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@Dueldrawer8 yes...but it is not returnin the first name it jumps to else statement and return the code inside else statement
@Dueldrawer8 but my if stament is al right i think cos if return the firstName inside else statement it returns what it should be
if (contacts[0].firstName === firstName) {
if (contacts[0].hasOwnProperty(prop)) {
return contacts[0][prop];
@JLuboff i have tried all sorts of weird combinations haha, so should i call arr[i][j]? something like
product = product * (arr[i][j]);
product = product * (arr[i][j]);
holy shit it worked yay!!!! thaaaaaanks :D :D
Yup, there you go
the arrays variable name is contacts..to access the first object within the array.. use contacts[0]
@naeri-kailash It could also be simplified to
product *= arr[i][j] but works perfectly fine the way you have it
then to access the firstName you just do contacts[0].firstName
yeah :) true true
@Dueldrawer8 ok... i tried something it seems returning undefined with your code it will help me alot now i know my error
@andercodder with a for loop..obvousily you would replace i inside the brackets
@Dueldrawer8 thank you man very thank you
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@andercodder welcome, if you need anymore help let me know.. and you can also checkout the wiki and it will give an explanation as well as hints
@Dueldrawer8 :+1: :smile: :sparkles:
Can anyone tell me why my code is pushing every item from the array into the prototype?
https://codepen.io/MrAdam/pen/vgGoGN?editors=0012
https://codepen.io/MrAdam/pen/vgGoGN?editors=0012
for example, the first object should have a property of
oMove: ['1'], and the next object should have oMove: ['2'], instead they all have oMove: [1,2,3,4,5,6,7,8]
I have a question. Why can't I split the array with the error: TypeError: arr.split is not a function.
@sirus3020 Did you give split an argument by which to split?
arr = arr.split(' ');
cant split with arrays
its not a method
for arrays
Yup...split is used on a string, not an array
alright. thanks
so how would I split the string in the arrays?
@sirus3020 You would need to access them via their index then run split
you mean like [''hello world'', "my name is"] to [['hello', 'world'], ['my', 'name', 'is']]?
yes
you would need to iterate over the list
ok. thanks. @JLuboff @adamakers
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so say
```
var arr = [''hello world'', "my name is"];
for (var i = 0; i < arr.length: i++) {}
```
var arr = [''hello world'', "my name is"];
for (var i = 0; i < arr.length: i++) {}
damn
var arr = [''hello world'', "my name is"];
for (var i = 0; i < arr.length: i++) {
arr[i].split(' ');
}
try that
I'm trying to create a function that will reference a list and for each item of that list it will make a copy of an existing object and push the array item to another list inside of the object. instead what my code is doing is pushing all of the items to the array in the object. Anyone able to see what is going on?
https://codepen.io/MrAdam/pen/vgGoGN?editors=0012
https://codepen.io/MrAdam/pen/vgGoGN?editors=0012
objects should look something like, obj1 = {xMove: ['1']}, obj2 = {xMove: ['2']}, obj3 = {xMove: ['3']}..etc... instead I'm getting obj1 = {xMove: [1,2,3,4,5,6...]}, obj2 = {xMove: [1,2,3,4,5,6...]}, obj3 = {xMove: [1,2,3,4,5,6...]}....
Hello everyone :)
i'm having trouble understanding this function:
function permute(string) {
function recur(string, prefix) {
if (string.length === 0) {
return [prefix];
} else {
var out = [];
for (var i = 0; i < string.length; i++) {
var pre = string.substring(0, i);
var post = string.substring(i + 1);
out = out.concat(recur(pre + post, string[i] + prefix));
}
return out;
}
}
var distinct = {};
recur(string, "").forEach(function(result) {
distinct[result] = true;
});
return Object.keys(distinct);
}in the recursive function, when is string.length ever === 0?
I'm working on "Sum All Primes" The explanation says to sum all the primes all the way up to the input value. And then also add the input value. But, they say that sumPrimes(10) should return 17.... I don't follow.... All the prime numbers up until 10 and including 10 would be..... 2, 3, 5, 7, 10
Oh, wait... something just clicked... input should only be added if it is also a prime.
NEVERMIND! :)
@kevinliu6102 "".length() returns 0
Can anyone explain what this means? "if (!sieve[i]) " sieve is an empty array. What does the exclamation at hte start mean?
@joehesse you want to set the
answer variable
not create new variables like
a b c defaultStatement
@mzedlach means not
basically returns the opposite true/false value of the statement.
@mzedlach logical not
mmmm.... I'm following the guide on this challenge and it does !make sense.
