Get help on our basic JavaScript and Algorithms Challenges. If you are posting code that is large use Gist - https://gist.github.com/ paste the link here.
@johnlovespi Well first of all you're going to need to go through each contact so you'll need a loop to go through each number.
Does anybody else thinks that this code is a bit sexist :)
@dcnr thats right, I missed the .length,
This message was deleted
No that's not the right word
still not getting anywhere
@Finesse315 What the error message?
@dcnr but I still having a problem, because it is not getting the second argument. (I also set sum without the () but it does not make sense to me because I need a second parameter.
unsuspected token else
so something is wrong with the else statement
those don't usually take parentheses
so it's
if (something) {
} else {
}
you've also still got an extra semicolon
right at the start
that usually messes all kinds of things up
@dcnr btw I think we broke smt, cause now I am not able to run it when setting sum without ()
ok i see where i went wrong, gonna keep practicing the if else/if statements thx
I think is enough for me today, I let the current code in case someone can give me a hint on what I am doing wrong.
function add() {
var sum = 0;
function sumfirstand(x){
return function(y){
if(typeof y === "number"){
return x + y;
} else {return undefined;}
};
}
if(arguments.length == 1 && typeof arguments[0] == "number"){
sum = sumfirstand(arguments[0]);
return sum;
}else{
for(var i = 0; i < arguments.length; i++){
var type = typeof arguments[i];
if(type !== "number"){ return undefined;
} else { sum += arguments[i]; }
}
return sum;
}
}
add(2)(3);Tomorrow more, nn!
@Abel1987 that should be correct I think
@Abel1987
function add() {
var sum = 0;
function sumfirstand(x) {
return function (y) {
if (typeof y === "number") {
return x + y;
}
};
}
if (arguments.length === 1 && typeof arguments[0] == "number") {
sum = sumfirstand(arguments[0]);
return sum;
}
else {
for (var i = 0; i < arguments.length; i++) {
var type = typeof arguments[i];
if (type !== "number") {
return undefined;
}
else {
sum += arguments[i];
}
}
return sum;
}
}
@Abel1987 at least it's passing for me
Hey everyone
yowassup
Gah! Having trouble with instanceof for javascript. I read through the Details of the Object Model. I'm pretty familiar with Java and setting up the class with its constructors but for some reason on this Make a Person challenge I can't seem to get instanceof to return true. I left the structure of the function as is, simply split the string into an array and set up a multiple return statement to make my getter and setter functions. I'm not sure how to get it so the object type is of Person.
@sreeves89 hi will you post your current code?
function Person(firstAndLast) {
var nameArr = firstAndLast.split(" ");
return {
getFirstName : function() {
return nameArr[0];
},
getLastName : function() {
return nameArr[1];
},
getFullName : function() {
return nameArr[0] + " " + nameArr[1];
},
setFirstName : function(first) {
nameArr[0] = first;
},
setLastName : function(last) {
nameArr[1] = last;
},
setFullName : function(firstAndLast) {
nameArr = firstAndLast.split(" ");
}
};
};
var bob = new Person('Bob Ross');
bob.getFullName();
@sreeves89 is it necessary that they're all functions? Can't you just assign values?
@sreeves89 as a constructor function, you shouldn't return an object
hello everyone, do y'all know if you can seat a loop in another loop example:
not as explicit values but in terms of the inputs.
@sreeves89 you'd have to do
this.getFirstName = function() { ...
like
this.name = nameArr[0]
Hello, can i get a review of my js code here?
OK. Maybe I'm misunderstanding the instanceof test. That's the only test that fails, the rest pass. I'll try to change it to this. ...
what's the error you're getting?
while(blah<blue){
while(cat=green){
var blah = 35;
}
}
also, make sure it's not supposed to be
instanceOf() instead
@savrov Just post it here or in the CodeReview chatroom https://gitter.im/FreeCodeCamp/CodeReview.
bob instanceof Person should return true. <-- This test fails
Am I supposed to actually write an instanceof? Not certain what I'm really supposed to write in it.
@TylerMoeller thank you
savrov sends brownie points to @tylermoeller :sparkles: :thumbsup: :sparkles:
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OMG
why the ** does this give me false
@sreeves89 no, you shouldn't return an object but use
this.name = function() {} inside your constructor function. Or extend Person's prototype, but you'd fail the property count test
@0x0936 what did i do
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
console.log(contacts.hasOwnProperty("number"))
@RNwebdk because
contacts is an ARRAY
OK, by removing my return functions and switching to this.getFullName = function() ... the instanceof passed.
@RNwebdk Try this:
console.log(contacts[0].hasOwnProperty('number'));
array of objects
Guess I'm still a little hazy on how that turns it into a constructor function.
OMG thanks @dcnr and @TylerMoeller
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i hate when you keep looking at your code and try really hard, but still can't find the issue :P
@RNwebdk lol, that's why I'm here in chat
@RNwebdk whats up?
thanks for the help @dcnr and @pjconsidine
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@TylerMoeller your awesome, we need more people like you :D
@iheartkode was just a comment on my other post :) thx anyway for asking
@iheartkode was just a comment on my other post :) thx anyway for asking
rnwebdk sends brownie points to @tylermoeller and @iheartkode :sparkles: :thumbsup: :sparkles:
:warning: rnwebdk already gave tylermoeller points
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@RNwebdk haha ok
I need some codeing music, anyone with some cool list on youtube, soundcloud, twitch ect ?
@RNwebdk yes
3 hours
@iheartkode thx appreciate that :) 3 hours is more then enough ^^
rnwebdk sends brownie points to @iheartkode :sparkles: :thumbsup: :sparkles:
:warning: rnwebdk already gave iheartkode points
working on loops "Iterate Through an Array with a For Loop” specifically.
can someone explain to how the loop is doing its math?
var myArr = [ 2, 3, 4, 5, 6];
var total = 0;
for (var i = 0; i < myArr.length; i++){
total += myArr[i];
}adding the total its 20. If I were to do myArr[4] it equals to 30 myArr[3] = 25, myArr2 = 20, myArr1 = 15, myArr[0] = 10.
I want to know how its processing it.
@RNwebdk yw
@vtli94 remember to increment i++
ow you did
sorry
@vtli94 each iteration it counts up
right. what does that mean exactly?
its going 0,1,2,3,4
right?
it goes through each item in the array until its empty
@vtli94 yep
@iheartkode this is so peacefull, OMG i love it
@RNwebdk nice :)
@RNwebdk also on spotify they have a focus music section
just youtube focus music and you will be set lol
nice
so… if i input myArr[0] how did it get 10?
@vtli94 do you understand indexes in the array?
refresh me please
@vtli94 btw you can do that array look easier ill show
var arr = [1,2,3,4,5,6];
for(var i = 0; i < arr.length; i++) {
console.log(i);
}
that will output
0
1
2
3
4
5
if we changed it to var i = 1; it will be 12345
right. i understand that
indexes start at 0
@vtli94 You can always add console.log() to get more detail:
var myArr = [2, 3, 4, 5, 6];
var total = 0;
for (var i = 0; i < myArr.length; i++) {
console.log('iteration: ' + i + ' = ' + 'total + myArr[i]' + ' = ' + total + ' + ' + myArr[i] + ' = ' + (total + myArr[i]));
total += myArr[i];
}Output is:
iteration: 0 = total + myArr[i] = 0 + 2 = 2
iteration: 1 = total + myArr[i] = 2 + 3 = 5
iteration: 2 = total + myArr[i] = 5 + 4 = 9
iteration: 3 = total + myArr[i] = 9 + 5 = 14
iteration: 4 = total + myArr[i] = 14 + 6 = 20
@TylerMoeller great explanation
@TylerMoeller thanks
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hey
Happy to help with this :)
OK, so I'm on "return early pattern" and I've tried the code with abTest. It seems to be working but it won't let me pass.
if (a < 0 || b < 0) {
return "undefined";
}
return "undefined";
}
thanks @iheartkode @TylerMoeller
vtli94 sends brownie points to @iheartkode and @tylermoeller :sparkles: :thumbsup: :sparkles:
hello
hello
:star: 553 | @iheartkode | http://www.freecodecamp.com/iheartkode
:star: 403 | @tylermoeller | http://www.freecodecamp.com/tylermoeller
so how is the ‘total’ calculated?
hey @Mahin2k
oh nevermind i got it
im thinking too hard
@Valeriav521 hi
can someone help me with this?
who wants to chat like about whatever?
@vtli94 sometimes taking a break and breathing helps lol
function largestOfFour(arr) {
// You can do this!
var result = [];
for (var i = 0; i < arr.length; i++){
var largestNumber = 0;
for(var j=0; j < arr.length; j++){
if(largestNumber<arr[i][j]){
result=arr[i][j];
}
}
result.push(largestNumber);
}
return result;
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
can someone help?
t
t
😅 😅 😅 😅
its not recognizing push as a function
anyone wanna chat?
@Valeriav521 about?
about whatever
you need to ask about @someone!
okay @camperbot
yes need help with falsy bouncer @Valeriav521
what @gvik02
I'm stuck with it ! can you help me with this?
assignment
sorry challange
sure if i know i am kinda new at this
ha ha OK then
can someone help?
Oh, I wasn't supposed to literally put
return "undefined"; now I feel silly.
in what? @Mahin2k java or html?
