Get help on our basic JavaScript and Algorithms Challenges. If you are posting code that is large use Gist - https://gist.github.com/ paste the link here.
@Jarevalo92 -- where are you using val in the above pasted code?
post ur code.. how u doing... usng val
Hello @*, anyone did the "Sum All Numbers in a Range" challenge using reduce?
@obouchari post ur code...
@obouchari - I don't remember!!!
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
var lookup = {
"alpha": "Adams",
"bravo":"Boston",
"charlie":"Chicago",
"delta": "Denver",
"echo": "Easy",
"foxtrot":"Frank",
};
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
so where are you using val in your code @Jarevalo92 ?
@bitgrower Can you have a look :)
LOL ... did you mean me, @obouchari ?
yeh
@Jarevalo92 but.. u not using val in there...
hhh LOL
@Jarevalo92 before return result... u should have something like
result = .... something with val and lookup variables
@bitgrower I guess thats my question. How do I use it
@bitgrower Its the first one under Intermediate Algo Scripting
ive tried result = lookup[''];
u r close...
add val variable now..
reduce is a wonderful thing ... but I used a sort of series calculation instead of reduce (I can thank an advanced algebra class for that ... LOL ... series are cool things ... )
@obouchari -- did you look at the examples on the MDN page for array.reduce ?
@obouchari post ur code!!!!
@moigithub -- I think he's just trying to understand how to use array.reduce ... :)
I know how to use it, but I think you will need to generate an array out of the range to use reduce on it
LOL @obouchari -- yeah, you would ... that's why I didn't do that ...
@bitgrower But I solved it without reduce just simple loop
This message was deleted
function sumAll(arr) {
var max = Math.max.apply(Math, arr);
var min = Math.min.apply(Math, arr);
var result = 0;
for (; min <= max; min++) {
result += min;
}
return result;
}
sumAll([1, 4]);
This message was deleted
yeah, that would do it ...
@bitgrower I just want to know if missed something about arrays, Although Underscore have something like _.range()
function lookUp(firstName, prop){
// Only change code below this line
for (var i=0; i < contacts.lenght ; i++){
if(contacts[i].firstName == firstName){
if (contacts[i].hasOwnProperty(prop)){
return contacts[i][prop];
}else{
return "No such property";
}
}
}
// Only change code above this line
}
please can someone help me
@moigithub @bitgrower Is ES6 supported in the FCC ?
in the challenges ?
think saw few ppl posting code on es6
yep -- I used an ES6 method on confirm the ending ...
Yeah in their code area
@intertarik please format your code for helper's tired eyes ... like @campberbot indicates (follow the instructions closely)
explain format
:point_right: code formatting [wiki]
Inline code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
Code Block
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
who can point into right direction?
Write a function queue which takes an array (arr) and a number (item) as arguments. Add the number to the end of the array, then remove the first element of array. The queue function should then return the element that was removed.
@darelisss for sure you read about necessary methods:
push() and shift(), that's all you need to complete this challenge :-)
@dareliss -- go check out the different Array functions in the Mozilla Developer Network pages
This message was deleted
@intertarik -- follow the instructions CLOSELY ...
Heading to algorithms now. It's scary!
nah, it's a lot of fun !!!
This message was deleted
Hope I get some fun out of it! Probably will feel awesome after finishing it, lol
@Takumar @bitgrower thanks guys
darelisss sends brownie points to @takumar and @bitgrower :sparkles: :thumbsup: :sparkles:
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yw @darelisss
@darelisss you are welcome :-)
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:bulb: to format code use backticks! ``` more info
This message was deleted
:bulb: to format code use backticks! ``` more info
@intertarik use ` instead of '
@intertarik -- backtick -- the key to the left of your 1 key ...
function lookUp(firstName, prop){
// Only change code below this line
for (var i=0; i < contacts.lenght ; i++){
if(contacts[i].firstName == firstName){
if (contacts[i].hasOwnProperty(prop)){
return contacts[i][prop];
}else{
return "No such property";
}
}
}
// Only change code above this line
}
YAY!!!!
yéééééh thx
hhhh
so ... how well is it working ? what part isn't working ?
you have a problem in your loop -- a couple of them, actualy
the all parts
@intertarik u missing a "no such contact" messsage
@intertarik you have to tell also that there is
No such contact in your code :-)
okay ... well, you have a spelling error in your for loop...
ohh yes ... but where put it ??
@intertarik with each iteration of your loop you check only one contact.
So when can you say that you haven't found your contact?
So when can you say that you haven't found your contact?
@intertarik -- if I have 20 marbles in a bag, how many do I have to look at to know there are no black marbles in the bag (not a trick question)
whene i= = (contacts.lenght-1) ?? @Takumar
yes.. no .. maybe... 3%
fast way to know is testing :P
trial n error
@intertarik -- take your mind away from js for a second, and your efforts on this solution ... and answer my question ?
@intertarik not really, please listen now to @bitgrower , that's a good explanation :-)
You are checking first contact, second...
You are taking first marble...
You are checking first contact, second...
You are taking first marble...
thanks @Takumar
bitgrower sends brownie points to @takumar :sparkles: :thumbsup: :sparkles:
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Hello All! Is it possible for anyone to help me on Seek & Destroy challenge?
ok @bitgrower
I am having confusion with the arguments object
sure, @SSabu -- please post your code ...
ok
thanks.
@SSabu -- that's a common mis-understanding with that challenge ... you are not alone ...
'''
function destroyer(arr) {
var mustRemove = [];
for (var i = 1; i < arguments.length; i++) {
arr = arr.filter(function(val){ return val != arguments[i];
});
(function(){return arr;})();
}
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);'''
:bulb: to format code use backticks! ``` more info
@bitgrower i have to look how many marbles i took ..
lol- SORRY! I'm a newbie, still working on posting code so it looks formatted correctly
close!!! use backtick ... --> ```js
and that must be on a line by itself ...
and that must be on a line by itself ...
thanks @camperbot
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@intertarik ... make it 5 marbles ... how many marbles do I have to look at to determine there are NO black marbles in the bag ?
@intertarik do you need to check first marble, 10 or 18?
When you check 18 marble and all are white, can you say that you don't have black marbles in your bag?
When you check 18 marble and all are white, can you say that you don't have black marbles in your bag?
function destroyer(arr) {
var mustRemove = [];
for (var i = 1; i < arguments.length; i++) {
arr = arr.filter(function(val){ return val != arguments[i];
});
(function(){return arr;})();
}
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
YAY!!!! @SSabu
thanks!
I get a message saying, "Don't define a function in a for loop"
But how else Can you make it cycle through the arguments?
@bitgrower 5 marbles
right ... so, don't do that ...
@intertarik -- YES!!!!
so how many elements in your array do you have to look at ?
4 itels
one at a time
items
@bitgrower any other suggestions?
well ... I don't remember the # of elements in the array ... but, assuming it's 4 ... yah, you have to look thru ALL of them ...
@SSabu Use Array methods
hang on ... let me look @SSabu
function factorialize(num) {
for(var i = 1 ; i <= num; i++) {
num *= i;
}
return num;
}
factorialize(5);
he is using filter @obouchari
k, thanks @bitgrower
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Or this isn't how you do it at all? :p
I missed that lol
@frandarre -- it has to do with your loop definition ...
no worries @obouchari
@bitgrower mk, I'll give it more thougth. Thanks!
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I think ... anyway ... LOL ... hang on ...need to look at @SSabu 's code
@frandarre -- it DOES have to do with your loop definition, in a way ... look at how you are using your num variable ...
@frandarre You check the num but you change it a the same time so the loop will keep going forever !
Oh, let me correct that. Thanks @obouchari @bitgrower
frandarre sends brownie points to @obouchari and @bitgrower :sparkles: :thumbsup: :sparkles:
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arr = arr.filter(function(val){ return val != arguments[i];
@SSabu -- I have a hard time figuring out exactly what js would do with that statement ... you might want to review Array.filter() in Mozilla Developer Network ... they have handy examples on the pages, too ...
yw @frandarre ... :)
i did this ans still don't work
````js
So, when I use that statement in replit and put in a value instead of "arguments [i]" it removes that value from the array
function lookUp(firstName, prop){
// Only change code below this line
var j=1;
for (var i=0; i < contacts.length ; i++){
if(contacts[i].firstName === firstName){
if (contacts[i].hasOwnProperty(prop)){
return contacts[i][prop];
}else{
return "No such property";
}
}else{
j++;
}
}
if (j== contacts.lenght){
return "No such contact";
}
// Only change code above this line
}
okay ... did you read the Arguments Object page, @SSabu ?
yes
that's why it says arguments[i] instead of just a straight value in the filter method
@intertarik the last if no needed.. neither j variable
what do you think the length of the arguments Object is ... and what do you think the values are ?
the length of the arguments object depends on how many arguments you input into the function
along with length being misspelled again ...
okay, in the first test case ...
@SSabu -- what are they in the first test case (the one I think you included above)
2 and 3
those are the only arguments in the arguments object ?
well there's the array too, but is that part of the arguments object?
what is arguments[0]?
argument1?
argument1?
@SSabu Are you using
(function(){return arr;})(); for debuging ?