@joehesse YOu need to set the return variable - see the return statement
thumbs up for the pun
:)
@mzedlach NICE
ach. I don't understand how to even come up with what htey came up with.
@mzedlach !sieve[i] would seem to me to test if sieve[i] is zero or not
@phiratio right but for each recursion, i'm reading that string is always pre + post of the previous recursion, and i'm having trouble picturing how pre + post is ever an empty string
It's the "Sum All Primes" challenge
@sjames1958gm
@mzedlach you are trying to implement the sieve method?
@sjames1958gm It looks like they just made an empty array called sieve. Let me post their code.
function getProductOfAllElementsAtProperty(obj, key) {
// your code here
for(var strange in obj){
if(Array.isArray(obj[strange])){
var total = 1;
for(var i = 0; i < obj[strange].length; i++){
total*= obj[key][i];
}
}
else if(obj[strange].length < 0){
return 0;
}
else{
return 0;
}
}
return total;
}
var obj = {
key: []
};
var output = getProductOfAllElementsAtProperty(obj, 'key');
console.log(output);function sumPrimes(num) {
var res = 0;
// Function to get the primes up to max in an array
function getPrimes(max) {
var sieve = [];
var i;
var j;
var primes = [];
for (i = 2; i <= max; ++i) {
if (!sieve[i]) {
// i has not been marked -- it is prime
primes.push(i);
for (j = i << 1; j <= max; j += i) {
sieve[j] = true;
}
}
}
return primes;
}
// Add the primes
var primes = getPrimes(num);
for (var p = 0; p < primes.length; p++) {
res += primes[p];
}
return res;
}
// test here
sumPrimes(10);
This just feels like a huge conceptual jump.
@mzedlach I guess it depends on the fact that sieve[i] that is not set is the same false.
@kevinliu6102 lets try to figure it out together can you give the code/sourse page of it?
@sjames1958gm Can you rephrase that? I don't understand your sentence ^^
@phiratio it's just an independent exercise, i came across out trying to figure out how to approach "no repeats please" algorithm problem. here is the source: https://www.reddit.com/r/dailyprogrammer/comments/164zvs/010713_challenge_116_easy_permutation_of_a_string/c7stc9m/
@mzedlach if sieve[i] is not true then i is a prime. The algorithm is to first set all the values to false, but for js sieve[i] that is not set is undefined which is also 'false'
if I do
var testArr = ['1', '2', '3', '4', '5'];
var obj = {
things: []
}
testArr.forEach(function(item){
var newObj = Object.create(obj);
newObj.things.push(item);
console.log(newObj)
});then why does each obj have a prop of things: ['1', '2', '3', '4', '5'] instead of one object havingthings:['1']and the next object havingthings: ['2']```?
@adamakers all the things refer to the same array that you created at the top. Object.create does only a shallow copy
@sjames1958gm But sieve[i] is going to give you a number. How can that be a true or false statement?
@Dueldrawer8 Because you do total = 1 if isArray is true.
@kevinliu6102 that's too advanced for my humble skills :D
@mzedlach No, sieve[i] is either true or undefined. See where it is set to true below. The idea is that when you find sieve[i] = undefined (!sieve[i])
You mark all the multiples of i with true to indicated they are not prime
You mark all the multiples of i with true to indicated they are not prime
@sjames1958gm so instead its just adding it to the prototype (which would be
obj correct?) instead of the newObj?
@adamakers No I don't think so - each instance has a things property they just happen to all reference the same array
@sjames1958gm is sieve a random array name? They could have just as well named it "apples"?
@mzedlach Yes, it is only sieve because that is the algorithm being implemented.
@sjames1958gm hmm... is there a way to implement what I am trying to do? Get it so that each object has just the one array item in it?
、、、
// Setup
var myPlants = [
{
type: "flowers",
list: [
"rose",
"tulip",
"dandelion"
]
},
{
type: "trees",
list: [
"fir",
"pine",
"birch"
]
}
];
// Only change code below this line
var secondTree = ""; // Change this line
、、、
@sjames1958gm Things are just flying over my head
@adamakers if you did
newObj.things = [item];that would create a new array each time.
HELP！How could I access the secondTree?
@sjames1958gm with what Im doing im trying to push them to an array with already existing numbers instead of create a new array
@mzedlach So the array is empty.
the first value of i is 2
2 is pushed onto the primes array - then the loop start at 4 and goes by twos (setting each value to true marking it for later as not prime)
the first value of i is 2
sieve[2] doesn't exist so is undefined !sieve[2] is true so the if passes the test.2 is pushed onto the primes array - then the loop start at 4 and goes by twos (setting each value to true marking it for later as not prime)
@shawnchenxmu try myPlants[1].list[1];
@adamakers please don't try to give out the answers when people are asking for help in the future
@adamakers With push you are adding to the existing array
@adamakers It works! Thank you! But why doing this?