Need help with falcy Bouncer can anyone help me !
@gvik02 what's your question?
lol
@KinichAjaw lol
Exactly my response! I was being too literal. XD
When do i use operater == and === ?
i understand the diffrence , but would it make sence to allways use === ?
i understand the diffrence , but would it make sence to allways use === ?
This message was deleted
@gvik02 no var test = "test" is assigning
not 2 ==
but when would it make sense to use the double instead of 3
someone help me
function largestOfFour(arr) {
// You can do this!
var result = [];
for (var i = 0; i < arr.length; i++){
var largestNumber = 0;
for(var j=0; j < arr.length; j++){
if(largestNumber<arr[i][j]){
result=arr[i][j];
}
}
result.push(largestNumber);
}
return result;
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
.push function is not being recognized
hey
@Mahin2k not sure, but i think result.push(largestNumber); is the problem here
again not sure
Math.max.apply() try this @Mahin2k
Hey fellas, a little help here
Stumped right now, trying to use the "lookup" object to find "val" and assign tghe associated string to the "result" variable
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
var lookup = {
"alpha": "Adams",
"bravo": "Boston",
"charlie": "Chicago",
"delta": "Denver",
"echo": "Easy",
"foxtrot": "Frank",
};
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
I already made the table
erm, object rather
@sethnejame what challenge is this?
@efhjones "Using Objects for Lookups"
try this lookup[val] @sethnejame
@gvik02 no dice :(
I changed the "alpha" to alpha
I think that helped
function myTest(val) {
// Only change code below this line
if (val > 10 || val < 20) {
return "Outside";
}
// Only change code above this line
return "Inside";
}
// Change this value to test
myTest(15);
of-course the val satisfies the if statement so it will return Outside @golfguy1984
use apha itself don't use the "" @sethnejame
right, did that
I need to assign the result to the lookup results somehow
i think
*the result variable
@gvik02 but if i change it to 25 it still returns outside
yes 25 is greater than 10 so
you need to rethink the if statement @golfguy1984
you can directly assign it @sethnejame
@gvik02 i tried this. . .
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
var lookup = {
alpha: "Adams",
bravo: "Boston",
charlie: "Chicago",
delta: "Denver",
echo: "Easy",
foxtrot: "Frank",
};
var result = lookup.val;
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
No dice
change it to lookup[val];
@sethnejame
what's that? the actual object or the result asssignment below
result assignment @sethnejame
oh wow
that worked
@gvik02 thanks!
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you are welcome
function factorialize(num) {
a = 1;
var val;
while(a <= num){
if (typeof num !== undefined) {
val = a * val;
a++;
return val;
}
else{
return a;
}
}
}
factorialize(5);
a = 1;
var val;
while(a <= num){
if (typeof num !== undefined) {
val = a * val;
a++;
return val;
}
else{
return a;
}
}
}
factorialize(5);
This is returning null and i dont see how.
just fyi, you might want to use var a instead of just a
you are also using val before giving it a value
Thank you. Now it doesn't recognize the val = a * val;
a++;
a++;
well ... did you give val a value ?
Yes, its set to a default of 1 at the top.
```
Where is the thumbs up button?
no thumbs up ... just say @username thanks ...
bitgrower sends brownie points to @username :sparkles: :thumbsup: :sparkles:
:warning: could not find receiver for username
```
ar contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}];
function lookUp(firstName, prop){
// Only change code below this line
for(var i = 0; i < contacts.length; i++){
if(contacts[i].firstName === firstName &&
contacts[i].hasOwnProperty(prop) === true)
{
return contacts[i][prop];
}
else if (contacts[i].firstName !== firstName){
return "No such contact";
}
return "No such property";
}
// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "address");
```
@cfj2 -- if both a & val are 1 -- your code isn't going to go thru your while loop
I am profile lookup
it keeps returning t
that there is no such property on the test one
so follow your code thru ... step thru it, @asaki444 ...
it looks at the first contact ... looks to see if the first contact has name "Akira' AND has the property "address" ... it doesn't ... so what will it do next ?
@bitgrower I dont understand. 1 is less then num. Did I mis enter the paramaters?
you said val is now 1 ... and a is now 1 ...is that correct?
@bitgrower it did do what it was supposed to do for that. I forgot I changed the test one. I ran lookUp("Sherlock", "likes"), and it said there was no such contact
Yes.
so look at your while loop ...
@asaki444 -- so follow your code ... step thru your code & see what it's doing ... use this site to help you pythontutor.com/javascript.html
This message was deleted
Why is this failing?
Encode the following sequence, separated by spaces:
backslash tab tab carriage-return new-line and assign it to myStr
var myStr = "\b \t \t \r \n"; // Change this line
i see it backslash not backspace
@cfj2 -- you are returning right away ...
I tried switching the if and while paramaters but still no.
post your current code ?
function factorialize(num) {
var a = 1;
var val=1;
while(typeof num !== undefined){
if (a <= num) {
val = a * val;
a++;
return val;
}
else{
return a;
}
}
}
factorialize(5);
var a = 1;
var val=1;
while(typeof num !== undefined){
if (a <= num) {
val = a * val;
a++;
return val;
}
else{
return a;
}
}
}
factorialize(5);
btw -- you can get cool syntax coloring & things if you use this ...
explain formatting
:point_right: code formatting [wiki]
Multi line Code
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
Single line Code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
so @cfj2
if ( a <= num) <--- 1 < 5 ... yes
val = a val; <--- 11 = 1
a++ <--- a is now 2
then you return val, which is 1 ...
you might want to look around at the various algos for coding factorial -- there are TONS of them around the web ...
...it's also a GREAT problem for getting exposed to using recursion ... because it's very clean & straightforward ... and recursion is something you'll want to at least get exposed to using ...
@bitgrower I am still not getting it... why doesnt it stop at i = 0 for the matchup?
I don't understand your question @asaki444
@bitgrower Thankyou. I will go ponder this.
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < multiplyAll.length; i++)
{
for (var j=0; j < multiplyAll[i].length; j++)
{
console.log(multiplyAll[i]*[j]);
}
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
How much did I screw that up?
@cfj2 -- you can use a loop -- but right now you are only going thru your loop one time and returning ... which isn't quite what you want ... so you probably don't want to use return in the loop ... because that takes you right out of your function ...
@grrttmrtn -- are you trying to ? :)
first you might want to use the length of arr instead of the length of multiplyAll (the function)
Ahh yeah...I started with that and stupidly came back and posted it with the function lol
But anyways, it still doesn't work
bitgrower @bitgrower re-programs @camperbot to recognize thank you
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er ... that is .. thankyou @camperbot
@grrttmrtn -- I know, that's why I said "first" ...
wanna try posting your revised code with cool syntax coloring ? Just follow the below instructions ...
explain format
:point_right: code formatting [wiki]
Multi line Code
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
Single line Code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
'function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < product.length; i++)
{
for (var j=0; j < product[i].length; j++)
{
console.log(product[i]*[j]);
}
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);'
Still messed up the formatting. One sec
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < product.length; i++)
{
for (var j=0; j < product[i].length; j++)
{
console.log(product[i]*[j]);
}
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);:bulb: to format code use backticks! ``` more info
you can edit the same message rather than re-posting ... and the backticks are the character to the left of the # 1 key on most keyboards
and ... product isn't an array ... so product.length is kinda meaningless ... you mean arr ?
@bitgrower on the link that you sent it would only compare the parameters against i = 0. Why is that?
Okay, I changed lengths to arr and left console.log(product[i][j] still having issues with that
okay ... your loops are still using product.length -- which isn't even valid because numbers do not have length properties, as far as I know ...
@asaki444 -- you'll have to be a whole lot more specific ... I'm sorry ...
@asaki444 -- are you referring to pythontutor.com/javascript.html ?
:point_up: March 3, 2016 6:53 PM @grrttmrtn
@bitgrower yes that shite
site*
you can edit your messages, @asaki444 -- just mouse over to the right, and just to the right of the time 3 dots will show up when you hover over them ... right click, you'll get a context menu, from which you can choose "edit" :)
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < arr.length; i++)
{
for (var j=0; j < arr[i].length; j++)
{
console.log(arr[i]*[j]);
}
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
@bitgrower thanks for the tip
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@asaki -- it doesn't go past i= 0 because your code returns before it iterates to the next number ...
@grrttmrtn -- alright ... now we're starting to cook on all burners ... :)
@bitgrower oh! so i should use console.log instead?
LOL ... @asaki444 -- depends on what you're trying to do ...
Typically I've been doing alright with JS...this and the profile lookup are my last ones left, but this is way over my head
@bitgrower trying to run the loop to find the match
nah ... just a little mental adjustment and you'll be thinking ... "that's all that that was??? pfftttt....let me at the next challenge..."
console log is only going be what it reads out
it isn't going to fix your loop
@asaki444 -- console.log is for debugging ... and what @grrttmrtn said ... it's not going to fix your loop ...
so @grrttmrtn .... you know how to address an element of an array, right ?
yup, I want to use dot notation
Sorry dot notation would be arr.whatever
but anyways yes arrary[0-X]
@grrttmrtn -- . notation is for objects ... this is for an array ...
so myArray = [1,2,3]; -- how do I address, point to, access, the number 3 ?
myArray[2]
awesome ...
now ... what if I had
myArray = [ [1,2,3], [2,3,4],[5,6,7]];
what would myArray[2] be equal to ?