@SSabu -- yes, it is ...
ok, will that's why the loop starts at 1
well
not sure what you are asking @obouchari
what may help is to understand that there are arguments, and some of them may actually get named in the formal function definition ... which makes it easy for you to use them ...
function factorialize(num) {
var n = num;
for(var i = 1; i < n; i++) {
num *= i;
}
if(num !== 0){
return num;
} else {
return 1;
}
}
factorialize(5);
in this case ... arguments[0] is the same thing as arr
yes
@bitgrower that makes sense
@SSabu What is the purpose of putting this
(function(){return arr;})(); inside the loop?
that's why I started the loop at 1
@frandarre -- well, considering someone could pass you a 0, it seems more than fair to check for it ... :) ... both 0 & 1 make for easy returns ... (although 0! I think is undefined ?)
@obouchari so that it updates the values in the array
@bitgrower so it's ok? Nice, then. Thanks for the help!
or maybe I'm confusing it with some of the other numeric stuff we've used in the challenges ...
frandarre sends brownie points to @bitgrower :sparkles: :thumbsup: :sparkles:
:warning: frandarre already gave bitgrower points
should I take that out of the loop? it seemed like that line was important to actually run the method
and have the array be updated after each filter
@SSabu Thats an IIFE so it will execute and take out of the function
@frandarre -- there's a concept known as defensive coding ... where you assume someone passing you data isn't passing you values that you expect ... in which case, you reject them outright, instead of having to find some weird bugs in your code ...
what's an IIFE?
no worries, I can google it.
@SSabu Immediately Invoked Function Expression
ok, thanks @obouchari
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@bitgrower then it's not cheeky if we want to prevent people from exploiting our code
:star: 335 | @obouchari | http://www.freecodecamp.com/obouchari
@SSabu Try to comment that and run your test again
ok, I did that. the test returned nothing
I didn't understand jQuery at all until I learned about IIFE's
so now the code looks like this
I could copy and paste code -- but didn't know how to debug it or do anything overly useful ...
function destroyer(arr) {
var mustRemove = [];
for (var i = 1; i < arguments.length; i++) {
arr = arr.filter(function(val){ return val != arguments[i];
});
}
(function(){return arr;})();
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
@frandarre -- defensive programming is good programming practice, for sure ...
where are you returning anything @SSabu ... ya gotta have a return statement ... the return in your last line does not return from destroyer, but from the anonymous function call ...
@SSabu u CANT use arguments object like that...
i hate arguments object...
like what, @moigithub ?
@SSabu cuz every function have its own arguments object copy
ahhh ... excellent point, @moigithub
@moigithub True!!!
if u have 2 nested function.. arguments will be different for both of em
I don't understand...
arr.filter calls a function, @SSabu -- so it creates a new arguments object ... but which parts are you not understanding ... ? what @moigithub said, or what I said ?
@SSabu anonymous function inside filter has its own arguments object...
@moigithub's point
@obouchari so could I take out the for loop?
okay...
let's not use IIFE's as an example ... let's just say I have a function, and within that function f(a), I call function b
@SSabu
arr = arr.filter(function(val){ return val != arguments[i]; // arguments[i] is not what you thinking
ok
when I call function a -- an arguments object is created ...
when I call function b, yet another arguments object is created ... each one's is accessed by the special variable arguments
ok
@SSabu arguments[i] at the time you using it belongs to
function(val) {};
so ... when you use arguments in an function, it refers ONLY to the the arguments passed to the function currently executing ...
ok
so how would you make the arguments function refer to the arguments passed into the original function?
sorry, arguments object...
set the arguments object to a variable ... and refer to that variable ... OR, more ideal, use something like splice
make a copy on an array first
ok.
so you make a copy ...
thanks
yes, I"ve seen splice used a lot in examples I've found online
er slice ... easier to copy ... but splice can be used sweetly here as well ...
splice does what exactly?
splice does a LOT ... but to copy an array, use slice ...
make a copy of the array being passed into the original function?
splice might be a bit of overwhelm atm ...
first get your arguments objects straightened out ...
ok, thanks all. I will look into splice and slice and think about how making a copy of the original array would help here.
congratulations on getting this far in the js challenges, @SSabu -- S&D is a challenge many folks have trouble with ...
thanks @bitgrower
ssabu sends brownie points to @bitgrower :sparkles: :thumbsup: :sparkles:
:warning: ssabu already gave bitgrower points
@SSabu
just thinking ... if u using this way
for (var i = 1; i < arguments.length; i++) {
arr = arr.filter(function(val){ return val != arguments[i];
});
}u no need to really make a copy of the whole argumnent object..
just the one u using at moment the filter callback use.. cuz u only need 1 value... at time
ok thanks @moigithub
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I still need to try to figure out what that means though
so on the filter.. u only using arguments[i] whatever i value is
yes
var igonnausethis = arguments[i];
ok, will think about that and the other suggestions you have all given me
yes, it makes sense now why I would need to do that
oh....!
function titleCase(str) {
var splitStrings = str.split(" ");
var stringStorage = splitStrings.map(function(val){
for (var i = 0; i < splitStrings; i++)
return val[i][0];
});
return stringStorage;
}
so I could have that variable definition in the for loop and the array filter method using the variable. but wouldn't the array filter need to be in the for loop too
?
you have the filter inside the loop now... and yes about the var too
should I have the filter outside the loop?
didnt tested so not sure if will work :) but best way to find out is trying :)
nope
ok, will think about that.
yes, that makes sense
thanks @moigithub
ssabu sends brownie points to @moigithub :sparkles: :thumbsup: :sparkles:
:warning: ssabu already gave moigithub points
sigining off the chat to try all the suggestions you guys have given me
thanks again!
@hellotojello this makes an array... from a string.. "splitting" on a space
var splitStrings = str.split(" ");
so if u have "hello world".. u will get ["hello","world"]
@hellotojello Array.map.. its like a for/loop
it picks each element of the array .. and pass it one by one to ur callback
it picks each element of the array .. and pass it one by one to ur callback
splitStrings.map(function(val){
so
val at first loop will be "hello"
and at second loop will be "world"
@hellotojello
since
return val[i][0];since
val === "hello" (at first loop)
val[0] will return "h"
but its not an array of array.. so u cant do val[i][0]
so i don't need the for loop?
on console doing "hello"[0][0] returns "h" :)
This message was deleted
@hellotojello nope
Can anyone point out why my code is returning two for:
Write a function that splits an array (first argument) into groups the length of size (second argument) and returns them as a two-dimensional array.
function chunk(arr, size) {
// Break it up.
result = [];
arr1 = arr.slice(0,size);
arr2 = arr.slice(size);
//return result.push(arr1, arr2);
return result.push(arr1, arr2);
}
chunk(["a", "b", "c", "d"], 2);
@FrOyxx push return a number
which correspong the length of the array
u pushing 2 elements to result... so ur function will return 2
@moigithub ok that makes sense. thanks for the explanation
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```
<script type="text/javascript">
/*<![CDATA[*/
var sportLink=[];
</script>
</head>
<body>
<form>
Select sport
<select id="sportlist" onchange="window.location.href=this.value">
<option></option>
<option value="http://www.espn.go.com/mlb">Baseball</option>
<option>Football</option>
<option>Hockey</option>
<option>Basketball</option>
<option>Tennis</option>
</select>
</form>
</body>
</html>
I'm trying to make a drop down list with three addtional url's per sport. I'm sort of lost.
I'm probably behind the times, I'd probably just use html/css ...
// Setup
function abTest(a, b) {
// Only change code below this line
// Only change code above this line
return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
}
// Change values below to test your code
abTest(2,2);When a return statement is reached, the execution of the current function stops and control returns to the calling location.
Example
function myFun() {
console.log("Hello");
return "World";
console.log("byebye")
}
myFun();
The above outputs "Hello" to the console, returns "World", but "byebye" is never output, because the function exits at the return statement.
Instructions
Modify the function abTest so that if a or b are less than 0 the function will immediately exit with a value of undefined.
Not sure what to do with undefined and if I'm supposed to use a switch state or if
@aphextwin234 shoutout to you for your username =p
undefined is a javascript keyword
@wumpafruits ^_^
are you saying use css to create additional links? @bitgrower
yeah ... if you look around on the css sites, I'm pretty sure you'll find css code to create cascading menus ...
@moigithub undefined: A primitive value automatically assigned to variables that have just been declared or to formal arguments for which there are no actual arguments.
function doSomething(arg1, arg2) {
console.log(arg1);
console.log(arg2);
}
doSomething(1, 2);
// => "1"
// => "2"
doSomething();
// => "undefined"
// => "undefined"
@brainyfarm yes cuz you folks are always there when i need help :smile:
Hello everyone...I am a bit stuck with else if statements. I understand the overall concept but I am having an issue with the 'Golf Code'.
function diff(arr1, arr2) {
var newArr = [];
// Same, same; but different.
newArr = newArr.concat(arr1, arr2);
newArr = newArr.filter(function (val) {
return !(arr1.indexOf(val) > -1 && arr2.indexOf(val) > -1);
});
return newArr;
}
diff([1, 2, 3, 5], [1, 2, 3, 4, 5]);
@Michelle2016 can you paste your code
I'm on the "Where art thou" challenge, and I'm having difficulty working with objects. I found a way to compare the properties of the "collection" and "source" objects, but I don't know how to compare the values of those properties. Here's my code:
function where(collection, source) {
var arr = [];
var keyarr = [];
for(i=0;i<collection.length;i++){
if (collection[i].hasOwnProperty(Object.keys(source))){
arr.push(collection[i]);
}
}
return arr;
}
where([{ first: "Romeo", last: "Montague" }, { first: "Mercutio", last: null }, { first: "Tybalt", last: "Capulet" }], { last: "Capulet" });@cannelflow function golfScore(par, strokes) {
// Only change code below this line
if (1, 1){
return "Hole-in-one!";
}
else if(strokes <= par - 2){
return "Eagle";
}
@cannelflow I am guessing that my condition should only be numeric?
if (1, 1){<-------if(1,1) means nothing do like if(strokes===1)
return "Hole-in-one!";
}
else if(strokes <= par - 2){<------this part is good
return "Eagle";
}
@cannelflow That is so funny because the if (1,1) is the par that they were giving me the green check for.