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@coymeetsworld got it
because you have a couple things going on here
couldn't read it correctly as it wasn't formatted but yeah that was right
some one help me with this. I can't figure out what's wrong with this code
function rot13(str) { // LBH QVQ VG!
var dec="";
function name(str){
var s=[];
for(var i=0; i<str.length; i++)
{
s[i] = (str.charCodeAt(i)-65+13)%26+65;
}
return s;
}
dec.fromCharCode(name(str));
dec.join("");
return dec;
}
Guys, please I'm missing something but I really don't know what it is...help out!
//Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUpProfile(firstName, prop){
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (contacts[i].firstName === firstName) {
if (contacts[i].hasOwnProperty(prop)) {
return contacts[i][prop];
}
return "No such property";
}
return "No such contact";
}
// Only change code above this line
}
// Change these values to test your function
lookUpProfile("Kristian", "lastName");
@sanjay-sopho that's not how you add to an array
there are array functions you can use to add items to an array
I don't understand what I'm doing wrong here. The test runs (showing me what answers I should be getting) aren't making sense in and of themselves, and I"m struggling with this concept as a whole.....if anyone has a moment to maybe explain why I'm on the struggle bus I'd really appreciate it.
var Bike = function() {
// Only change code below this line.
var gear=0;
this.setGear=function(change){
gear += change;
};
this.getGear = function(){
return gear;
};
};
var myCar = new Car();
var myBike = new Bike();
Make Object Properties Private
also fromCharCode takes a character in, not a String I believe
@coymeetsworld like push ?
thanks
yes
I am from c background. I keep making such mistakes
thanks anyway
@vzambrano98 did you do the same for Car?
no problem
also @vzambrano98 that's not how you set the gear for a Bike
its not the same as accelerating for a car
@shawnchenxmu your inital structure is an array, inside that array you have an object, thats the first item in the array. the second item in the array, the one we are interested in has an index of 1. we access that item by going myPlants1. Then we need to access the second item just in that obj. doing that we can go myPlants1.list. we wont do myPlants1 because that would look for the property of 1 so instead we go myPlants1.list. Then to access the second item in the list we just add a 1 to the end of that, getting myPlants1.list1
@coymeetsworld The car part is from their section, before mine.
also I don't understand why it's not the same....
also I don't understand why it's not the same....
you guys how do you handle this issue?
Handling of 'touchstart' input event was delayed for 164 ms due to main thread being busy. Consider marking event handler as 'passive' to make the page more responsive.
@vzambrano98 hmmm i feel like that should've been covered and tested in a previous challenge
but for car you increment the speed, but bike you just change it
@sjames1958gm so im just SOL then? Cant push the item to the existing array?
@coymeetsworld explain this as if I were five, because what you're saying isn't clickin
oh wait that is in the same challenge
hey guys do we have any good example problems that would explain how to transform an array of data into an object format??
did you ever own a variable speed bike @vzambrano98 ?
@sjames1958gm trying to use it for the minimax algorithm to determine the next possible gamestates
@adamakers Thank you very much! You are so nice!
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theres just a dial on the handle and you change it and then its set. So if you're on speed 1 and want to go to speed 4, you don't go to 2 then 3, its just 4
so whatever value you get to setGear, thats what you make gear, you don't increment it to what it has. If you did that, then the example above if you set the speed to 4 it would be 5
@sjames1958gm Okay, thank you so much for "Explaining it like I'm 5" That seriously helped :) (I know that may sound like sarcasm. But, no sarcasm!) So it all makes sense up until this point:
for (j = i << 1; j <= max; j += i) {
sieve[j] = true;So, first line --> I'm reading that << has something to do with binary notation? I do understand that this section has something to do with all following multiples created from i value. So, i = 2 would propogate 4, 6, 8, 10 (If the input was 10). So I don't understand the << ..... and if sieve[j] = true (or even if it equaled false...) so what? I don't see what happens there.
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@coymeetsworld ooooooohhhhh!!!!! see that's so much better, so then I wouldn't use
+= I would just use... gear=change
right?
yep
YAY! okay, I would have never gotten that lol I"ll give it a try, thanks for your help
@coymeetsworld thanks*
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no problem
@sjames1958gm
function getProductOfAllElementsAtProperty(obj, key) {
// your code here
for(var strange in obj){
if(obj[strange].length > 0){
var total = 1;
for(var i = 0; i < obj[strange].length; i++){
total*= obj[key][i];
}
return total;
}
else if(!Array.isArray(obj[strange])){
return 0;
}
}
}
var obj = {
key: []
};
var output = getProductOfAllElementsAtProperty(obj, 'key');
console.log(output);now if the property at the key is an empty array..it needs to return 0 but it is returning undefined
i find the instructions rather vague
@AndrewScr Copy the test string and replace the keywords with the values from the table then remove all spaces
@Dueldrawer8 Init total before the if so that it is set when the if test false
hello...
