84
I'm trying to solve dna-pairing but i don't know how it works... why is GCG dna-pairing GC, CG, GC again
Stephen James
@sjames1958gm
@raynor84 Each character in the string is paired with its designated value G with C, C with G and G with C again.
@raynor84 The pairing values are given in the instructions
steve84
@raynor84
ok i get it thanks
@sjames1958gm thx
Aditya Dehal
@aditya2000
hello
Stephen James
@sjames1958gm
@sjames1958gm :+1:
quintik
@quintik
how do I get the name of the location from the coordinates?
for the weather app
Stephen James
@sjames1958gm
@Quantomistro3178 There is a name value in the JSON from the FCC URL