[5,6,7]
excellent !!!!
so, if I wanted to address the number 6, how would I do it ?
myArray[2][1]?
YUP!!!!!
so ... let's go back a few lessons ...
you remember learning about i++;
?
Yup that's incrementing i in the for loop
okay, most commonly ... but I could do something like
product++; as well ...
@uCtrlr still here
now ... do you remember this syntax:
myNum += 1;
myNum = myNum +1
yup
so ... if I have a loop like this ...
var num = 3;
j = 0;
for (i = 0; i < num; i++) {
j += 1;
}
what is j going to equal at the end ?
J = 3
cool ...
what if I said
j *= i;
instead ?
if you don't have a for loop in profile lookup, you definitely need one
help with profile lookup
no wiki entry for:
with profile lookup
@bitgrower I am still stuck on this problem
anyone!
helo frnds.. I'm trying to truncate a string
oops, let me change that around @grrttmrtn start j = 1 instead of 0
but not getting it completely
j would equal 4
function truncate(str, num) {
// Clear out that junk in your trunk
var trunk = '';
if (str.length > num) {
trunk = str.slice(0, num - 3) + '...';
return trunk;
}
return str;
}
this is what i have used
can anyone help me?
@grrttmrtn -- what if I changed the inner loop to do this instead, @grrttmrtn ...
j *= i;
profile look up
it didnt do anything
@keerthinerella ..... look carefully at the instructions ...
@keerthinerella There's another rule you're missing
is that I'm missing in using slice() function>
?
@glenohumeral13 ... describe the data structure in profile lookup ?
working on tic tac toe... can anyone give me a clue about how to put removeEventListener on divs after they've been clicked? http://codepen.io/weedmark/pen/JXdPVr?editors=1111
@bitgrower its a nested object. but idk how to access anything.
@keerthinerella You've solved the main part of the problem. There's a special case to handle though
@glenohumeral13 -- what is the first character after the equal sign in the data structure definition
@bitgrower like are the curly bracket pieces accessed by array bracket notation or what
@bitgrower what
@bitgrower if j=1 adding that to the loop j = 2 if inner loop j *= i
look carefully at the data structure definition ... what is the first character after the equal sign on the 2nd line
so ... if I have a loop like this ...
var num = 3;
j = 2;
for (i = 0; i < num; i++) {
j *= 1;
}
var num = 3;
j = 2;
for (i = 0; i < num; i++) {
j *= 1;
}
@grrttmrtn yeah I've got that page practically memorized thanks
davidweedmark sends brownie points to @grrttmrtn :sparkles: :thumbsup: :sparkles:
:star: 258 | @grrttmrtn | http://www.freecodecamp.com/grrttmrtn
@glenohumeral13 thanx, question tho in like 33 -- && contacts[i][prop]
why is prop in []
@bitgrower but is the one thing one big array? or can i access the individual curly brackets with contacts[prop]?
I'm hoping not to repeat the same code for each of eight instances I'll need it.
@johnlovespi wouldnt that be how i access a property's value?
@glenohumeral13 -- YES ... it is ... a big (well, not too many element) array -- of ... OBJECTS ...
@glenohumeral13 -- so the first thing you must do is address WHICH element of the array ... :)
@glenohumeral13 i mean i guess im confused on that as well
all look it to it
@bitgrower but isnt there only one element? because everything is in contacts[0] ?
@glenohumeral13 -- no ... there are 4 or 5 elements in the array ... (I forget which, think it's 4)
yeah..got it :smile:
each element in the array is an object, though ...
remember ... an array can contain ANYTHING ... objects, subarrays, numbers, booleans ... etc
this one contains objects .
the elements of the array, the different objects, are separated by commas ...
so you have [ {...}, {...}, {...}, {...}]
for anyone looking at my page, I would have thought something like this would work
this.removeEventListener("click");
above my paygrade, @DavidWeedmark
@grrttmrtn
@bitgrower while that blows my mind, I appreciate you taking a look. thanks! I'll figure it out I'm sure
davidweedmark sends brownie points to @bitgrower :sparkles: :thumbsup: :sparkles:
:star: 707 | @bitgrower | http://www.freecodecamp.com/bitgrower
so ... if I have a loop like this ...
var num = 3;
j = 2;
for (i = 0; i < num; i++) {
j *= 1;
}
now what would j be equal do ...
and the easiest way to do this is to list out each loop iteration and what j equals at the end of that iteration ...
@DavidWeedmark -- just haven't gotten to that corner of js ...
j would be equal to 2
@DavidWeedmark from the doc it looks like you need to call your function after "click", "function name"
good one ... @mgsakata ... and once again I messed up my example !!! LOL ... let me try again ...
var num = 3;
j = 2;
for (i = 0; i < num; i++) {
j *= i;
}
@bitgrower totally understanding your examples then looking at this with an empty mind :facepalm
@glenohumeral13 hey does your code word
work
@johnlovespi no sorry
@bitgrower j = 4
ok
@bitgrower lol. That new sample makes it a much more interesting question :)
@grrttmrtn -- you have a couple of different pieces I'm building up, @grrttmrtn ...
oh nuts let me try that again ...actually, it would be zero
@grrttmrtn I actually had that at the bottom and moved it after the last unsuccessful test to see if it would help. guess what... it didn't! lol
var num = 3;
j = 2;
for (i = 1; i < num; i++) {
j *= i;
}
@bitgrower wouldn't it equal 4 because i counts up until 2 because it's looking to be less than 3 in that last example?
`so ... first time thru the loop it will be j = j * 1
so j will be 2
next time thru the loop it will be j = j * 2
oh damn
I skipped the first couple of loops lol
and jumped right to two ha
that's alright ... it's a very human tendency ... we want to jump ahead ... and the computer just plods along ... we have to slow down and think like the computer ... 4
but in your second one j = 4
yes !!! excellent ...
now ... you have to multiply all the elements of your 2-D array ... you know how to address each element, you know how to accumulate a product ... "just" put them together to solve the challenge .. :)
see if you can take the pieces we've built up and plug them into the nesting for loops challenge ...
@glenohumeral13 ... (you've got me all kinds of curious about your nickname, reminds me of my A&P classes) ... how ya doin' ?
@bitgrower lol it was my favorite joint in the skeletal unit of A&P. still confused
@bitgrower and the 13 is my fav #
LOL I never had a favorite joint ... are you an orthopod or something ? exercise physio guy ?
bitgrower @bitgrower thinks @glenohumeral13 should open a beer "joint" ...
@bitgrower no just nerd
so ... have you played around with addressing the objects in your array ?
@bitgrower thank you!
grrttmrtn sends brownie points to @bitgrower :sparkles: :thumbsup: :sparkles:
:star: 708 | @bitgrower | http://www.freecodecamp.com/bitgrower
@bitgrower do you work for fcc, or do you just do this for fun?
you figure it out, @grrttmrtn ?!?
fun ...
Finally ha
@bitgrower ive been trying to but im not fully getting it
I think FCC is all volunteer ...
@grrttmrtn -- you did really good -- I've seen people struggle much, much more with that ... which is why I built it up the way I did ... I was pretty sure you had the knowledge from previous challenges ... so, I was just reminding you of it ... so you could access it and put the right puzzle pieces together ...
@glenohumeral13 ... gonna call you joint nerd ... LOL ... can you post your code again ?
knock knock :door:
hey there @abhisekp -- ain't seen you in a while ... where ya been ?
@bitgrower FCC main channel :P
hmmm oh yeah, guess I don't have that one open ...
better
better ?
@bitgrower Helping people is better here
Coding vs Chatting bla bla bla
yeah ... sometimes ...
@glenohumeral13
hey
got the answea
it makes snence
so ... @glenohumeral13 you've got to use contacts[i]<something>
so you index into your array ... (of objects)
@bitgrower like with a for loop?
help format
:point_right: code formatting [wiki]
Multi line Code
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
Single line Code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
yup
@bitgrower like with
contacts[i][prop] ?
you're already using a for loop I see ...
bc it didnt work last time
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (firstName == contacts.firstName && prop == contacts.i) {
return contacts[prop];
} else if (firstName !== contacts.firstName) {
return "No such contact";
} else if (prop !== contacts.prop) {
return "No such property";
}
}
// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "likes");@glenohumeral13 ... well ... I think the first thing you need to do is look for a firstname, no ?
And how did you use contacts[i][prop] ?
@bitgrower i did before and it didnt work. like this:
@bitgrower I don't know about you but I feel like I see this almost every time I get on here :)
so ... you're iterating thru the loop in your loop statement, but you are not using the indexing available to you ...
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (firstName == contacts.firstName && prop == contacts[i][prop]) {
return contacts[prop];
} else if (firstName !== contacts.firstName) {
return "No such contact";
} else if (prop !== contacts.prop) {
return "No such property";
}
}
// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "likes");
lol @gloriousjob -- there are some challenges that come up a lot ...
@glenohumeral13 -- where are you using contacts[i] please ?
@bitgrower yeah idk what im "indexing" (is that just running through a for loop?). is contacts[0] the bit about akira laine? or all the four objects?
ahh ... just once .. you have to use it everywhere within the loop ...