Is it legal to assign IIFE to a variable?
Like
var m = (foo(){
var a = 2;
return a;
}();Is this legal? Does it have any bad side effects?
@sjames1958gm these are the other 3 objctives i have to do :
Notes:
Notes:
- If the array is empty, it should return 0.
- If the property at the given key is not an array, it should return 0.
- If there is no property at the given key, it should return 0.
@sjames1958gm tried using Array.isArray but that doesnt work
If i wanted to change [['myName', 'John'],['yourName, 'Ed']] to {myName: "John", yourName: "Ed"} where would I even start?
@sjames1958gm keeps saying its NaN
for example if i make the key a string
also used typeOf
@sjames1958gm nvm got it although its long
@sjames1958gm i think i might have a solution. I could just create a new array like you suggested, and then concat the two. just tested it and it works
function getProductOfAllElementsAtProperty(obj, key) {
for(var strange in obj){
var total = 1;
if(Array.isArray(obj[strange]) && obj[strange].length > 0){
for(var i = 0; i < obj[strange].length; i++){
total*= obj[key][i];
}
return total;
}
else{
return 0;
}
}
}
Im having a little problem figuring out what's wrong here:
var count = 0;
function cc(card) {
// Only change code below this line
for (card) {
if (card =2,3,5,6) {
count ++;
} else (card =10, 'J', 'Q','K','A') {
count --;
}
}
}
return count;
@ceharrison is card supposed to be an array?
Trying to figure out the for loop
Question! When would it be useful or required to delete a property from an object using delete object.property? Would it not just be better to edit the object all together?
Hi everyone! Could anyone help me with the Arguments Optional challenge? I read about closures but it does not make too much sense for me. Why when I run addTogether(2)([3]); it says addTogether(...) is not a function?
Could use some help with the Babel compilier.
http://codepen.io/JTKnox91/pen/zNxyXP?editors=0010
Look at line 1134 uncomplied and line 1443 compilied.
Usually any this is turned into _thisXX. For instance this.player in the uncompiled constructor for Map becomes _this23.player. In the I am expecting line 1134 to compile into _thisXX.player.location but instead remains as this.player.location, which is undefined when that method is called. What am I doing wrong here that's stopping the Babel from compiling that method the way it compiles the other methods?
function nextInLine(arr, item) {
// Your code here
return item; // Change this line
}
// Test Setup
var testArr = [1,2,3,4,5];
// Display Code
console.log("Before: " + JSON.stringify(testArr));
console.log(nextInLine(testArr, 6)); // Modify this line to test
console.log("After: " + JSON.stringify(testArr));
New to javascript and this is doing my head in!
I need to add the number to the end of the array and remove the first?
@ jbkwizera
Anyone?
there is nothing wrong by assigning a IIFE to a variable as far as I know. IIFEs are useful in the context of closures. In the specific example you have provided, there isn’t much value
hi guys any help here?
function titleCase(str) {
var arrayNew = str.split(" ");
for(var i= 0; i<arrayNew.length; i++){
arrayNew[i].charAt(0).toUpperCase();
equis = arrayNew.join(" ");
}
return equis;
}
titleCase("I'm a little tea pot");do you know why the code is not working?
@c0mplexm0z try looking at MDN documentation when you have questions about methods related to certain classes
@y0el22
function titleCase(str) {
var arrayNew = str.split(" ");
for(var i= 0; i<arrayNew.length; i++){
arrayNew[i].charAt(0).toUpperCase(); //this doesn't actually assign anything, try " arrayNew[i] = ..." and then what you had written before.
equis = arrayNew.join(" "); //this only needs to be done once, so you could move it out of the for loop
}
return equis;
}
titleCase("I'm a little tea pot");Let me know how those changes work
@y0el22 you should try using the debugger to see what you are getting
@sjames1958gm thanks Stephen
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@GregatGit i'm getting the string normal
I have and still cannot get my head around it
need some help on this 1st lesson of javascript
Do not change code above the line
a should have a value of 7
b should have a value of 7
a should be assigned to b with =
a should have a value of 7
b should have a value of 7
a should be assigned to b with =
@y0el22 are you trying to uppercase the sentence one letter at a time and add it to the array?
maybe im just fucking stupid
@JTKnox91 sorry i understand but i don't know how to do it
So on one of the lessons it says that this:
var testObj = {
12: "Namath",
16: "Montana",
19: "Unitas"
};
// Only change code below this line;
var playerNumber = 16; // Change this Line
var player = testObj[playerNumber]; // Change this Line
prints out "Montana"
but i put it in the browser console and it says undefined ..why is that?