The second part else if they were still giving me the incorrect red X.
@Michelle2016 yes if(1,1) will do good sry cuz strokes value is also 1 can you show you whole code
but its good to write like if(strokes===1)
hello, it's me again... still having trouble with Search and Destroy challenge. I did make a little progress since last time.
Can anyone help?
here's my code:
function destroyer(arr) {
var mustRemove = arr.splice(1, arr.length);
for (var i=0; i<mustRemove.length;i++)
var remove = mustRemove[i];
arr = arr.filter(function(val) { return val != remove;
});
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
I think I just figured out my mistake...
@cannelflow Thank you for your help, I got it!
function golfScore(par, strokes) {
// Only change code below this line
if (strokes == 1){
return "Hole-in-one!";
}
else if(strokes <= par - 2){
return "Eagle";
}
else if (strokes == par - 1){
return "Birdie";
}
else if (strokes == par){
return "Par";
}
else if (strokes == par + 1){
return "Bogey";
}
else if (strokes == par + 2 ){
return "Double Bogey";
}
else if ( strokes >= par +3){
return "Go Home!";
}else{
return "Change Me";
}
// Only change code above this line
}
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:star: 799 | @cannelflow | http://www.freecodecamp.com/cannelflow
@SSabu you slicing from arr not arguemnts
@Michelle2016 :+1:
@cannelflow Yea!!!
yes, that's what I realized.
Thanks @obouchari
ssabu sends brownie points to @obouchari :sparkles: :thumbsup: :sparkles:
:star: 338 | @obouchari | http://www.freecodecamp.com/obouchari
My question is why there is only one argument for the original function.
Shouldn't there be 2: one array, and then arguments for the values to remove from the array?
Arguments in function contain all arguments passed in not parameters defined in the function
@SSabu -- it's like I explained earlier ... you can have ANY number of variables sent to a function ...
however ... they aren't always necessarily named ...
in this case, 3 arguments are passed, only the first of which is named (arr)
ok, so I should split the argument arr into the array from which I am supposed to remove values, and then the values which I am supposed to remove?
or put another way .... (number of named-parameters) !== (number of arguments passed to the function)
...in this case ...
@SSabu also put in mind that arguments are not arrays even though the look like it, so you have to use apply/call
ok.
arr = argument[0] = [1,2,3,1,2,3]
and then what do you call the 2,3 in the example?
argument1 -- has no "name" until you give it one ... = 2
argument [2] = 3
both the 2nd & 3rd arguments have NO NAME outside of arguments[n]
no you are handed the arguments object, you don't have to do anything with it except use the values you find
go run your code at pythontutor.com/javascript.html
I'm running my code on replit
so should I use arguments.slice(1,1) to peel off the arguments one by one?
there's a reason I'm recommending pythontutor ... I've not seen the same features on repl.it
@SSabu
function foo() {
console.log(arguments); // { '0': 2, '1': 3 }
}
foo(2,3);
ok, I'll check it out
@SSabu Arguments are Array like object
no ... I really wouldn't recommend using arguments.slice(1,1) in the way you are indicating ... there are much cleaner ways of doing that (you CAN loop thru the arguments object if you really need to ...
array-like -- which means MOST of the array functions don't work on it, except .length
oh, and indexing ...
@bitgrower @SSabu arguments.slice() would not work
indeed!!!
wasn't paying attention ... LOL ...
function destroyer(arr) {
//var mustRemove = arguments.splice(1, arr.length);
for (var i=1; i<arguments.length;i++)
var remove = arguments[i];
arr = arr.filter(function(val) { return val != remove;
});
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
which is WHY you want to make a copy of the arguments.object and/or parts of the AO
does it work ?
ok, so this returns [1,2,1,2]
@bitgrower Can still use slice
[].slice(arguments, 1);
so it's removing the 3's ... not the 2's ...
yes
and when I change so the i starts at 0 it returns the same array with the 2's inside it...
can you assign arguments to a variable? so var x = arguments?
I would look at your return statement based on your results ... (not based on the code) ...
@SSabu -- there is a line of code on the MDN AO page you can steal ... :)
ok, will take a look.
I took a long nap, haven't been working on this since I was last on here, for what it's worth...
Thanks @obouchari & @bitgrower
ssabu sends brownie points to @obouchari and @bitgrower :sparkles: :thumbsup: :sparkles:
:warning: ssabu already gave obouchari points
:star: 526 | @bitgrower | http://www.freecodecamp.com/bitgrower
you might also want to take a look at the indexxOf array function, too ...
and you could use pythontutor to step thru the code and see why it's giving you the results you are getting ...
@bitgrower Nice tool man!
pythontutor
yeah ... it gets hard to follow if you have more than a few arrays, but it can really help get insight on what's going on ....
Hello guys im at basic algorithm scripting now didn't completed my basic front end projects, which one to do first,any help???
True and learn some neat stuff on the way ;)
seek and destroy was driving me nuts because I didn't understand the difference between named parameters & the arguments object -- when I put some S&D code in and saw that arr = 1,2,3,1,2,3 -- I was convinced that there was something REALLY basic I didn't understand ...
and, at that point, I started to be able to ask the questions which helped me finally understand ...
...then I pieced different things I'd learned about js and finally understood why arr was 1,2,3,1,2,3 ... and expanded my understanding of js tremendously ...
Anyone please
@meghanasarikonda You can follow the order of projects
Tribute is kind of simpler to build than Portfolio
I would recommend doing the first 2 front end projects if you've done all the html/css, jquery, bootstrap stuff ...
...yeah, and it's better to do them while all the stuff you've just learned is fresh in your mind ...
What they did with those projects was an EXCELLENT move, imo ...
people get so bogged down in doing the algos & learning js, they forget what they just learned ...
@bitgrower okay I will complete my projects now
I like that python tutor @bitgrower
LOL ... told ya ... :)
they have other languages, too (obvious by the name, I'm sure ... )
so if I made a copy of the arguments object, in the example, that would be an array with 2 and 3 in it, right?
based on the example: destroyer([1,2,3,1,2,3], 2,3)
@SSabu -- go try it and see
w/ pythontutor you should be able to see EXACTLY what's going on ...
how should I make a copy of the arguments object? just like var x = arguments?
did you look on the MDN Arguments Object page like I told you about 5 minutes ago ?
yeah
don't glance at it ... READ it ... starting from the beginning ...
meh
Could someone give me a hint on where to start with Falsy Bouncer? The instructions are to "Remove all falsy values from an array." I've read the filter() documentation at MDN, but am just so lost on where to even start. Like, do I create a new variable outside the function like MDN shows? Do I loop through every value in the array individually?
let me tell you something, @SSabu -- software changes rapidly -- if you want to work in software, you need to be able to go get these answers for yourself ...
it's an important skill ...as important as being able to write the code ...
that was true 35 years ago ... and it's even truer today ... :)
it worked!
umm... ok
YAY!!!!
you figured it out ???
yeah
so...did you have a breakthrough insight ?
do you understand why your code works ?
lol, still trying to figure that out, actually.
if you go into my profile http://freecodecamp.com/bitgrower -- you can click on my solution ...
NOW, let me tell you that I had kinda given up, so that's not original code ... HOWEVER, what I did do is sit down and understand, IN DETAIL why it works (well, with the exception of the line of code I stole from MDN) ...
...and I explain it all in my solution ...
...because the solution really is a BRILLIANT use of economical javascript ...
I took the line from the MDN where it turns the arguments object into an array
I understand the rest of the code
ah ... you found it !!!!
excellent !
I don't understand how that line turns the arguments object into an array
it's a long line
it is ...
var args = (arguments.length === 1?[arguments[0]]:Array.apply(null, arguments));
yeah, it uses the ternary operator to determine the length of the arguments array/object
that was my trouble... i was assuming the arguments object was an array that I could loop through
if it's 1 -- hey, just return it back
ok, I'll look
if it's 2 -- then it turns the arguments object into an array ... using apply ... I don't understand that very well .
ternary operator?
ok will research that
it's basically a way of shortcutting an if/else statement ...
Is this anywhere close to the solution for Falsy Bouncer? It doesn't work, but I feel like it's close...
function bouncer(obj) {
if(!isNaN(obj)) {
return true;
}
}
var filtered = arr.filter(bouncer);
console.log(filtered);
bouncer([7, "ate", "", false, 9]);
if (x === 3)
do something
else
do something else
do something
else
do something else
that's awesome though, I was working on this for like a week, or at least putting it off for a week because I was on a roll with the basic challenges and this one completely threw me for a loop.
would be x===3? do something : do something else
LOL ... I hear ya ...
:smile:
but go check out my solution, because I think the comments will help you to understand the solution (which is the wiki solution) ...
it's a handful of lines ... but very elegant...
ok, I will
yo
mapping the debris description is wack
...and, then make your own comments -- because I can nearly guarantee you, you'll go back and look at that solution again ...