@bitgrower why?
contacts[0] is this ...
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
}
@glenohumeral13 Think of it like this: var arr = [3, 5, 7, 9]. To get 5, you'd do arr1.
because you have to use it to point to the right element in the array ...
@gloriousjob ahh i see
But you'd have to do that every time
arr[1]
ok so i have this which isnt working ```
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (firstName == contacts.firstName && prop == contacts[i].prop) {
return contacts[i].prop;
} else if (firstName !== contacts.firstName) {
return "No such contact";
} else if (prop !== contacts[i].prop) {
return "No such property";
}
}
// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "likes");
```
think of each element (each object) as a room ... the index opens the door to THAT room ...
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (firstName == contacts.firstName && prop == contacts[i].prop) {
return contacts[i].prop;
} else if (firstName !== contacts.firstName) {
return "No such contact";
} else if (prop !== contacts[i].prop) {
return "No such property";
}
}
// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "likes");
@glenohumeral13 -- you can edit your message ... you need to put the backticks on lines of their own
oops ... you did it ...
change this
if (firstName == contacts.firstName && prop == contacts[i].prop) {
to this ` if (firstName == contacts[i].firstName && prop == contacts[i].prop) {
and so on ... wherever you are using contacts within the loop (below the loop iteration definition .. you need to use contacts[i]
@bitgrower but that doesnt work either
@glenohumeral13 Well, it should get you closer
@glenohumeral13 There's another thing but make sure you understand how this works first. It's key to understanding loops
@gloriousjob idk. my current understanding is that i am using a for loop to run through each object in the array. contacts[i].firstName is the value of the firstName property of each object in the array, where "i" is a number being incremented by the for loop. contacts[i].prop SHOULD be any property that the "prop" variable stands for
if I have
retArr = [];
myArr = [1,2,3];
for (var i = 0; i < myArr.length; i++) {
retArr.push(myArr[i]);
}do you know what this does?
do you know what retArr will contain after the loop finishes running ...
@bitgrower yeah youre running through the myArr array with i and pushing the indexed array value into retArr. at the end retArr will be
[1, 2, 3]
wiki Sum All Primes
:point_right: algorithm sum all primes [wiki]
Explanation:
The explanation for this problem is very simple. You will generate a list of prime numbers up to the number you are given as a parameter. Then you need to add them all up and return that value. The tricky part is on generating the list of prime numbers. I suggest you find a code or a good math algorithm that you can turn into code.
:pencil: read more about algorithm sum all primes on the FCC Wiki
excellent!!!!
This message was deleted
This message was deleted
should i golf it
This message was deleted
??
Help needed With Exact Change Challenge - It's late, I'm tired, maybe I am overlooking something obvious.
I am getting the right answers for the change but not as 2 decimal places. (ie - ["DIME", 0.2], ["QUARTER", 0.5], ["ONE", 1], etc - instead of ["DIME", 0.20], ["QUARTER", 0.50], ["ONE", 1.00]). I can use toFixed(2) to force 2 decimals but then it converts to a string and that is not accepted as the right answer either. Converting back to a number loses the decimal places again. I am stumped. How do I force a number to be 2 decimal places without converting it to a string?
I am getting the right answers for the change but not as 2 decimal places. (ie - ["DIME", 0.2], ["QUARTER", 0.5], ["ONE", 1], etc - instead of ["DIME", 0.20], ["QUARTER", 0.50], ["ONE", 1.00]). I can use toFixed(2) to force 2 decimals but then it converts to a string and that is not accepted as the right answer either. Converting back to a number loses the decimal places again. I am stumped. How do I force a number to be 2 decimal places without converting it to a string?
no wiki entry for:
needed with exact change challenge - its late im tired maybe i am overlooking something obviousi am getting the right answers for the change but not as 2 decimal places ie - dime 02 quarter 05 one 1 etc - instead of dime 020 quarter 050 one 100 i can use tofixed2 to force 2 decimals but then it converts to a string and that is not accepted as the right answer either converting back to a number loses the decimal places again i am stumped how do i force a number to be 2 decimal places without converting it to a string
@bitgrower what was gonna be your next example?
@martensclass That doesn't matter
Don't use toFixed(2) as that will convert it to a string
0.5 === 0.50 so no worries
@glenohumeral13 -- if you have an array ... assume each element of the array is a room ... the room can contain anything ... but in order to get to anything within the room, you still have to access it by the array index ...
...so, if the element is an object ... then you need to use the array indexing followed by your object addressing ...
your object address can be either dot or bracket ...
if you know the name, and the name is appropriate ... you can use the dot notation ...
contacts[i].firstname
help Record Collection
:point_right: checkpoint record collection [wiki]
Checkpoint: Record Collection
Instructions
You are given a JSON object representing (a small part of) your record collection. Each album is identified by a unique id number and has several properties. Not all albums have complete information.
Write a function which takes an id, a property (prop), and a value.
For the given id in collection:
If value is non-blank (value !== ""), then update or set the value for the prop.
If the prop is "tracks" and value is non-blank, push the value onto the end of the tracks array.
If value is blank, delete that prop.
Always return the entire collection object.
Remember to use Read-Search-Ask if you get stuck. Try to pair program. Write your own code.
:pencil: read more about checkpoint record collection on the FCC Wiki
or if it's a property named in a variable, then you will use bracket notation
contacts[i][prop]
wiki Sum All Odd Fibonacci Numbers
:point_right: algorithm sum all odd fibonacci numbers [wiki]
Explanation:
You will need to gather all the Fibonacci numbers and then check for the odd ones. Once you get the odd ones then you will add them all. The last number should be the number given as a parameter if it actually happens to be an off Fibonacci number.
:pencil: read more about algorithm sum all odd fibonacci numbers on the FCC Wiki
@bitgrower i have this but it isnt working
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (firstName == contacts[i].firstName && prop == contacts[i][prop]) {
return contacts[i].prop;
} else if (firstName !== contacts[i].firstName) {
return "No such contact";
} else if (prop !== contacts[i][prop]) {
return "No such property";
}
}
// Only change code above this line
}
// Change these values to test your function
lookUp("Akira", "likes");
just fyi, it's generally a good idea to use the triple equals ==> === sign instead of the double == sign
@bitgrower yeah i had that originally but i scrapped it in case it was causing the problems
wiki Steamroller
:point_right: algorithm steamroller [wiki]
Explanation:
This problem seems simple but you need to make sure to flatten any array, regardless of the level which is what adds a bit of difficulty to the problem.
:pencil: read more about algorithm steamroller on the FCC Wiki
anyway .. let's take a look ...
firstName is "Akira" ... so you look at contacts[i].firstName ... and yes, it's Akira ... but then we have to see if this particular object has a property "likes" ... it doesn't ... so it goes to your ELSE statement ...
well ... we already know that firstName === contacts[i].firstName, so it skips that ...
however ... it looks to see if prop !== contacts[i][prop] (which we already determined before, btw)
...and it doesn't ... so it returns "No such property"
since you are returning from the function, you don't look at any of the other objects in your array ...
if you want to do so, you shouldn't return from the loop
wiki smallest common multiple
:point_right: algorithm smallest common multiple [wiki]
Explanation:
The smallest common multiple between two numbers is the smallest number that
both numbers can divide into. This concept can be extended to more than two
numbers as well.
We can first start with just finding the smallest common multiple between two
numbers. Naively, you can start writing out multiple of each number until you
write a multiple that exists from both numbers.
An example would be the numbers 3 and 4. The multiples of 3 are 3, 6, 9,
12, 15, 18, ... and the multiples of 4 are 4, 8, 12, 16, 20, .... The
first smallest number we run into in both lists is 12 so this is the smallest
common multiple between 3 and 4.
This problem can be confusing because most people look for the smallest common
multiple of just the two numbers but forget the keyword range. However, this
means that if you are given [1,5], then you have to check for the smallest
common multiple for all the numbers [1,2,3,4,5] that is evenly divisible by
all of them.
:pencil: read more about algorithm smallest common multiple on the FCC Wiki
it's important ... what @gloriousjob said ... you need to understand what the code is doing ...
you can put your code in here: pythontutor.com/javascript.html ... and see a cool visualization of what is happening in your code ...