@GregatGit yes i¡m doing that no?
@y0el22 toUpperCase() does change the orginal so
var a = 'a';
var capitalA = a.toUpperCase();
// a is still 'a' and capitalA is 'A'
@c0mplexm0z you basically need to remove the first element of the array: use shift method and to add the given item at the end of the array, use push method
@raghu-nx yes but I need the function to return the shift.
It's this bit I am stuck with
@GregatGit let me see what i'm doing wrong
@TacoJoe because in the console, the testObj is undefined
run testObj in the console
@c0mplexm0z oh ok, shift method removes the first element and returns that value.
var shiftedVal = arr.shift()
var shiftedVal = arr.shift()
help ```
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < multiplyAll.length; i++){
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
```
no wiki entry for:
function multiplyallarr var product 1 only change code below this line for var i0 i multiplyalllength i only change code above this line return product modify values below to test your codemultiplyall1234567
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < multiplyAll.length; i++){
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
@veksen var player = console.log( testObj[playerNumber]); this seemed to work
@y0el22
sorry guys i really don't get this problem
maybe later i can i don't know :(
sorry guys i really don't get this problem
maybe later i can i don't know :(
is that what you meant?
yes and no, type:
testObjin the console
@mtpjr88 Look at the example - it shows how to do the two loops and how to access the value
@CheeZeee I got stuck on this too. It seems the return "No such contact" inside the first for loop is where it's getting stuck. Because you're iterating through each member and not all of them are contacts[i].firstName === firstName.
I got around this by adding a boolean:
I got around this by adding a boolean:
function lookUpProfile(firstName, prop){
// Only change code below this line
var hasName = false;
for(var i=0; i< contacts.length; i++){
if(contacts[i].firstName == firstName){
hasName = true;
if(contacts[i].hasOwnProperty(prop)){
return contacts[i][prop];
}
return "No such property";
}
}
if(hasName === false){return "No such contact";}
// Only change code above this line
}:bulb: to format code use backticks! ``` more info
@y0el22 try writing out each of the steps you want to do - your first step would be to make the str lowercase
@veksen woo! thanks!
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@GregatGit all the string lowercase first?
@y0el22 yes
titleCase("HERE IS MY HANDLE HERE IS MY SPOUT") and titleCase("sHoRt AnD sToUt") need it
@RetartedZombie just FYI the boolean is not needed because you return when the firstName is matched the only way to fall out of the loop is if there is no match on firstName
@y0el22 don't code it - just write the steps you need to take
nextInLine([5,6,7,8,9], 1) should return 5 . ??
@c0mplexm0z Yes, you add 1 to the end and remove and return 5 from the front.
Yeah it should return 5 and the array should be modified as 6,7,8,9,1
Hello FCC friends, I need some guidance with the "stand in line" challenge. I think that I will need to use the .unshift() function and .push() function but am having trouble after attempting a few times.
I’m not sure if you understand what I meant.
Basically var ele = arr.shift() would pop the first element from the array and return it
Now for a function to reuturn a value you need to use return statement. So, essentially it would be return ele;
Basically var ele = arr.shift() would pop the first element from the array and return it
Now for a function to reuturn a value you need to use return statement. So, essentially it would be return ele;
Thanks @sjames1958gm . Must have been getting stuck on something else then :)
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unshift adds to the front - @colinmac17
Not quite sure what im missing here, should return a count of -5, i think:
var count = 0;
function cc(card) {
// Only change code below this line
if (card == 2,3,4,5,6) {
return count ++;
} else if (card == 10, 'K', 'Q', 'J', 'A') {
return count --;
}
return count;
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(4); cc(5); cc(6);
sorry, should return 5
@ceharrison card == 2, 3, 4, 5, 6 is not how you test for various values you need ||
ah I did mean shift() @sjames1958gm still having trouble. I was using a for loop but having trouble getting it to work
could you expand?
@sjames1958gm
@sjames1958gm https://www.freecodecamp.com/challenges/comparisons-with-the-logical-or-operator
card == 2 || card == 3
card == 2 || card == 3
so there's not a short way to write it?