@gordondavidescu -- you won't get any argument from me on that
like ... hi, can we dimensionalize the numbers here ?
I've taken it to mean you have to add the radius of the earth to the height
I can't say much for no repeats please, either ... seems like b(1) a(1) b(2) a(2) is different than b(2)a(2)b(1)a(1) in determining the # of permutations ...
Array.apply(null, arguments)
so this is the part that turns the arguments into an array it seems.
yes...
ok, I'll look into the apply method.
@bitgrower is that all it means?
i'm reading the wikipedia article and getting nowhere
yeah ... that's a bit of a "through the looking glass" -- using apply (& bind & call) ... if you get any profound insight, @SSabu,, come back and share it ...
lol.... i'm a dabbler... don't think I will come to a profound insight... but if I do, I'll keep you posted
@gordondavidescu -- that's what I kind of took away from it ... but I'm not getting the right answer, either ... so ... you know the saying "don't follow me, I'm lost!"
I did figure out what they want in that equation is in meters & they give you a value in kM ...
@SSabu -- do you know any other programming languages ?
I've studied python a bit
just dabbling in all this
my job is boring...
lol
don't know if I could be a professional programmer though because this stuff is pretty challenging...
do you @bitgrower ?
do I what ?
know other languages?
yeah ...
nice!
pascal, c, several different assembly languages -- or at least I used to ... :)
a little bit of python ...
a little bit of python ...
nice!
oh yeah, and let's not forget basic ... hahahahahahaha
cool. Ok, signing off. thanks again !
@bitgrower
several different assembly languages
Respect :+1:
you bet ...
wow, quiet in here today...
thanks @bitgrower
gordondavidescu sends brownie points to @bitgrower :sparkles: :thumbsup: :sparkles:
:star: 527 | @bitgrower | http://www.freecodecamp.com/bitgrower
Did anybody complete the Chunk challenge?
are you stuck on it?
@Vanhealen i'm sure somebody has. paste your code and your issue and maybe they will give some advice
Did you guys do FCC in order completely? it is meant to be done in order
?
it's meant to be done in order but you can jump around if you want
@rphares -- Valentine's Day ...
@vanhealen -- chunky monkey ?
@Vanhealen , it is meant to, but by no means required,
i have thus (no where near done) but many do not,
if you have prior coding experience, feel free to skip around--
@Vanhealen -- some exercises make a lot of sense to do before others ... like the nested for loops comes after an exercise in using a for loop to walk thru an array ...
@rush86999
anybody know why this doesn’t work i am trying to pass a number or a “.” point in the if function
else if (!(isNaN(this.pressed) || (this.pressed == ".")decimal point
the material does build-- it expects you to know more as the lessons progress, so if you are new to coding, going in order will be beneficial. if not, do what you like, though the review doesn't hurt and should be quick if you know a lot :)
which challenge, @rush86999 ?
I'm on the "Where art thou" challenge, and I'm having difficulty working with objects. I found a way to compare the properties of the "collection" and "source" objects, but I don't know how to compare the values of those properties. Here's my code:
function where(collection, source) {
var arr = [];
var keyarr = [];
for(i=0;i<collection.length;i++){
if (collection[i].hasOwnProperty(Object.keys(source))){
arr.push(collection[i]);
}
}
return arr;
}
where([{ first: "Romeo", last: "Montague" }, { first: "Mercutio", last: null }, { first: "Tybalt", last: "Capulet" }], { last: "Capulet" });
this is not a javascript challenge it is the calculator challenge but this is a javascript question @bitgrower
I was just reading how isNaN is a very tricky function ... and about the only way to make sure you have NaN is to check the value you are checking against NaN ....BECAUSE, hold onto your seats ... NaN !== NaN ... (go figure!)
the if( ) should allow either number OR decimal point send from a click function but not working for the decimal point
@BLayman -- it may help to review some of the previous object algo challenges ..
like Profile Lookup ...
@bitgrower and
typeof NaN === number :wink2:
i am using console log and the expression i mentioned doesn’t seem to allow “.” to go through
yeah ... that too .. @qualitymanifest -- I spent hours trying to figure out why my falsy bouncer didn't work and discovered that ... LOL ...
@rush86999 dunno about the . ... have you tried escaping it ?
@BLayman -- I can't say my solution is the best or fastest way to do it ... but I did make use of the Object.keys function ...
@bitgrower i am not sure that would matter but I’ll try. it’s just string object
@bitgrower yea doesn’t work
try it on jsfiddle see
@BLayman this will most certainly fail
if (collection[i].hasOwnProperty(Object.keys(source))){if you read the return value of Object.keys you will notice that it returns an array of properties from the object you pass as an argument/parameter
@BLayman so if you want to check if properties in source exist in collection then you have to loop through the returned array in Object.keys(source)
@rush86999 what you working on?
for the Seek and Destory, I am confused that how to filter the arguments.
function isExist(value)
{
if(value)
{
return false;
}
else
return true;
}
function destroyer(arr) {
// Remove all the values
for (var i = 1;i < arguments.length;i ++)
{
arguments[0].filter(isExist);
}
return arr;
}
@neal1991 look at the examples on how to get the arguments
@neal1991 -- 90% of the time people's initial problem with S& D is this: they don't understand what Arguments Objects represents, AND they think Arguments Object === arr ... and it is NOT ... arr is arguments[0];
and you can't use filter on the arguments object ...
it is array-like -- but it is NOT an array ...
The crucial probelm is the isExist function can not accept arguments in the filter.
why do you think that, @neal1991 ?
@bitgrower Yeah I think that challenge was helpful for understanding .hasOwnProperty , but in this case I don't know the name of the properties, so I can't use object.property to compare them. Like how I did contacts[0].firstName in profile lookup.
In the destoryer function, I need the arguments, and then filter them, isn't it?
you need to use the Object.keys to get an iterator ... :)
@neal1991 also remember each function is assigned an object (arguments) that will contain all the parameters passed on to the function, named or not named
This message was deleted
@bitgrower :smile:
LOL ... devilish little thing, isn't it ... who you send msgs to ...
@neal1991 remember about scope as well
I don't see why it doesn't do auto-complete ...
..,.I do not understand what do you mean.
@bitgrower not a big deal :smile: we can just edit
I mean, it does -- but under what pattern, I'm not sure ... I'll go to type someone's name and I'll end up with @camperbot ...
bitgrower @bitgrower is auto-complete spoiled
@neal1991 -- we know you don't understand ... and that's one of the reasons you're having problems ...
@wearenotgroot It seems to be successful in pushing the collection objects that contain a key that is found in source, but it fails at returning the objects that match both the keys, and the values associated with the keys.
@neal1991 remember if you try and access arguments inside the filter you will access the arguments of the filter function and not the main function it is in
the arguments object is an array-like object containing ALL the arguments ...
@BLayman you need to test for it separately
however, not all parameters provided in the function definition have to have names ... so the only way you can find them is through the arguments object ...
I know this, but how should I use it for the filter, it is the poinrt.
in this case, you are passed 3 arguments, and you only have 1 named argument ...
@wearenotgroot I think it would fail to work if source contained more that one key, which might be what you're getting at.
@neal1991 -- start with Arguments Object page on Mozilla Developer Network ... there's a nice little piece of code which will convert your AO to an array ... :)
@neal1991 just store the values on argument of the main function into an array so the filter can access it
can you give an example, I think it would be easier for me to understand ...
literally, @neal1991
@BLayman need more loops then,
but the arr how to be passed to the isExist function
@BLayman remember you have other types of loop that specialises on looping through properties as well
@wearenotgroot So I shouldn't use a for loop?
@neal1991 -- read up on Array.filter ...
@BLayman you can use normal for loop
@BLayman you just need separate for loops
@BLayman or a filter then a for loop for the properties
@wearenotgroot would nesting the loops be a good approach?
@BLayman sure thing
@BLayman remember you have other types of loop that specialises on looping through properties as well
^^^ I'm all ears... :)
@BLayman just dont get confuse on which is which
@bitgrower for (var someprop in) :smile:
@wearenotgroot @bitgrower So I think I could figure out how to use two loops to find the shared properties in collection and source, but the main wall that I'm hitting is that I don't know how to compare the values of those properties, to make sure those match too.
@BLayman you can try and use a filter for the collection then for loop for the Object.keys, that way you only have to deal with 1 for loop
value = object[property]
Will someone please help me understand why this function is not working properly?
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// Only change code below this line
for(var i = 0; i < contacts.length; i++){
if(firstName === contacts[i].firstName && prop === contacts[i].prop){
return contacts[i].prop;
}
if (firstName !== contacts[i].firstName){
return "No such contact";
}
if(prop !== contacts[i].prop){
return "No such property";
}
}// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "likes");
@bitgrower But what if I don't know what the property is called?
@wearenotgroot -- so then you would have to check .hasOwnProperty, right?
that's what Object.keys is for
@bitgrower :+1:
For some reason the first "if" statement is not evaluating.
It is not evaluating true.
@bitgrower i meant more for like the algorithm challenges
The arguments of "Akira", "likes" are contained in contacts. Therefore, they are true.
@knnonah this guy ----->prop === contacts[i].prop will not give you the result you are after
@knnonah -- can you please help the tired eyes of the helpers here and use @camperbot's formatting instructions (follow closely & carefully) ...
explain format
:point_right: code formatting [wiki]
Inline code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
Code Block
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
@knnonah to test if the property exist use .hasOwnPropert(prop)
@bitgrower But wouldn't that just tell me if it has a property, not the value of the property?
can anyone explain the .reduce function? the mozilla description is sort of weird
im on the first intermediate bonfire summing all numbers in a range
@wiscoay521 is it ?