(although I had someone vociferously complain that pythontutor.com was wrong on one of his pieces of code...unfortunately, he was wrong ... )
Hi all! I just finished Title Case a Sentence. This is my solusion
This message was deleted
Hey @PoisonHawk -- generally not a good idea to post solutions in here .. use the codereview room ... but it looks like an interesting solution !!!
help rooms
:point_right: help rooms [wiki]
Help Rooms
- HTML/CSS/Bootstrap -
[FreeCodeCamp/Help] - JavaScript/Algorithms -
[FreeCodeCamp/HelpJavaScript] - Front End -
[FreeCodeCamp/HelpFrontEnd] - Data Visualization -
[FreeCodeCamp/HelpDataViz] - Back End -
[FreeCodeCamp/HelpBackEnd] - Python -
[FreeCodeCamp/Python] - Java -
[FreeCodeCamp/Java] - Go -
[FreeCodeCamp/Go] - Ruby -
[FreeCodeCamp/Ruby] - PHP -
[FreeCodeCamp/PHP] - Elixir -
[FreeCodeCamp/Elixir] - Linux -
[FreeCodeCamp/Linux] - SQL and Relational Databases -
[FreeCodeCamp/SQL] - Non-profit Projects -
[FreeCodeCamp/NonprofitProjects] - Code Review -
[FreeCodeCamp/CodeReview] - You Can Do This -
[FreeCodeCamp/YouCanDoThis]
:pencil: read more about help rooms on the FCC Wiki
function queue(arr, item) {
// Your code here
return arr; // Change this line
}
// Test Setup
var testArr = [1,2,3,4,5];
// Display Code
console.log("Before: " + JSON.stringify(testArr));
console.log(queue(testArr1, 6)); // Modify this line to test
console.log("After: " + JSON.stringify(testArr));
what shoud i do?
i just want ask how make better this solution, but i cannot normally show code)
@rexChip -- you need to use 2 array functions ... here are some you can choose from ... shift, unshift, pop, push ... 2 of them will be used in solving the problem ... BUT you will need to know how to use them correctly ... when you do, it's a simple solution ...
yeah, I understand, @PoisonHawk -- that's why there's a CodeReview room :)
@bitgrower ok)
@bitgrower thanks , but i don't know why to use ... where i can use 2 array function
rexchip sends brownie points to @bitgrower :sparkles: :thumbsup: :sparkles:
:star: 709 | @bitgrower | http://www.freecodecamp.com/bitgrower
you have an array, you want to add an item to the array, and then you want to remove (and return) an item from the array (different item) ...
Probably enqueue with pop or dequeue with push
Or you can use filter
help Record Collection
:point_right: checkpoint record collection [wiki]
Checkpoint: Record Collection
Instructions
You are given a JSON object representing (a small part of) your record collection. Each album is identified by a unique id number and has several properties. Not all albums have complete information.
Write a function which takes an id, a property (prop), and a value.
For the given id in collection:
If value is non-blank (value !== ""), then update or set the value for the prop.
If the prop is "tracks" and value is non-blank, push the value onto the end of the tracks array.
If value is blank, delete that prop.
Always return the entire collection object.
Remember to use Read-Search-Ask if you get stuck. Try to pair program. Write your own code.
:pencil: read more about checkpoint record collection on the FCC Wiki
hi, How I can format a code in a black square
help format
:point_right: code formatting [wiki]
Multi line Code
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
Single line Code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
hello everyone!!! :)
Heyyy
hello
Hello
I am wondering why the two codes below giving different result:
First code:
function convert(num) {
var str = "";
var tmp;
tmp = Math.floor(num/1000);
for(i=0;i<tmp;i++)
str += "M";
tmp = Math.floor((num%1000)/100);
if(tmp === 9)
str += "CM";
else if(tmp >= 5) {
str += "D";
for(i=0;i<tmp-5;i++)
str += "C";
}
else if(tmp === 4)
str += "CD";
else if(tmp < 4) {
for(i=0;i<tmp;i++)
str += "C";
}
tmp = Math.floor((num%100)/10);
if(tmp === 9)
str += "XC";
else if(tmp >= 5) {
str += "L";
for(i=0;i<tmp-5;i++)
str += "X";
}
else if(tmp === 4)
str += "XL";
else if(tmp < 4) {
for(i=0;i<tmp;i++)
str += "X";
}
tmp = num%10;
if(tmp === 9)
str += "IX";
else if(tmp >= 5) {
str += "V";
for(i=0;i<tmp-5;i++)
str += "I";
}
else if(tmp === 4)
str += "IV";
else if(tmp < 4) {
for(i=0;i<tmp;i++)
str += "I";
}
return str;
}
convert(3999);
after not messing with java script for a few day, i have become slightly rusty.
Second code:
function convert(num) {
var str = "";
var tmp;
tmp = Math.floor(num/1000);
for(i=0;i<tmp;i++)
str += "M";
tmp = Math.floor((num%1000)/100);
if(tmp === 9)
str += "CM";
else if(tmp >= 5) {
str += "D";
for(i=0;i<tmp-5;i++)
str += "C";
}
else if(tmp === 4)
str += "CD";
else if(tmp < 4)
for(i=0;i<tmp;i++)
str += "C";
tmp = Math.floor((num%100)/10);
if(tmp === 9)
str += "XC";
else if(tmp >= 5) {
str += "L";
for(i=0;i<tmp-5;i++)
str += "X";
}
else if(tmp === 4)
str += "XL";
else if(tmp < 4) {
for(i=0;i<tmp;i++)
str += "X";
}
tmp = num%10;
if(tmp === 9)
str += "IX";
else if(tmp >= 5) {
str += "V";
for(i=0;i<tmp-5;i++)
str += "I";
}
else if(tmp === 4)
str += "IV";
else if(tmp < 4) {
for(i=0;i<tmp;i++)
str += "I";
}
return str;
}
convert(3999);
notice that the only diffrence that I have removed the brackets from the below:
else if(tmp < 4)
for(i=0;i<tmp;i++)
str += "C";
@mukhtar2t :point_right:
FreeCodeCamp/CodeReview for Code Review after completion
@mukhtar2t my guess would be that by removing the brackets, Javascript is inferring there is a ; at the line break, which it sometimes does when a needed ; is missing
help Return Early Pattern for Functions
:point_right: challenge return early pattern for functions [wiki]
Challenge: Return Early Pattern for Functions
When a return statement is reached, the execution of the current function stops and control returns to the calling location.
Example
function myFun() {
console.log("Hello");
return "World";
console.log("byebye")
}
myFun();The above outputs "Hello" to the console, returns "World", but "byebye" is never output, because the function exits at the return statement.
:pencil: read more about challenge return early pattern for functions on the FCC Wiki
Could anyone help me with that challenge? can't seem to understand it
@Cyberistic which part exactly?
@DavidWeedmark I don't really know what to do.
@DavidWeedmark thanks for your point
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thanks @abhisekp
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@Cyberistic okay well you want to specify if a is less than zero or b is less than zero that the console replies with undefined, right?
@DavidWeedmark Yes
so those are the three things to focus on
return a < 0 || b < 0;
is what I did
is what I did
close
To be honest, I don't understand the whole undefined thing
you just tell it "return undefined"
mhm..?
if a < 0 || b < 0, then "return undefined"
Am I allowed to use if statements?
if you type nothing but "return undefined" the console will respond with "undefined"
oh yeah, you need that for this
Ahh okay
return is like saying "console.log"
let me know if you get it. I'll be around for another 20 mins or so
I completed the challenge
could use some help on filtering out on my array. Basically it is only filtering out my first i value argument when I want it to go through my for loop and filter all of the arguments. I believe it has something to do with the
return value !== args[i];function destroyer(arr) {
// Remove all the values
var args = Array.prototype.slice.call(arguments);
var filtered;
filtered = arr.filter(function destroy(value) {
for (var i = 1; i < args.length; i++) {
return value !== args[i];
}
});
return filtered;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
but I still don't get it
@Cyberistic ah, great!
in this case "undefined" is just a word. you could say "return pickles" or "return abc" and it would give you back those instead
Erhhh
I think the focus of this one is to get you used to "return" which you will be using a lot now
What does return exactly do
here, it just tells the browser to return something back to you in the console, much like console.log does
@DavidWeedmark I will do some research later, Thanks for the help though.
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Could someone help me with the Drop it challenge? I pass all but one test.
function drop(arr, func) {
// Drop them elements.
for (var i = 0; i <= arr.length; i++) {
if (func(arr[0])) {
break;
} else {
arr.shift();
}
}
return arr;
}
drop([1, 2, 3, 4], function(n) {return n > 5; });
i have a peice of code thats acting really weird. in my second if statement i have it calling data.stream.preview.small.. that part is doing its job correct but its making any of the offline stream be removed from the list. cannot figure out why. http://codepen.io/andrewchar/pen/bpdLGv?editors=1011
if i console.log before the if statement, everything comes back as normal. if i console.log after the if statement. it only shows the streams that are online
@doudeman I think you want to return arr instead of the break
but i cant see any errors with the code
@doudeman Are you supposed to use 0 instead of the index?
@gloriousjob The idea is that the array gets smaller with each shift so I keep checking the first element
@doudeman You should probably use a while instead of a for because that's a bit confusing but anyway...
@doudeman which case fails?
@DavidWeedmark That gives me the same answer
@gloriousjob drop([1, 2, 3, 4], function(n) {return n > 5;}) should return []. I'm getting an array with [4]
@doudeman Funny, I was going to ask what happens when the whole array is dropped
@doudeman its giving you 3,4 instead of []?
@doudeman You might want to consider your exit conditional
@doudeman in the for loop
help stand
:point_right: challenge understand boolean values [wiki]
Understand Boolean Values
Booleans can only hold the value of either true or false. They are basically little on-off switches.
:pencil: read more about challenge understand boolean values on the FCC Wiki
help stand in line
:point_right: checkpoint stand in line [wiki]
Checkpoint: Stand In Line
About queues
In Computer Science a queue is an abstract Data Structure where items are kept in order. New items can be added at the back of the queue and old items are taken off from the front of the queue.
Instructions
Write a function queue which takes an "array" and an "item" as arguments.
Add the item onto the end of the array, then remove the first element of the array.
The queue function should return the element that was removed.