@colinmac17 This does not require a loop - just two statements one to add item to the end of arr and one to remove and return the first value of arr
@ceharrison no, you could use a switch / case but that is even longer
@mtpjr88
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < arr.length; i++){
if(Array.isArray(arr[i])) {
product = arr[i].reduce(function(a,e) {
return a * e
}, product);
} else {
product *= arr[i];
}
}
// Only change code above this line
return product;
}
ok, i'll give that a shot, thanks
var customerData = {
'Joe': {
visits: 1
},
'Carol': {
visits: 2
},
'Howard': {
visits: 3
},
'Carrie': {
visits: 4
}
};
function greetCustomer(firstName) {
var greeting = '';
if(customerData['firstName'].visits === 1){
greeting = "Welcome back, " + firstName + "! We're glad you liked us the first time!"
}else if()
return greeting;
}
greetCustomer("Joe")
can anyone see here why visits is coming up as undefined?
when I replace ['firstName'] with ['Joe'], it works, but I want it to work for all customers
@sjames1958gm go to question 176 on the map
I've also tried if(customerData.property.visits===1)
customerData[‘firstName’] => access property firstName on the object
customerData[firstName] => access property where the property name is the value of the variable firstName
customerData[firstName] => access property where the property name is the value of the variable firstName
@c0mplexm0z if you are talking stand in line I am quite familir with it
basically ‘firstName’ is a string but you want to access it as a variable
what's the order again? object, property, value?
so when the testArr is 1,2,3,4,5 - how can nextInLine([5,6,7,8,9], 1) return 5?
@sjames1958gm can you explain why this returns "4":
var count = 0;
function cc(card) {
// Only change code below this line
if (card == 2 || card == 3 || card == 4 || card ==5 || card == 6) {
return count ++;
} else if (card == 10 || card == 'K' ||card == 'Q' ||card == 'J' ||card == 'A') {
return count --;
}
return count;
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(4); cc(5); cc(6);
yeah [] notation or .(dot) both try to access the property of an object. So the expression evaluates to value of the property
@ceharrison because return count ++ returns the value of count before the last increment.
You should not return there or in the else
Because you need to test count > 0 to determine what to return.
You should not return there or in the else
Because you need to test count > 0 to determine what to return.
can i ask for more help again with the escape sequences
var myStr = "FirstLine\n\SecondLine\rThirdLine\";
is the solution i have so far
i got it. Thanks @raghu-nx
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@sjames1958gm thanks for the tip!
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@colinmac17 :+1:
@AndrewScr Your last
\ is out of place there should be a \ escaped after SecondLine
function nextInLine(arr, item) {
arr.push(item);
var shiftedVar = arr.shift();
return shiftedVar;
arr.push(item);
var shiftedVar = arr.shift();
return shiftedVar;
}
About time
you need to ask about @someone!
@c0mplexm0z nice!
@sjames1958gm var myStr = "FirstLine\n \SecondLine\r\ ThirdLine"; // Change this line
@raghu-nx cheers man!
like that?
it still doesn't like it
@sjames1958gm im a little confused how to return a < or > 0 after the "if else"
@AndrewScr The other side of the
\r and then remove all the spaces
@ceharrison Another if / else
if count > 0
else
if count > 0
else
does that require different indents than the previous if/else statements?
i need help```function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i = 0; i < arr.length[i]; i++){
product *= arr1;
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
```
@sjames1958gm thanks again
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still not going
var myStr = "FirstLine\n\SecondLine\rThirdLine"; // Change this line
some help
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i = 0; i < arr.length[i]; i++){
product *= arr[1];
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
@mtpjr88 that looks close, but you want to use
[i] in your loop
var myStr = "FirstLine\n\SecondLine\rThirdLine"; // Change this line
var myStr = "FirstLine\n\SecondLine\rThirdLine"; // Change this line
wtf the chat is removing a slash
@mtpjr88 also, I think you may need nested loops (an i loop and a j loop)
@AndrewScr On either end of SecondLine there should be escape backslashes
@AndrewScr put your code inbetween single or triple backticks
@mtpjr88 each element in the arr argument itself is an array. so yeah as @dhcodes said
@raghu-nx PM'ed you man
var myStr = "FirstLine\n\SecondLine\rThirdLine"; // Change this line
chat still removing backslashes
@AndrewScr you should put it between backticks
I'm still not sure why this is returning "5":
var count = 0;
function cc(card) {
// Only change code below this line
if (card == 2 || card == 3 || card == 4 || card ==5 || card == 6) {
count ++;
} else if (card == 10 || card == 'K' ||card == 'Q' ||card == 'J' ||card == 'A') {
count --;
}
return count;
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(4); cc(5); cc(6);
whats a backtick?