@Blayman -- once you use Object(keys) you have an array of keys ...you can iterate thru those
@wearenotgroot yeah i don't really understand it
post your code @wiscoay521 ... always seemed pretty straightforward to me ...
@camperbot
ah i haven't started it haha. just looking at how best to approach it first
@wiscoay521 well it start out with the previous at element zero, then you have a current, now do some computation on those then return result, that result will now be the previous
@knnonah -- you can say things like "help", "wiki", "explain" to get @camperbot's attention ...
@wiscoay521 then it moves on to the next
@wearenotgroot oh ok that helps
@wiscoay521 take a look at the table displaying data on the example
bitgrower @bitgrower thinks she should go thru the FCC suggested course on functional programming ...
so if an array is like this ([1,4]) than it means it is a ranged array? like 1,2,3,4?
@wiscoay521 -- no .
it's just 2 numbers
Why doesn't contact[i].prop work?
Also, contact[i].hasOwnProperty(prop) isn't working as well?
@bitgrower oh ok. i thought the parenthesis meant it was a range or something
which parentheses ?
sumAll ([1, 4]);
@knnonah if you analyse your data. you will see that prop is not a property on the object so .(dot) notation will not work
{
"firstName": "Akira",//<--------------------.firstName will work
"lastName": "Laine",//<---------------------.lastName will work
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
it wants me to sum the two numbers and all numbers in between. Since there are only two numbers I was wondering how exactly I sum numbers that aren't there
@bitgrower Oh, so Object.keys() gives you the keys, and the value of the keys?
LOL ... no, that means it's an argument being passed to the function ... :) ... I think the instructions mention it's a 2 member array ...
@Blayman -- that's how I understand it ... it's an array of the keys of your object ...
Yes, is prop a variable and if the argument "likes" is assigned to it and "likes" is a property why doesn't it work?
@bitgrower oh jeezz. duh lol
We'll pass you an array of two numbers. Return the sum of those two numbers and all numbers between them.
The lowest number will not always come first.
those are the instructions though
@knnonah using variable to access the object and values, you have to use bracket notation
LOL ... we all do s* like that, not to worry ... laugh ... slap your head and go ... okay, hopefully I won't make THAT mistake again ...
...but the PRIMARY lesson is to read things CAREFULLY ... read 'em once, and even when you think you understand them ... read them again ...
@knnonah like so contacts[i][prop] as oppose to contacts[i].prop
there are ANY number of challenges where I didn't do that to begin with, and would have gotten to solutions much faster had I ...
@knnonah this guy ---prop = 'likes' --->
contacts[i][prop] is the same as contacts[i].likes or contacts[i]['likes'] if prop is equal likes that is
seems like straightforward instructions to me, @wiscoay521 -- I don't know how they could get too much clearer ... :)
@wearenotgroot
@wiscoay521 -- so break it down ...
you have 2 numbers, and they aren't in order ...
ah ... okay, maybe I need to put them in consistent order before I move on ... :)
@wearenotgroot using the bracket notation or the hasOwnProperty() method is not working.
@wiscoay521 -- then I have 2 numbers, and I need to sum up the intervening numbers and the 2 numbers I've been given ... hmmmmm ... okay ... how can I do that?
@knnonah depends on how you are using them
I am still not seeing where I am going wrong and where my misunderstanding is.
@knnonah post updated code
@wiscoay521 -- many times if you just solve the problem any way you can to get the right solution, then you can get some insight into how to solve the problem better ... :)
@wearenotgroot
function lookUp(firstName, prop){
// Only change code below this line
for(var i = 0; i < contacts.length; i++){
if(firstName === contacts[i].firstName && prop === contacts[i].hasOwnProperty(prop)){
return contact[i][prop] ;
}
if (firstName !== contacts[i].firstName){
return "No such contact";
}
if(prop !== contacts[i].prop){
return "No such property";
}
}// Only change code above this line
}
@bitgrower @wearenotgroot Ok, I think I have a strategy for getting the values associated with the keys. Use Object.keys() to make an array of the keys, then use that array to get the values associated with those keys. Something like this:
sourceKeys = Object.keys(source);
valueOfFirstKey = source.sourceKeys[0];look about right?
@knnonah the most trickiest but rather simple part of this challenges is where to do the
return "No such contact" bane of peoples existence
@knnonah remember .hasOwnProperty will return a boolean value
@knnonah if the property in question exist it will return true if not false
@knnonah the correct use is
if(firstName === contacts[i].firstName && contacts[i].hasOwnProperty(prop))
@knnonah prop value is 'likes' --while ------->contacts[i].hasOwnProperty(prop) will return true/false so this wont work prop === contacts[i].hasOwnProperty(prop)
@
@wearenotgroot Previously, I tried the hasOwnProperty based my condition on the true or false outcome and still the function did not evaluate correctly.
@BLayman sure that will work
@knnonah yes because of the second if test you have
@bitgrower @wearenotgroot Cool, I think I have the tools to figure it out now. Thanks for pointing me in the right direction.
blayman sends brownie points to @bitgrower and @wearenotgroot :sparkles: :thumbsup: :sparkles:
:star: 844 | @wearenotgroot | http://www.freecodecamp.com/wearenotgroot
:star: 528 | @bitgrower | http://www.freecodecamp.com/bitgrower
@wiscoay521 sorry wrong mention :smile:
@wearenotgroot The if test for firstName?
@knnonah this guy --------->
if (firstName !== contacts[i].firstName){
return "No such contact";
}
@knnonah what happens if the first if test fails ? and this triggers?
@wearenotgroot I get "No such contact" in the console.
@knnonah yes you do
@knnonah however are you sure it chck every item on contacts array?
It doesn't. It only checks FirstName.
At least, that is my belief.
@knnonah well ->firstName !== contacts[i].firstName means it the firstName are not equal
hello, can anyone help me center an h1? http://codepen.io/thaniri/pen/MKPEXm
@knnonah it is the same as else
if(firstName === contacts[i].firstName)
{
}
else
{
}
@wearenotgroot Yes, that is a condition written into the exercise. If firstName does not correspond to any contacts then return "No such contact"
@knnonah yes, but think of what happens if the first if test fails
@knnonah the second one will be executed next
@knnonah then it will be triggered and then returns No such contact
Yes, but it triggers only if firstName has no match.
@knnonah but you cant be sure if the test reaches the end of the contacts array
No, I can't.
@knnonah ok let take an example
@knnonah let's say "Harry" is the name you are after
@knnonah now we know that the first on the list is Akira
@knnonah so the first if test will fail for sure
@knnonah then it moves on to the second if test
@knnonah finds that the firstName isnt a match then return No such contact
@knnonah the loop exits and the function returns
@knnonah you see what happened?
@knnonah it never got to the second item on the array
Yes, I understand. The function is only evaluating thru the first item in the array.
@knnonah remember every return statement will stop the loop and exit the function
I need to rearrange my return statements.
@knnonah ok then how can we make sure that it will not exit too early?
@knnonah :+1:
hi All
function factorialize(num) {
var factorial;
var ans = 1;
for(i=0; i<num; i++){
factorial = num - i;
ans = ans * factorial;
}
return factorial;
}
factorialize(5);whats is wrong with this code?
@knnonah most simpliest solution is to not have the second if test
@knnonah just return "No such contact" outside the for loop
@knnonah that way you let the test continue until the end of the contacts array
@wearenotgroot Thanks for your help. I am going to rewrite the function now.
knnonah sends brownie points to @wearenotgroot :sparkles: :thumbsup: :sparkles:
:star: 845 | @wearenotgroot | http://www.freecodecamp.com/wearenotgroot
@knnonah YW
@SuhasHosamani you are returning the wrong thing
@SuhasHosamani try return
ans instead of factorial
also @SuhasHosamani -- did you mean factorial to be num -1 ?
can anyone help me out ... in solving the "stand in line" chaallenge in javascript?
working on the wikipedia project. has anyone noticed that you can just paste wikipedia's search code into a page and it works? no api's needed
@keerthinerella -- it's a 2 line solution, pretty much -- and the best way to find it, imnsho ...
is to go look inthe Mozilla Developer Network on the arrays page and "shop" for some functions which will satisfy the challenge ... :)
@bitgrower i have used push and pop functions there..
@SuhasHosamani `
function factorialize(num) {
var factorial;
var ans = 1;
for(i=0; i<num; i++){
factorial = num - i;
ans = ans * factorial; //<-----------------------stored the computed value on ans but returned factorial for some reason :)
}
return factorial; //<-------------returning the wrong thing, return ans instead
}
factorialize(5);
@bitgrower yet it is not completed
good !!! you are very close then .. but you picked up one wrong function ... you need to replace it with a different one .. there are methods for getting the value on the "left" side of the array, and ones for getting the value on the "right" side of the array ... .different functions
@DavidWeedmark yes but the point was to use the api
(but ones this old assembly language programmer finds near & dear to her heart ... !!!)
@bitgrower so shall i use shift function here?
hmmm .... well, try it out and see !!!!!
@wearenotgroot oh I'll be doing it the hard way. I just wanted to see how they did it, when lo and behold, it worked!