Remember to use Read-Search-Ask if you get stuck. Try to pair program. Write your own code.
:pencil: read more about checkpoint stand in line on the FCC Wiki
@gloriousjob the break?
@doudeman Yes, and also what your exit criteria is before the break
@doudeman exit of the for loop, that is
@doudeman Consider what your for loop does if I give it arr = []
@gloriousjob Ah! That makes sense. Hmmm
Can someone explain to me why this is wrong?:
function golfScore(par, strokes) {
// Only change code below this line
if (1) {
return "Hole-in-one!";
} else if (2) {
return "Eagle";
} else if (3) {
return "Birdie";
} else if (4) {
return "Par";
} else if (5) {
return "Bogey";
} else if (6) {
return "Double Bogey";
} else if (strokes >= 7) {
return "Go Home!";
}
// Only change code above this line
}
// Change these values to test
golfScore(4, 2);
@gloriousjob The interesting thing is that my code is basically the same solution that is in the wiki
@doudeman wiki?
@Moose1551 you need to compare the strokes to the par
wiki drop it
:point_right: algorithm drop it [wiki]
Explanation:
Basically while the second argument is not true, you will have to remove the first element from the left of the array that was passed as the first argument.
@doudeman interesting. yours was just a bit off from what mine was too
@doudeman Oh, I didn't realize there were spoilers
@doudeman Your exit criteria for the for loop is different
It is?
@Moose1551 It should be like this
if (strokes == 1) {
return "Hole-in-one!";
}
@doudeman look closely
@doudeman I'd tell you straight up but this is how you learn :)
@gloriousjob the "<="? because making it just less than returns [3, 4]
@doudeman Try changing it :)
challenge:Word Blanks
code:
function wordBlanks(myNoun, myAdjective, myVerb, myAdverb) {
var result = "";
// Your code below this line
result ="dog" + "big" + "ran" + "quickly";
// Your code above this line
return result;
}
// Change the words here to test your function
wordBlanks("dog", "big", "ran", "quickly");
so i don't know how to solve it.
@doudeman oh, I see it now
@doudeman yeah, that's why you should use a while loop instead of a for
@doudeman because think about what i is and what your array length is when you do the iterations
@gloriousjob I tried a while loop and it only solved the test case I can't pass
first iteration: i = 0, array = [1, 2, 3, 4]
@doudeman What's the next iteration?
@doudeman also, first iteration, arr.length = 4
@doudeman I know this is basic but can you give the three values for the next iteration? It'll help you see the problem
@doudeman using your for loop
okay so all I had to do was declare a variable before the for loop and set it equal to arr.length
@doudeman Can you see why?
that way I had a number that didn't change
@doudeman There you go :)
@gloriousjob thanks
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@Cyberistic , @DavidWeedmark , thank you. I'm getting there, but I'm stuck again. I don't understand why "Bogey, Double Bogey, and Go Home!" aren't working...
function golfScore(par, strokes) {
// Only change code below this line
if (strokes == 1) {
return "Hole-in-one!";
} else if (strokes <=par-2) {
return "Eagle";
} else if (strokes == par-1) {
return "Birdie";
} else if (par) {
return "Par";
} else if (strokes == par+1) {
return "Bogey";
} else if (strokes == par+2) {
return "Double Bogey";
} else if (strokes >= par+3) {
return "Go Home!";
}
// Only change code above this line
}
// Change these values to test
golfScore(4, 2);moose1551 sends brownie points to @cyberistic and @davidweedmark :sparkles: :thumbsup: :sparkles:
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@Moose1551 Whats the error?
@Cyberistic , no error. It's just not passing all the tests. Earlier, I was failing 4 tests, but now it's just the one "Par" Here's the revised code:
function golfScore(par, strokes) {
// Only change code below this line
if (strokes == 1) {
return "Hole-in-one!";
} else if (strokes <=par-2) {
return "Eagle";
} else if (strokes == par-1) {
return "Birdie";
} else if (strokes == 4 && par == 4) {
return "Par";
} else if (strokes == par+1) {
return "Bogey";
} else if (strokes == par+2) {
return "Double Bogey";
} else if (strokes >= par+3) {
return "Go Home!";
}
// Only change code above this line
}
// Change these values to test
golfScore(4, 2);
@Moose1551 This is where you are wrong
else if (strokes == 4 && par == 4) {
return "Par";
else if (strokes == 4 && par == 4) {
return "Par";
You want your strokes to equal your par, no && needed
^ That
Ah! So "else if (strokes == 4 par == 4) { return "Par"; }"
not quite
you only need one condition statement, not two
Did you get it @Moose1551 ?
Not quite. I think I'm alomost there, though.
Hi, I'm having trouble with the record collection problem. How do you access object properties with variable more than one variable deep?
function update(id, prop, value) {
if (value !== "" && prop !== "tracks"){
collection[id][prop].push(value);
}
if (value !== "" && prop !== "tracks"){
collection[id][prop].push(value);
}
@Moose1551 You are comparing storks and par everywhere else why not in par
@rpark4 When the prop is not tracks, you wan't to just assign the value, not push. Use assignment operator.
Like this?
} else if (par == 4) {
return "Par";
} else if (par == 4) {
return "Par";
Yes
When I changed it to that, I ended up not being able to return 4 tests instead of 1.
@Moose1551 if strokes = 4 and par =4 then strokes = par
@Masd925 Thanks. I'm still struggling though
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@Moose1551 dude not like that compare stokes and par why are you sending 4 it's not in your input function
Okay I need help with the counting cards challenge
Here is my code
Here is my code
var count = 0;
function cc(card) {
// Only change code below this line
switch (card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count++;
break;
case 10:
case "J":
case "Q":
case "K":
case "A":
count--;
break;
}
if (card <= 6 && card >= 2){
return count + " Bet";
}else if (card >= 7 && card <= 9 ){
return count + " Hold";
}else if (card == 10 || card === 'J' || card === 'Q' || card === 'K' || card === 'A'){
return count + " Hold";
}
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc(2);
@abhishekKumar1 , is this what you mean?
function golfScore(par, strokes) {
// Only change code below this line
if (strokes == 1 && par == 4) {
return "Hole-in-one!";
} else if (strokes <=par-2) {
return "Eagle";
} else if (strokes == par-1) {
return "Birdie";
} else if (par) {
return "Par";
} else if (strokes == par+1) {
return "Bogey";
} else if (strokes == par+2) {
return "Double Bogey";
} else if (strokes >= par+3) {
return "Go Home!";
}
// Only change code above this line
}
// Change these values to test
golfScore(4, 2);
cant get through "Cards Sequence 2, J, 9, 2, 7 should return "1 Bet"" task
@Moose1551 it's just "else if strokes = par" - try that
@Cyberistic Bet/hold decision is based on count.
@Moose1551
else if (strokes == par) {
return "Par";Is what you need to do
@Cyberistic your if statements should be focusing on the value of count.
@rpark4 Which means..?
it means that you want to bet if count is positive, hold if it's 0 and fold if its negative
I did it right before I read the suggestions! Lightbulb moment, haha. Thanks, @abhishekKumar1 @alfonsotech @Cyberistic @rpark4
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woops. there is no folding
@Cyberistic
if (card <= 6 && card >= 2){
return count + " Bet";
}else if (card >= 7 && card <= 9 ){
return count + " Hold";
}else if (card == 10 || card === 'J' || card === 'Q' || card === 'K' || card === 'A'){
return count + " Hold";
}This is the problem. maybe you've never sat at the blackjack table and counted cards, aye?
i did
@alfonsotech Never lol
Thank you both @rpark4
Thank you both @rpark4
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What I'm confused about is how strokes = par if it par was never assigned a value in the first "if"
if (strokes == 1) {
return "Hole-in-one!";
} else if (strokes <=par-2) {
return "Eagle";
} else if (strokes == par-1) {
return "Birdie";
} else if (strokes == par) {
return "Par";
} else if (strokes == par+1) {
return "Bogey";
} else if (strokes == par+2) {
return "Double Bogey";
} else if (strokes >= par+3) {
return "Go Home!";
}
Like, how does it know that 4 strokes = par?
Hi, I need some help with a lesson I've been stuck on for a good number of days
par and strokes are both input
@Cyberistic lol The way it works is if the total count of the cards coming out is positive, you want to bet; if negative or neutral, you want to hold. The count is the number you've been adding and subtracting in the switch statemnt.
at the beginning of the function
The function should check if firstName is an actual contact's firstName and the given property (prop) is a property of that contact.
If both are true, then return the "value" of that property.
If firstName does not correspond to any contacts then return "No such contact"
If prop does not correspond to any valid properties then return "No such property"
golfScore(5,5); function golfScore(par, strokes) {
function lookUp(firstName, prop){
// Only change code below this line
if (firstName === contacts.firstName && prop === contacts.prop) {
return contacts.prop;
} else if (firstName !== contacts.firstName) {
return "No such contact";
} else if (firstName !== contacts.firstName && prop !== contacts.hasOwnProperty(prop)) {
return "No such property";
}
thanks @qualitymanifest
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:/ all my other lessons in basic js is complete except this one
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@rpark4 no, tax you
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@mshehab93 Yes, that's a tough one. Profile Look Up, right?