@dhcodes
@AndrewScr `
is under the esc key
what he said
'''
:bulb: to format code use backticks! ``` more info
click 'more info'
thank you
@raghu-nx @dhcodes so I got it right
but i dont fully understand it
but i dont fully understand it
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i = 0; i < arr.length; i++){
for (var j = 0; j < arr[i].length; j++){
product *= arr[i][j];
}
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
the lesson doesn't mention backticks
@ceharrison hmmm you're calling the function 5 times and every card number you're sending increments the count variable by 1
maybe i missed it earlier
@AndrewScr i'm saying the chat is removing your backspace becuase you're not formatting it as code in the chat (by using backticks)
oh
there i was typing it into the editor wondering why you were suggesting i type invalid js
var myStr = "FirstLine\n\\SecondLine\\rThirdLine"; // Change this line
:)
var customerData = {
'Joe': {
visits: 1
},
'Carol': {
visits: 2
},
'Howard': {
visits: 3
},
'Carrie': {
visits: 4
}
};
function greetCustomer(firstName) {
var greeting = '';
if(customerData[firstName] !== firstName){
greeting = "Welcome! Is this your first time?"
}if(customerData[firstName].visits === 1){
greeting = "Welcome back, " + firstName + "! We're glad you liked us the first time!"
}else {
greeting = "Welcome back, " + firstName + "! So glad to see you again!"
}
return greeting;
}
greetCustomer("John")
any ideas why a new customer isn't working?
@mtpjr88 you have 1, and then the first i loop loops through the outside array (the one with all the sub arrays), then the j loop loops through all the individual items in each subarray and *= multiplies them with 1 and returns the new value
i guess im not following @RonyVidaur...
@mtpjr88 ok when i generally face such issues, i would start down with a pen and paper and write down the values of i and j and update the values by executing the function by hand
that provides great clarity
i would suggest doing that and if you still have issues you can ask again
I think I may have a bug on my hands. This is on the Iterate with Javascript for Loops. It wants me to push 1-5 to myArray and I am doing that but it still says that myArray should equal [1,2,3,4,5] Which it does.
// Example
var ourArray = [];
for (var i = 0; i < 5; i++) {
ourArray.push(i);
}
// Setup
var myArray = [];
// Only change code below this line.
for (var i = 0; i <= 5; i++) {
myArray.push(i);
}
sorry, let me correct myself. Changed "if" to "else if" but now it prints the first greeting for everyone
proud of you @CoryCMyers for checking your bug in the chat first ;)
@dhcodes Thankee Sai
@CoryCMyers i think your issue is
i<=5 should be i<5
@dhcodes it asks for it to push 1-5 to the array though, would'nt i<5 only push 1-4?
I'm stuck on this Word Blanks
function wordBlanks(myNoun, myAdjective, myVerb, myAdverb) {
var result = "";
// Your code below this line
My myAdjective myNoun myAdverb myVerb straight into the pile of leaves.
// Your code above this line
return result;
}
// Change the words here to test your function
wordBlanks("dog", "big", "ran", "quickly");
idk if I'm supposed to make a sentence or what
the directions are confusing me
@CoryCMyers no because remember that while i<5, i will increment up to 5 and be pushed
so even when i is 4, the loop will run
@ceharrison you're making these cc(2); cc(3); cc(4); cc(5); cc(6);
count++
count was 0, now it is 1
and so on
I see that they would add up to a 5. I'm confused on how show a "bet" or "hold" givin a >0 or <0.
@dhcodes Just tried that fix and it only displayed up to 4 in the check your results area.
@ceharrison oh
@CoryCMyers can you paste your url
@dhcodes This is with the i<5 want me to do it after running how I had it originally?
Has anyone done the Word Blanks project before?
@longorjames yes
I don't understand how they want me to start it
do I start making a sentence ?
and then just fill in spots with myNoun, myAdjective, etc.?
@CoryCMyers ah,
my bad
you were rigth
I know how Mad Libs works... but I'm really confused
but your i should be 1
@CoryCMyers
You will need to use string operators to build a new string, result, using the provided variables: myNoun, myAdjective, myVerb, and myAdverb.
You will also need to use additional strings, which will not change, and must be in between all of the provided words. The output should be a complete sentence.
We have provided a framework for testing your results with different words. The tests will run your function with several different inputs to make sure all of the provided words appear in the output, as well as your extra strings.