@DavidWeedmark :+1:
function steamroller(arr) {
// I'm a steamroller, baby
var result = [];
function flatten(stuff) {
for (i = 0; i < stuff.length; i++) {
if (Array.isArray(stuff[i])) {
flatten(stuff[i]);
} else {
result.push(stuff[i]);
}
}
}
flatten(arr);
return result;
}
sorry...anyone did this yet?
@DavidWeedmark well the wikipedia page uses it's own api so, it only make sense that what you did will work :smile:
I can't seem to be able to complete it...:(
LOL, yes @LaevateinY -- lots of folks ...
i mean like is there anything wrong with my recursion? it crashes my browser everytime haha
...I'd say your browser has spoken ...
@bitgrower yes num -1
@bitgrower i have used shift function...but no change ;(
@SuhasHosamani did my suggestion worked?
can u help me out?
@keerthinerella -- post your code follow @camperbot's instructions CLOSELY
explain format
:point_right: code formatting [wiki]
Inline code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
Code Block
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
@wearenotgroot yes :) thanks
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@SuhasHosamani next time name the variable properly and note what to use them for :smile:
@SuhasHosamani i think you got confuse because you both have factorial and ans variable
@wearenotgroot yes got confused :smile:
@LaevateinY you forgot to concat the arrays!
@wearenotgroot can i better tat ans??
@SuhasHosamani you mean if your code was ok?
@SuhasHosamani yes your code it good
@wearenotgroot Doesn't the push function push all the values that are not arrays into the array called result?
@wearenotgroot okay
@LaevateinY well the point of the isArray test was to test if the item is an array
@LaevateinY then concat the result of
@LaevateinY a recursive call
@LaevateinY something like -
@LaevateinY
if (Array.isArray(stuff[i])) {
result = result.concat(flatten(stuff[i]));
} else {
@LaevateinY the recursive call is meant to check if there is further more array inside the item you tested
anyways going to eat beakfast
GL and Happy Coding
@LaevateinY The function gets simpler if you forget the inner function and use steamroller to flatten the inner arrays.
@Masd925 @wearenotgroot Thanks guys...I found the issue but I'm not sure why
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for (var i = 0; i < stuff.length; i++) {
Apparently i needed to add the "var" in the declaration of the loop variable
which I'm not very sure why...you guys have any idea?
you've otherwise defined it as a global, @LaevateinY -- that means each call of the function is going to be using the same variable i
@LaevateinY You need to declare it inside the for loop definition or at the start of the function. Both are actually equivalent.
oh i see...so in previous exercises it worked because i only used the i once!
@bitgrower @Masd925 thanks guys
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can anyone please help me with Counting cards challenge
well, when you are using recursion -- local variables take on added significance ... :)
I'm sure @Mas925 & @wearenotgroot have better explanations ... :)
@Yuvraj1989 -- sure -- helps if you can post your code as to @camperbot's instructions:
explain format
:point_right: code formatting [wiki]
Inline code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
Code Block
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
Hi All,
function palindrome(str) {
// Good luck!
var arr = [];
arr = str.split('');
arr.reverse();
revstr = arr.join('');
revstr = revstr.replace(/' '/g, '');
if(revstr === str){
return true;
}else{
return revstr;
}
}
palindrome("race car");space is not getting removed.
you probably need to declare revstr before using it, @SuhasHosamani
and you've only removed spaces from the reversed string
that too, @uriznik -- I'm not sure if @SuhasHosamani has assumed strings are mutable ... (which they aren't)
var count = 0;
function cc(card) {
// Only change code below this line
if (card<1 && card<=6){
count =1+ card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card >6 && card<=9){
count=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card ===10 || card === 'J'|| card ==='Q'||card ==='K'||card =='A'){
count -=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
yeah, looks like you cannot do this effectively: revstr = revstr.replace(...
not working
can you post your code via @camperbot's formatting instructions ?
explain format
:point_right: code formatting [wiki]
Inline code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
Code Block
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
thanks!
revstr = revstr.replace(/\s/g, '');
str = str.replace(/\s/g, '');
@SuhasHosamani You should first remove the non-alphanumerics with replace and then construct the reversed string. That way you only need to replace once.
hmmm ... wonder if my playground is more restrictive for some reason ...
so ... you are saying those assignments worked ... or are you saying that you've solved the challenge... @SuhasHosamani ?
Hi everyone, could someone please tell me why my function capitalizeFirstLetter is returning that it's not a function?
function capitalizeFirstLetter(string) {
return string.charAt(0).toUpperCase() + string.slice(1);
}
var capitalized;
function titleCase(str) {
var splitStr = str.split(" ");
for (i = 0; i< str.length; i++){
var capitalized = splitStr.capitalizeFirstLetter();
return capitalized;
}
}
@efhjones why are you slicing after capitalization?
@efhjones Variables need to be declared inside the function so FCC can test function properly.
What happens when you call
slice() on an array without passing any argument?
@efhjones what type is splitStr?
@Masd925 @bitgrower only half assignment worked, the other half not working
@efhjones splitStr is an array and arrays don't have method capitalizeFirstLetter.
'var count = 0;
function cc(card) {
// Only change code below this line
if (card<1 && card<=6){
count =1+ card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card >6 && card<=9){
count=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card ===10 || card === 'J'|| card ==='Q'||card ==='K'||card =='A'){
count -=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
'
@Masd925 Ah ok. That would be convenient wouldn't it? :laughing:
@Masd925 earlier versions had SplitStr[i] in hopes of capitalizing the first character in a string in an array :grimacing:
''' js
:bulb: to format code use backticks! ``` more info
'''var count = 0;
function cc(card) {
// Only change code below this line
if (card<1 && card<=6){
count =1+ card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card >6 && card<=9){
count=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card ===10 || card === 'J'|| card ==='Q'||card ==='K'||card =='A'){
count -=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
'''
:bulb: to format code use backticks! ``` more info
@efhjones Your code has several small problems. If you don't get it working I can post the repaired version of it that works.
@Masd925 thanks, i'll keep working on it for a while and come back just before my fist goes through the screen
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```var count = 0;
function cc(card) {
// Only change code below this line
if (card<1 && card<=6){
count =1+ card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card >6 && card<=9){
count=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card ===10 || card === 'J'|| card ==='Q'||card ==='K'||card =='A'){
count -=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');```
@Yuvraj1989 the back ticks have to be on a new line
@efhjones Yes, that feeling is the driving force behind learning to code.
@Masd925 please
Hii @/all Can anyone recommend a good blog name for javascript? I want to start a blog to help the beginners get started on JS
Javascribe! :laughing: :
@4mohit JavaScript, the pesky little browser scripting language...not!
@SuhasHosamani post you updated code
var count = 0;
function cc(card) {
// Only change code below this line
if (card<1 && card<=6){
count =1+ card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card >6 && card<=9){
count=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
if (card ===10 || card === 'J'|| card ==='Q'||card ==='K'||card =='A'){
count -=card;
if(count>0){
return count+"Bet";
}if (count === 0 || count<0){
return count + "Hold";
}
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
@Yuvraj1989 -- you are SOOOO close ... you need to put the ```js on one line, and have nothing else on that line ...
@Yuvraj1989 have you done an exercise using the 'switch' statement?
```
yes I have
Hi, are there other ways to write Seek and Destroy without indexOf ?
```/jshint esversion: 6 /
function destroyer(arr, ...args) {
arr = arr.filter(function(val) {
if(args.indexOf(val) == -1) {
return val;
}
});
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);```
Thanks!
ahh you got it !!!! Congrats!
function convert(celsius) {
// Only change code below this line
myVar=(9/5)+32;
// Only change code above this line
if ( typeof fahrenheit !== 'undefined' ) {
return fahrenheit;
} else {
return 'fahrenheit not defined';
}
}
// Change the inputs below to test your code
convert(0);
Why don't you want to use indexOf, @TheoSarran
@Yuvraj1989 review this challenge: Multiple Identical Options in Switch Statements
Please help!
@chandra90 first of all you have to declare a variable
I just thought I'd ask, I find it useful to know different ways to do the same thing, for flexibility
@wearenotgroot Ok I'll try
@chandra90 here review this the formula http://www.rapidtables.com/convert/temperature/how-celsius-to-fahrenheit.htm
could this be written as a switch statement?
// Only change code below this line
function update(id, prop, value) {
if(value !== "" && prop !== "tracks") {
collection[id][prop] = value;
}
if(prop == "tracks" && value !== "") {
collection[id][prop].push(value);
}
if(value === "") {
delete collection[id][prop];
}
return collection;
}
you have a solution which works ? @TheoSarran ... I would say most people find indexOf as a pretty cool way to solve problems ...
What happens when you call
slice() on an array without passing any argument?
Great! I was curious... I'm pretty new. Thanks for the info @bitgrower
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@chandra90 your myVar is doing nothing to the input "celsius" check your formula
I would say you are doing very well if you are already attacking Seek and Destroy ...
@wearenotgroot , I know the formula, the problem is to write the algorithm
@chandra90 same as the formula
@chandra90 you just forgot to multiply the celsius
@chandra90 -- keep an eye on all the variables you are using, and arguments that are passed in, and make sure they are doing what you expect!
@Casadaro it will be complicated for switch because there are two things to check value and prop
err...make you you are using them in ways you think you are ... :)
@TheoSarran You can do it without adding new parameters to the function.