@alfonsotech Never played that game, so how would I know? lol
@alfonsotech yes
@rpark4 , I see! I was paying to much attention to "if (strokes = 1)...
*too
I can't get to understand the handle on the method .hasOwnProperty
:thumbsup: @Moose1551
and accessing the objects
@alfonsotech , how'd you do that thumbs up?
@Moose1551 if you hover the mouse over that thumbs up itll give you its code
type a colon symbol and "thumb" and you get icon options
" :thumbsup: "
@mshehab93 That's the last one I have left as well so I haven't done it, but maybe we can do it together now?
Hello everyone! Please help me with the task :"Golf Code"
hi chandra go for it
return "Eagle";if(strokes=1){
return "Tiny";
}else if (strokes<=par-2){
return "Eagle";
}else if(par-1){
return "Birdie";
}else if(par){
return "Par";
}else if(Par+1){
return "Bogey";
}else if(par+2){
return "Double Bogey";
}else if(strokes>=par+3){
return "Go Home!";
}else {
return "Change Me";
}
lol
I just banged my head against the wall on that one.
@Moose1551 oops lol
if(strokes=1){
return "Hole-in-one";
}else if (strokes<=par-2){
return "Eagle";
}else if(par-1){
return "Birdie";
}else if(par){
return "Par";
}else if(Par+1){
return "Bogey";
}else if(par+2){
return "Double Bogey";
}else if(strokes>=par+3){
return "Go Home!";
}else {
return "Change Me";
}
@Moose1551 Zach can you help?
'''
:bulb: to format code use backticks! ``` more info
@chandra90 , you should compare strokes and par in each "else if" (conditional) statement.
''' function myTest(val) {
var answer = "";
// Only change code below this line
switch (val) {
case 1:
answer = "alpha";
break;
case 2:
answer = "beta";
break;
case 3:
answer = "gamma";
break;
case 4:
answer = "delta";
// Only change code above this line
return answer;
}
}
// Change this value to test
myTest(1);
'''
:bulb: to format code use backticks! ``` more info
function myTest(val) {
var answer = "";
// Only change code below this line
switch (val) {
case 1:
answer = "alpha";
break;
case 2:
answer = "beta";
break;
case 3:
answer = "gamma";
break;
case 4:
answer = "delta";
// Only change code above this line
return answer;
}
}
// Change this value to test
myTest(1);
casse 1 ,2,3 are not workinig
@chandra90 , I'd show you the code, but the others didn't and I learned a bit from it.
can anyone help
ok @chandra90 if you use else if(par) and pass any number it will pass
you have to compare it with stokes like you did above in if and first else if statement
you have to compare it with stokes like you did above in if and first else if statement
i'm dying on the record collection challenge. I don't know how to assign value within an object using only variables: function update(id, prop, value) {
if (value !== "" && prop !== "tracks"){
collection[id][prop][value]=value;
}
if (value !== "" && prop !== "tracks"){
collection[id][prop][value]=value;
}
just completed portfolio challenge. need some feedback. :smile:
http://codepen.io/arunkumrv/pen/oxvLoN
http://codepen.io/arunkumrv/pen/oxvLoN
@chandra90 , when you first use strokes, use the "==" symbol.
@rpark4 can you post your whole code and tell the challenge name and use this
help format
:point_right: code formatting [wiki]
Multi line Code
```js ⇦ Type 3 backticks and then press [shift + enter ⏎] (type js or html or css)
<paste your code here>,
then press [shift + enter ⏎]``` ⇦ Type 3 backticks, then press [enter ⏎]
Single line Code
This an inline `<paste code here>` code formatting with a single backtick(`) at start and end around the code.
See also: ☛ How to type Backticks | ☯ Compose Mode | ❄ Gitter Formatting Basics
@rpark4
collection[id][prop] accesses the property value, so you assign to it with: collection[id][prop]=value;
@Moose1551 got it.But other one?
@arunkumrv The footer is kind of big making it look empty
thanks again
@rpark4 I'll take a look, but can you post all your code so it will jog my memory
@Masd925 just hooked me up. thanks though and @alfonsotech @abhishekKumar1
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@coderNoob thanks. i'm on it
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else if(par){
return "Par"; @chandra90
hello everyone. Hows everyone doing tonight?
Hi @mstettner loverly, you?
@mstettner Hello! do not even ask lol
fabulously @mstettner. And yourself?
Hello! What is the shortest regEx for resolving http://www.freecodecamp.com/challenges/validate-us-telephone-numbers?
doing well. About to start some more JS learning. hopefully not to fustrating
@chandra90 tough night?
@mstettner just one challenge is *
@IDriuk This is a tough one. I would suggest you figure it out yourself. Its a great feeling when you get it done all by yourself.
@IDriuk You can test your cases on some useful sites like RegEx
@Moose1551 thanks
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@coderNoob I use read-search-ask, and found /^(?:(?:+?1\s(?:[.-]\s)?)?(?:(\s([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s(?:[.-]\s)?)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s(?:[.-]\s)?([0-9]{4})(?:\s(?:#|x.?|ext.?|extension)\s(\d+))?$/ This is working, but somebody must know better solution.
// Only change code below this line
function update(id, prop, value) {
if (value !== "" && prop !== "tracks"){
collection[id][prop]=value;
}
else if (value !== "" && prop === "tracks") {
collection[id][prop].push(value);
}
else if (value === "")
well that worked miserably
can't say i didn't try to format that correctly
anyone know how to comlete the Convert Celsius to Fahrenheitlesson?
anyways, I'm supposed to delete prop?
@mstettner yes, what are you struggling with?
@rpark4 I'm not sure how to write it in to javascript.
i understand the formula
- 9 / 5 + 32
ok
I just dont know how to appply that formaula into JS
so you have a function with an input for celsius
are you following so far?
Celcius = * 9 / 5 + 32; @rpark4
@IDriuk There may be many solutions. A better one? I'm not sure.
yeah this is my function * 9 / 5 + 32. correct?
@rpark4
yeah, so when they give you a function with an input for celsius. you need to define fahrenheit
@IDriuk I'm not sure if this is a good solution or bad but here is my solution
function telephoneCheck(str) {
// Good luck!
if(str.match(/(\({1})\d{3}(\){1})/g)){
if(str.match(/^1?[\s-]?\(?(\d{3})\)?[\s-]?(\d{3})[\s-]?\d{4}$/g)){
return true;
}
else
return false;
}
else if(str.match(/^1?[\s-]?\d{3}[\s-]?\d{3}[\s-]?\d{4}$/g))
return true;
else
return false;
}
okay how do I define fahrenheit?
google it
fahrenheit = celsius * 9 / 5 + 32
and use brackets
yeah bc right now it is saying that fahrenheit is not defined
@rpark4 makes sense
you'll probably need ()
celsius * (9/5) + 32
anyone know how to delete prop at the end of the record collection challenge?
its giving me a little warning triangle saying "Invalid type of value 'celcius*(9/5) + 32"
spelling
@rpark4 i think i got it
I had '' around it
ahh
there you have it
I need to define fahrenheit also??
which is fahrenheit = celsius?
no, you only need to define fahrenheit, celsius is arleady defined.
how do I define fahrenheit?
'fahrenheit not defined'
that what it is saying
you just type fahrenheit = celsius * (9/5) +32
;
that should be the only thing you have to do for that challenge
it says, "did you mean to return a conditional instead of an assignment?
function convert(celsius) {
// Only change code below this line
// Only change code above this line
if ( typeof fahrenheit !== celsius * (9/5) + 32 ) {
return fahrenheit;
} else {
return fahrenheit = celsius * (9/5) +32
;
}
}
// Change the inputs below to test your code
convert(30);
read the comments
Hello, i'm currently stuck at the "Seek and Destroy" Algorithm challenge...
how can i access the parameters to remove from the array ? there is only 1 parameter in the function signature...
how can i access the parameters to remove from the array ? there is only 1 parameter in the function signature...
Hi guys .. I am working on to make "weather web app" , can anyone tell , how to trigger the events when the page starts loading ?
bf Seek and Destroy
:fire:Bonfire: Seek and Destroy :link:
function destroyer(arr) {
// Remove all the values
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);You will be provided with an initial array (the first argument in the destroyer function), followed by one or more arguments. Remove all elements from the initial array that are of the same value as these arguments.
more info:
bf details|bf links|hint
@timgrossmann You can add more:
function destroyer(arr, num1, num2) {
...
@tnsurender Are you using jquery?
there are no comments. it says function convert referenceError: fahrenheit is not defined
yup
this challenge is so odd
@demipixel yup
@tnsurender
$(document).ready(function() {
...
});
if i console.log the art, there is only the array... But there is an undefined number of Parameters i need to take into consideration
@timgrossmann why?
@demipixel I will try and get back to you :) :)
@mstettner you will want to push the reset button. then read the //only change code below this line // only change code above this line comments
@tnsurender alright haha
@rpark4 okay
between those two comments, you will define fahrenheit like we had talked about
how can i say: this function should take a not yet specified number of parameters ?
@timgrossmann Doesn't the function always take 3 paramaters though?
no, only the arr
also there is a test case where 3 arguments are passed
Which?
@rpark4 thanks i got it
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destroyer([3, 5, 1, 2, 2], 2, 3, 5) should return 1.