@coderNoob try it and see what happens :smile:
function lookUp(firstName, prop){
for (var i = 0; i < contacts.length; i++){
if ((firstName == contacts[i].firstName) && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
else if( firstName !== contacts[i].firstName) {
return "No such contact";
}
}// Only change code below this line
// Only change code above this line
}
// Change these values to test your function
lookUp("Kristian", "lastName");
@coderNoob -- or go check out the MDN page and see what it says .. :)
there is something wrong with my else if statement here. it evaluates to true even firstname is equal contacts[i].firstName
@george-of-croton remember you have an &&
I'm working on the simon game. I have an array of divs that need to be clicked, but I want a delay between each click. Here is my loop :
for(var i =0; i<sequence.length; i++){
$("#div" +sequence[i]).click();
}
I tried using setTimeOut, but I can't call functions inside loops. How do I do it?
I'm working on the simon game. I have an array of divs that need to be clicked, but I want a delay between each click. Here is my loop :
for(var i =0; i<sequence.length; i++){
$("#div" +sequence[i]).click();
}
I tried using setTimeOut, but I can't call functions inside loops. How do I do it?
@abhishekKumar1 looking at it, I felt like all he if statements were a hack job and was wondering if their might be a better way.
(argh sorry about the format. )
@wearenotgroot does that affect how i should write my else if statement?
@george-of-croton just remember it will evaluate both
@george-of-croton how many different things does your function return and does that match the specs?
@george-of-croton also use strict mode comparison 3 equals ===
@wearenotgroot I just completed the music collection today. I used a series of if statments. is there a better way to write it? ```
function update(id, prop, value) {
if(value !== "" && prop !== "tracks") {
collection[id][prop] = value;
}
if(prop == "tracks" && value !== "") {
collection[id][prop].push(value);
}
if(value === "") {
delete collection[id][prop];
}
return collection;
}
I still do not understand
myVar= fahrenheit;
myVar=*9/5+32;
`
@Casadaro looks fine!
@Casadaro you can restructure the if statement if you like
@chandra90 ---------formula ------->T(°F) = T(°C) × 9/5 + 32
myVar=*9/5+32; //<------------where is the celsius?var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
for (var i = 0; i < contacts.length; i++){
if ((firstName === contacts[i].firstName) && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
else if( firstName !== contacts[i].firstName) {
return firstName
;
}
}
// Only change code below this line
// Only change code above this line
}
// Change these values to test your function
lookUp("Kristian", "lastNa
@wearenotgroot I got it , but how ro add C in the formula?
@chandra90 look at the code where do you see a variable/parameter named celsius?
@chandra90 -------->convert(celsius)<-------------------------- use that
@wearenotgroot Thanks. Apparently it returns the original array as it is.
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something about my else if statement is causing it to evaluate as true when firstname === contacts name...
@coderNoob yes. because it has nothing to work on :smile:
@chandra90 are you not sure how variables are used in expressions/calculations?
@wearenotgroot So, I need to use convert(celsius) instead of my var bla bla?
hey finally I got the trick for the Counting Cards
@chandra90 you can store the result on myVar
@chandra90 you just need to complete the formula
@chandra90 the thing you are trying to convert is store in celsius which is the function parameter
@chandra90 the value of celsius is pass on to the function call when ----------->convert(6)------>convert(celsius)---------------> myVar = celsius * 9/5 +32
@chandra90 makes sense?
thanks @wearenotgroot im sure the further I get the worse my previous code is good to look.
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function lookUp(firstName, prop){
for (var i = 0; i < contacts.length; i++){
if (firstName === contacts[i].firstName && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
else if (firstName !== contacts.firstName) {
return "No such contact";
}
}
@george-of-croton yes that is the most simply and trickiest part to understand for most people
@george-of-croton ok lets take an example
@george-of-croton here is our array
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
},
];
@george-of-croton now say you are looking for the firstName equal "Harry"
@george-of-croton when the for loop gets going
@george-of-croton then the first if statement gets execute--------->
if (firstName === contacts[i].firstName && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
@george-of-croton it will result to false
@george-of-croton then it move to the second test the else if
else if (firstName !== contacts.firstName) {
return "No such contact";
}
@george-of-croton what do you think happens next?
@george-of-croton any clue?
wait wouldnt the if statement result to true if we searched harry because harry is a contact?
var celcius=(30);
function farenhight(celcius ) {
var farenheight =celsius * 9/5 +32};
@george-of-croton well it will be false because Akira is first on the list
@george-of-croton but yes Harry is in the list so it should be true
oh okay then it will return no such contact
@george-of-croton yep, and why is that bad?
@chandra90 what does that function return?
because harry is a contact...
@chandra90 the formula is now correct however you dont have to have another function
@george-of-croton what happens is because of the return key word
@george-of-croton the loops stop/break and the function exits
@george-of-croton so we cannot complete the search
@george-of-croton now, how can we fix this?
@wearenotgroot hmmmm...
@wearenotgroot i could change the value of firstName instead of returning a string?
@george-of-croton not necessay
@george-of-croton there is much simplier approach
@george-of-croton simple solution is to not check it at all
@george-of-croton remove that else if statement
@george-of-croton and move the return "No such contact" elsewhere
@george-of-croton but where? that is the question
@Casadaro try if , else if and else
@george-of-croton how can we make sure the the loop continues/ finishes when the first if test turns to be false on every iteration
@george-of-croton this is our loop right now
for (var i = 0; i < contacts.length; i++){
if (firstName === contacts[i].firstName && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
else if (firstName !== contacts.firstName) { //<--------------------if we remove this the loop continues if the first if test is false
return "No such contact"; //<---------------where to move this??
}
}
@wearenotgroot do we make it part of the for loop?
@george-of-croton no we want it not to break the loop so we need to move it
Hi there!
Is there anyone here who has completed the Weather App project? Need some help
Is there anyone here who has completed the Weather App project? Need some help
@george-of-croton where is the most logical place to put it then? if we want it remove from the loop?
@george-of-croton the answer is outside the loop
outside of the loop
@george-of-croton :smile: :+1:
@george-of-croton remember the code execute from top to bottom
@george-of-croton so we place it outside the loop after the loop
@george-of-croton that way even if the first if test and any other test is not triggered
@george-of-croton the loop finishes the search
@wearenotgroot that makes a lot of sense!
@george-of-croton then we eliminate any doubt that there isnt a contact with the given firstname
@wearenotgroot thank you!
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@george-of-croton YW
thank you very much!
@wearenotgroot did you complete the Weather project?
@george-of-croton remember you still have this ------->If prop does not correspond to any valid properties then return "No such property"
@neeraj-lad yes why
@neeraj-lad also there is a chat for that stuff btw
switch (val) {
case "bob":
answer="Marley";
break;
case 42:
answer="The Answer";
break;
case 1:
answer="There is a no #1";
break;
case 99:
answer="Missed me by this much!";
break;
case 7:
answer="Ate Nine";
break;
replacing if/if else...all tests pass except case 1,can anybody help me out?
case "bob":
answer="Marley";
break;
case 42:
answer="The Answer";
break;
case 1:
answer="There is a no #1";
break;
case 99:
answer="Missed me by this much!";
break;
case 7:
answer="Ate Nine";
break;
replacing if/if else...all tests pass except case 1,can anybody help me out?
@neeraj-lad ->https://gitter.im/FreeCodeCamp/HelpFrontEnd
@wearenotgroot thanks! but I was facing issues with Mixed content requests over chrome.
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@neeraj-lad yep chrome has stricter check than other browsers
@wearenotgroot how did you handle http access to open weather api, from codpen which is https? I found a workaround using background pages, but it seemed a bit complex.
@neeraj-lad what is the url you using
@lomu99 does what you're setting answer to exactly match what the challenge asks for?
@neeraj-lad link the codepen
@wearenotgroot accessing api using:
api.openweathermap.org/data/2.5/weather?lat=19&lon=73&appid=44db6a862fba0b067b1930da0d769e98
api.openweathermap.org/data/2.5/weather?lat=19&lon=73&appid=44db6a862fba0b067b1930da0d769e98
@neeraj-lad have you tried with http in front
@uriznik yes, i think so
@wearenotgroot yes.. didn't solve it. Tried https, but api call was unsuccessful
@neeraj-lad ok linked the project then
@neeraj-lad you can either try jsonp
@neeraj-lad
"http://api.openweathermap.org/data/2.5/weather?callback=?lat=" + Math.round(latitude) + "&lon=" + Math.round(longitude) + "&appid=44db6a862fba0b067b1930da0d769e98";
@neeraj-lad by adding
?callback=?
@wearenotgroot sorry.. didn't get that
@neeraj-lad look at that url and what you have right now
@wearenotgroot i need to add one more if statement in that exercise but again im returning the presult of the previous if statement...
@neeraj-lad this part
"http://api.openweathermap.org/data/2.5/weather?callback=?lat="vs
"http://api.openweathermap.org/data/2.5/weather?lat="
@neeraj-lad by adding the callback=? you are saying that the request is jsonp
@neeraj-lad that will solve your problem
@wearenotgroot I got this:
{"cod":"404","message":"Error: Not found city"}
@neeraj-lad yes beacuse it cannot find the location you are after
@lomu99 check down the bottom left for what each test expects
@neeraj-lad also remember there is a delay on the getCurrentPosition
@wearenotgroot I put the lat & lon values.. shouldn't it find the location then?
@neeraj-lad i see the problem
@neeraj-lad dont use Math.round
@wearenotgroot did you not face mixed content issues? I got them on firefox too.
@neeraj-lad it chopps off some decimal so it cant pin point exact where you are
@wearenotgroot maybe..