Oh hm
@demipixel it varies. you have to use
arguments on this one
I have no idea how I would know to do that? I mean should i have known what to do? @rpark4
@timgrossmann You should use arguments object for those extra arguments.
also how could anyone even know how to set that entire code? seems insanely tough to understand?? @rpark4
ohh, thanks @Masd925 i'll look up this one
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yeah, to some degree. if you read through the code, you see that they have a function named "convert" with the input "celsius" That means that somewhere the code will tell you what "celsius" is, or it will explain how it will get it.
So you look for "convert()" again in the code
and you see convert(30) at the bottom
that means that the input is 30, so "celsius = 30
then you have the if statement : if ( typeof fahrenheit !== 'undefined' ) {
return fahrenheit;
} else {
return 'fahrenheit not defined';
}
}
return fahrenheit;
} else {
return 'fahrenheit not defined';
}
}
so that means that if the variable fahrenheit is a number, return fahrenheit.
otherwise return "fahrenheit is not defined"
@rpark4 I hope to one day be able to write that code and understand it. to me right now it is unbelievable that someone could come up with that
just keep at it bro
I wouldnt know where to start
@rpark4 im trying but every lesson that goes by I have fifty more questions
keep reading over it, step-by-step. In my experience peeps moves too fast through. if you have a question, even if you got the challenge right, come by the help room and ask.
@dcnr Yeap! it work.. I had to erase the checking function add(2); jeje
Thanks for all the support, It help me a lot!
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you're definitely in the right place to be lost with a lot of this. You're in good company.
thanks @coderNoob I'm not sure how to use it though
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@rpark4 true, everyone is super helpful
@coderNoob nevermind Thanks it worked
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camperbot is being a points nazi
What if somebody thanks himself/herself?
I am doing a fantastic job
haha
Thanks everyone, I'm out
later
thanks @mstettner
sorry mstettner, you can't send brownie points to yourself! :sparkles: :sparkles:
Lol
camperbot doesnt like that
@camperbot thanks
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hahahah
He likes brownies
weird lil bot
I thought i had this one! what is wrong?
"I am a \"double quoted\" string inside \"double quotes\".";
@mstettner get rid of the period
@mstettner Link to the BF please.
BF?
we're talking about bonfire :fire: Bonfire: Seek and Destroy
bonfire?
we're talking about bonfire :fire: Bonfire: Seek and Destroy
If I remember correctly you need to use the same " or ' at the start and at the end of the sentence. And anything in between you have to use the alternate of " or ' that you used at the start of the sentence.
@mstettner if you're assigning that to
var myStr you just need to get rid of the period
@mstettner Yes
otherwise, you need to assign it to
var myStr and get rid of the period
@qualitymanifest i guess I assigned it to var myVar
I am still learning all this lingo
@mstettner copy and paste the whole line
"bonfire" was just the name for what are now referred to as "algorithms". these "challenges" you're doing used to be called "waypoints"
Sorry, can't find a bonfire called was just the name for what are now referred to as algorithms these challenges youre doing used to be called waypoints. [ Check the map? ]
the change in naming happened a month or two ago
@qualitymanifest I got it. I needed to "assign" it to var myVar by putting the = sign.
shhhh camperbot does not know about that :D
thanks @qualitymanifest @coderNoob
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what is BF?
Bonfire
we're talking about bonfire :fire: Bonfire: Seek and Destroy
they are the exercises that you are doing.
seek and destroy is a bonfire
so the lessons are called BF's?
hence the little fire symbol?
I'm actually stuck on the Seek and Destroy challenge
you mean bonfire?
@mstettner Yes
function destroyer(arr) {
arguments[0].filter(function(val){
return val != arguments[i];
});
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
@mikenaza What is
i in there?
It has to be defined first.
I can't seem to figure out how to iterate through the given arguments that come after the array
@coderNoob Well I had a for loop in there
But I guess you can't have loops inside of functions
@coderNoob I realized that when I use "arguments" inside the filter method, it's taking the arguments from the callback function, not the destroyer function
The https://www.codeschool.com/free-weekend just starts in about 13 hours.
@revisualize what is that about?
Read the page?
@revisualize just says free from march 4-6th
what does that mean ?
@mikenaza You can have loop inside function.
@mikenaza In order to use destroyers arguments inside the filter callback function, you can store (destroyer function) arguments object on a variable, turn it into an array, or pass it into the filter callback as value of this.
@revisualize can I take any course?
and you have only 2 days to finish it ?
@kirbyedy good question
at the end they ask for your credit card info?
well I signed up. well see what happens
I already have an account there from before, but they pretty much dissapointed me with that its free course...
NOT!
and of course give us your credit card number...
so it was ctrl+Q straight away
@kirbyedy interesting
hey does anyone know if there are meet ups for FCC in LA?
check the facebook page for your city
@Masd925 Ahh alright
function destroyer(arr) {
var theArguments = arguments;
arguments[0].filter(function(val){
for(var i = 1; i <= arr.length; i++) {
return val != theArguments[i];
}
});
}
That's what I'm at now, but I think it may be using the arguments of the callback function still
@mstettner I wouldn't give them any of my money. I haven't and I've completed all of the free options. I'm going to try and power through as much as possible this weekend.
@kirbyedy thanks
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@revisualize cool
I have a question if a string is surrounded by single quotes i.e. '' then it can have double quotes i.e"" without have to use \\\\\?
if thats the case why not always use double quotes?''
@mikenaza You should loop theArguments, so change the limit. You can return false if you find a match, but true only after the loop.
@mikenaza Always use strict equality === and !==. Abstract equality only bites you in the butt sometimes.
I mean why not always use single quotes
??
@mstettner you can always use single quote
function destroyer(arr) {
var theArguments = arguments;
arguments[0].filter(function(val){
for(var i = 1; i <= theArguments.length; i++) {
if(val === theArguments[i]) {
return false;
}
} return true;
});
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);
@mikenaza Return statement?
so if I use single quotes I wont have to escape my double quotes within the single quotes? ugh whatever that question is probably to difficult to read and understand
@Masd925 what do you mean?
oh i need to return arr
@mikenaza You can just put the return on the start of filter line.
@mstettner nah it makes sense, and you are correct: https://repl.it/BsqY
@qualitymanifest thanks
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I am trying to encode the following sequence. I am getting close?
var myStr = \ \ \t \t \r \n;
@Masd925 Sorry I'm not sure what you mean by that
@mstettner sort of, you have too many spaces in there
@mstettner which was the name of that exercise ?
I have it after the filter method is completely done
Escape Sequences in Strings
@URobert
@mikenaza I mean this:
function destroyer(arr) {
var theArguments = arguments;
return arr.filter(function(val){
for(var i = 1; i <= theArguments.length; i++) {
if(val === theArguments[i]) {
return false;
}
}
return true;
});
}
says unexpected early end of program and an unexpected slash
@URobert
@mstettner give me a sec
yeah np
@mstettner get rid of the space in between
\ \
@mstettner you got two mistakes
oh yeah. quotation marks
@mstettner 1)your variable is a string so make sure you use "".
@Masd925 Ahh, how does it work when you are calling the method on arr? It will filter through every argument when we only need to filter through the first.
Is it because we used return so it only went through once?
@mstettner 2)your backslash escape is off... @qualitymanifest mentioned that already above
@mikenaza arr only has the first passed argument which is the array.
@mikenaza arr is the same as arguments[0]
@Masd925 Okay understood. Do you know if there's a way to console.log() a method to see the code inside? To see what exactly methods like .filter() or .map() are doing?
@mikenaza I don't know if that is possible. The functionality of all those methods is specified on ECMAScript standard http://www.ecma-international.org/publications/files/ECMA-ST/Ecma-262.pdf
@URobert @qualitymanifest thanks guys I got it. I forgot those quotes
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@mstettner yw. Happy coding !
@qualitymanifest sorry coamperbot says no brownie pts for you yet
@mstettner haha. im not worried about it. tax :+1:
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@Masd925 Okay cool. Thanks for all your help!
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oh snap! I just got me some b pts. thanks
LoL tax works for thank you
hey guys you know on your iphone when you hit the space bar twice it makes period"." can I program my computer to do the same thing?
thats the reason I'm going through code camp. thats all i want to learn lol
// Setup
function phoneticLookup(val) {
var result = "undefined";
// Only change code below this line
var obj = {
"alpha": "Adams",
"bravo": "Boston",
"charlie": "Chicago",
"delta": "Denver",
"echo": "Easy",
"foxtrot": "Frank";
}
result = obj[val];
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
syntax error
Remove the ; after frank
@rj-unstoppable Remove the ; after frank
Hello!How can send screen here?with ipad
@safbek
(shift+enter for line break)
var code = "formatted";
@safbek type ``` then enter and then write your code in between
Thanky!but I am mean send screen from ipod, no computer. I haven't shift and so on((
@rj-unstoppable
@rj-unstoppable
does this correct?
var myStr = "This is the first sentence. ";
ourStr += "This is the second sentence.";
ourStr += "This is the second sentence.";
for:
Concatenating Strings with the Plus Equals Operator
Concatenating Strings with the Plus Equals Operator
anybody out there?
errr where did you declare the ourStr ?
var myStr = "This is the first sentence. ";
ourStr += "This is the second sentence.";
is this not right?
kirbyedy
@kirbyedy