}
if ( firstName !== contacts.firstName ){
result = "No such contact";
}
else if (prop !== contacts[prop] ){
result = "No such property";
}
@neeraj-lad hmm working on my end
@neeraj-lad even without the callback=?
@wearenotgroot sorry?
@neeraj-lad only used this
var latitude = position.coords.latitude;
var longitude = position.coords.longitude;
openWeatherURL += "http://api.openweathermap.org/data/2.5/weather?lat=" + latitude + "&lon=" + longitude + "&appid=44db6a862fba0b067b1930da0d769e98";
@neeraj-lad and it work
@wearenotgroot yeah.. but adding 'callback=?' after 'weather?' doesn't work somehow
@wearenotgroot I guess, I'll try some other api then.. which offers https calls
@george-of-croton if you're looking for harry and the first contact is alice what happens?
@neeraj-lad ok try this
$(document).ready(function () {
var openWeatherURL = "";
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(function(position) {
console.log(position);
var latitude = position.coords.latitude;
var longitude = position.coords.longitude;
openWeatherURL = "http://api.openweathermap.org/data/2.5/weather?callback=?";
$.getJSON(openWeatherURL,{lat:latitude,lon:longitude, APPID:'44db6a862fba0b067b1930da0d769e98'}, function(json){
console.log(json);
var city = json["name"];
var country = json["sys"]["country"];
var location = city + ", " + country;
var weatherDesc = json["weather"][0]["description"];
var windSpeed = json["wind"]["speed"];
$(".location").html("<h3>" + location + "</h3>");
$(".weather-desc").html("<h3>" + weatherDesc + "</h3>");
$(".wind-speed").html("<h3>" + windSpeed + " meter/sec</h3>");
}); //end getJSON
}); //end navigator.geolocation if clause
}
}); //end document ready
@neeraj-lad you can add an object that contains the url parameter on the getJSON
@neeraj-lad instead of adding it to the url it self
@wearenotgroot didn't help :(
@neeraj-lad that way you can just add a base url which is much cleaner and gives you more controll
@uriznik it returns alice
@neeraj-lad it works even in firefox
@george-of-croton is that snippet in or outside the for loop?
@wearenotgroot strange.. it didn't work for me
@neeraj-lad what error you getting?
@uriznik outside
@neeraj-lad and did you allow the geolocate on you browser?
@wearenotgroot same one.. Mixed Content. Yes, I enabled it.
@neeraj-lad and you copied exactly the code above?
it should work, I just tried it
stupid question, do you have jquery embedded ?
@george-of-croton what happens if you look for harry and a property of 'pizza'?
@wearenotgroot yes, I replaced my js code with yours, saved it, and refreshed the page.
need help
@neeraj-lad i refeshing it and it havent change
@ it returns "no such contact"
@uriznik it returns "no such contact"
@george-of-croton can you paste the whole function
@wearenotgroot I undid the change, after it didn't work. I'll change it again now.
@wearenotgroot do you see the changed js code?
@neeraj-lad yep i see it
@neeraj-lad it works
function lookUp(firstName, prop){
for (var i = 0; i < contacts.length; i++){
if (firstName === contacts[i].firstName && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
}
if ( firstName !== contacts.firstName ){
result = "No such contact";
}
else if (!contacts.hasOwnProperty(prop) ){
result = "No such property";
}
return result;
// Only change code below this line
// Only change code above this line
}
// Change these values to test your function
lookUp("Harry", "address");
@wearenotgroot
Mixed Content: The page at 'https://s.codepen.io/neeraj-lad/fullpage/dGadyX?' was loaded over HTTPS, but requested an insecure script 'http://api.openweathermap.org/data/2.5/weather?callback=jQuery2130792804101…2002&lon=73.0437446&APPID=44db6a862fba0b067b1930da0d769e98&_=1455524804055'. This request has been blocked; the content must be served over HTTPS.
@neeraj-lad ok you are using https
@neeraj-lad change the http to be https then
@neeraj-lad same code but use https
@neeraj-lad
@neeraj-lad because the browser sees to different header info so that is why it is throwing this error
@wearenotgroot
this is my link:
codepen.io/neeraj-lad/full/dGadyX/
I tried http://codepen.io/neeraj-lad/full/dGadyX/ but it changes to codepen.io/neeraj-lad/full/dGadyX/
this is my link:
codepen.io/neeraj-lad/full/dGadyX/
I tried http://codepen.io/neeraj-lad/full/dGadyX/ but it changes to codepen.io/neeraj-lad/full/dGadyX/
@george-of-croton ok so you're looping through looking for harry and a prop 'pizza' and it goes through the loop - what happens next?
@neeraj-lad ok if it still persist
@neeraj-lad then add this to the url for the query
@neeraj-lad add this in front of the ---->openWeatherURL, this ----->https://crossorigin.me/
@neeraj-lad should look like this
openWeatherURL = "https://crossorigin.me/http://api.openweathermap.org/data/2.5/weather?callback=?";
@wearenotgroot Found the issue at last!
@neeraj-lad which was?
@uriznik the the code says if harry is not in the function return "no such contact"
@wearenotgroot I have https everywhere extension enabled. It might be changing http://codepen.io/neeraj-lad/full/dGadyX/ to codepen.io/neeraj-lad/full/dGadyX/
@wearenotgroot so silly of me!
@uriznik but harry is in the the function and i want i to run the else statement on pizza
@neeraj-lad :smile:
@wearenotgroot thanks a ton for your help! :D
neeraj-lad sends brownie points to @wearenotgroot :sparkles: :thumbsup: :sparkles:
:warning: neeraj-lad already gave wearenotgroot points
@neeraj-lad YW
@wearenotgroot
function palindrome(str) {
// Good luck!
var arr = [];
arr = str.split('');
arr.reverse();
revstr = arr.join('');
revstr = revstr.replace(/[,. ]/g, '').toLowerCase();
str = str.replace(/[,. ]/g, '').toLowerCase();
if(revstr === str){
return true;
}else{
return false;
}
}
palindrome("0_0 (: /-\ :) 0-0");this last string is failing
@SuhasHosamani yes
@SuhasHosamani here is the thing to consider----> most people doesnt know that underscore is considered an alphanummeric
@SuhasHosamani so you have to filter it out separately
@wearenotgroot how?
@SuhasHosamani another thing consider using \W <----------------- will take care of all non-word characters
@SuhasHosamani add _ in the regex
}
if ( firstName !== contacts.firstName ){
result = "No such contact";
}
else if (prop !== contacts.hasOwnProperty(prop) ){
result = "No such property";
}
@SuhasHosamani go practice ---->https://regex101.com/
@wearenotgroot :smile: :+1:
@george-of-croton hmm didnt we cover the second if last time?
@george-of-croton you only need to have return "No such contact" outside the loop and near the lass } of the function
@george-of-croton like that
function lookUp(firstName, prop){
for (var i = 0; i < contacts.length; i++){
if (firstName === contacts[i].firstName && (contacts[i].hasOwnProperty(prop))){
return contacts[i][prop];
}
else if (!contacts.hasOwnProperty(prop) ){
result = "No such property"; //<----------this part you can just return no such property immediately, return "No such property"
}
}
return "No such contact";
// Only change code above this line
}
@george-of-croton you can also replace an if(a == something && b = 4) { .. } with a nested if ( a ...) { if (b ...) {...} ... and it could make the code clearer
@wearenotgroot
revstr = revstr.replace(/[,._ ]/g, '').toLowerCase();
str = str.replace(/[,._ ]/g, '').toLowerCase();not working
@SuhasHosamani as I said try \W bcoz this will take care of any non-word characters.
[\W_]
@SuhasHosamani another thing is try to use toLowerCase then replace then split then reverse then join
@wearenotgroot oh ok i'l try
@wearenotgroot Bingo tat worked
@SuhasHosamani :+1:
@george-of-croton so how did it went?
please help !!
What I missing here?
Convert the switch statement into a lookup table called lookup. Use it to lookup val and assign the associated string to the result variable.
Convert the switch statement into a lookup table called lookup. Use it to lookup val and assign the associated string to the result variable.
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
var lookup = {
alpha: "Adams",
bravo: "Boston",
charlie: "Chicago",
delta: "Denver",
echo: "Easy",
foxtrot: "Frank"
};
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
@mossandboar Do you still need help with the testObj question?
@WebDevPr0 Try " " in names too like "alpha":"Adams"
and so on for bravo, charlie...
can anyone help me on arguments optiona;
l
?
' ' '
var count = 0;
function cc(card) {
// Only change code below this line
switch(card){
case 2:
count+=1;
return count + " Bet";
case 3:
count+=1;
return count+" Bet";
case 4:
count+=1;
return count+" Bet";
case 5:
count+=1;
return count+" Bet";
case 6:
count+=1;
return count+" Bet";
case 7:
count=0;
return count+"Bet";
case 8:
count=0;
return count+"Bet";
case 9:
count=0;
return count+" Bet";
case 'K':
count-=1;
return count+" Bet";
case 'J':
count-=1;
return count+" Bet";
case 'Q':
count-=1;
return count+" Bet";
case 'A':
count-=1;
return count+" Bet";
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
' ' '
@Yuvraj1989 u havn't used the break; statement anywhere
and please if you have similar cases don't repeat them.
@abhishekKumar1 I think if you are using return in function, you cannot use break;
hello @all
Abhishek Kumar
@abhishekKumar1