@dhcodes oh I feel silly. they want 1-5 and I have 0 in there
function wordBlanks(myNoun, myAdjective, myVerb, myAdverb) {
var result = "";
// Your code below this line
// Your code above this line
return result;
}
// Change the words here to test your function
wordBlanks("dog", "big", "ran", "quickly");
@johnnunns if they are back you should make their visits go up by 1, or if it's there first time add them to the customerData obj with visists at 1
@longorjames set the result equal to a string made of the function's arguments concatenated together
@CoryCMyers :+1:
@dhcodes thanks
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@GregatGit it specifically tells me to not worry about a count++, but the code still doesn't run correctly. I think the problem is in the first if statement.
@longorjames this is one of the first challenges with a reusable function. The tests will supply different values to the arguments of the function (ex. myNoun) so your job is to build a string using those variable names (and spaces inbetween) and then assign it to result
// Setup
var myStr = "Jello World";
// Only change code below this line
myStr = "Hello World";
myStr[0] = "H"; // Fix Me
can anyone tell me why this isn't working for me. I am new to all this
@drywallandy delete myStr[0]=
@drywallandy remove the last line
yeah what Dylan said
@johnnunns your if condition logic is a little off
can anyone help me
still not workng
thanks, I was almost going to start beating my head against the wall
var myStr = "FirstLine\n\\SecondLine\rThirdLine"; // Change this line
@dhcodes sooooo result = "My" + myAdjective + myNoun + myAdverb + myVerb " into the pile of leaves.";
@longorjames yeah but with some spaces
ex. "My "
and spaces in between the arguments
it just gives me an error with unexpected string
also it asks for an extra word blank with cats and stuff
Hey guys - I need help with the Convert Celsius to Fahrenheit challenge!
@longorjames you need to have a + before the last line
@johnnunns it is always going to check this
if(customerData[firstName].visits === 1) and for "Joe" it doesn't exist so you will get an error
wordBlanks("dog", "big", "ran", "quickly") should contain all of the passed in words separated by non-word characters (and any additional words in your madlib).
wordBlanks("cat", "little", "hit", "slowly") should contain all of the passed in words separated by non-word characters (and any additional words in your madlib).
wordBlanks("cat", "little", "hit", "slowly") should contain all of the passed in words separated by non-word characters (and any additional words in your madlib).
do I just add that or am I supposed to change the dog stuff
@longorjames those tests will be passed to the function
so just fix the function
you don't need to write the function for each test
@krittiyaclark what's up
result = "My " + myAdjective + myNoun + myAdverb + myVerb + " into the pile of leaves.";
@longorjames but you need spaces between your variables
? there are spaces?
I'm confused
@dhcodes got stuck. not understand.
@longorjames not between your variable
@johnnunns if the first condition is correct you want it to exit the function immediately - not make anymore evalution - so instead of setting greeting to "Welcome! Is this your first time?" just return "Welcome! Is this your first time?";
@dhcodes "The algorithm to convert from Celsius to Fahrenheit is the temperature in Celsius times 9/5, plus 32."
@krittiyaclark understandable; the tests will give you a celsius value
my variables?
@longorjames WHY u added space on ur
"My "+myAdjective ?
you mean the myAdjective and stuff
you need to return a formula using the variable
celsius @krittiyaclark
@moigithub Dylan said I needed spaces
@moigithub hey that's fine
he just needs spaces between the variables
i don't understand how to add spaces between the variables, aren
@longorjames myVariable + " " + nextVariable
aren't there already spaces?
.... oh
;)
otherwise they'd all be smashed together
do i put a space in between the quotes
or just leave empty quotes?
you put a space
ok it worked. that is odd o.O
not intuitive at all....
@dhcodes thank you very much
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@dhcodes thank you very much
:warning: longorjames already gave dhcodes points
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@dhcodes I got this --> function convertToF(celsius) {
var fahrenheit = (celsius(9/5))+32;
// Only change code below this line
// Only change code above this line
return fahrenheit;
}
// Change the inputs below to test your code
convertToF(0);
@longorjames that's how you build strings with variables though
@krittiyaclark u need an
* to multiplicate values
@krittiyaclark looks good, just add a
* after celsius
and return fahrenheit
idk how I was supposed to know that though, it wasn't discussed in any previous teachings of how to use strings
or variables
sure it was
we were taught to add strings
Constructing Strings with Variables
not strings and variables
and concatenating strings
nor did they use empty space quotes in between
yeah, you have to merge the ideas
this challenge is a common question in the chat
no worries
well i just felt the core ideas to put together weren't given is what i mean
i get that
so idk who makes this website or the projects but I think they should add smaller steps in between or more hints or something
I'm just glad there are people to get help from on here cause i'd probably give up...
well there is this issue freeCodeCamp/freeCodeCamp#9233
but the changes won't be live until the next site update
@dhcodes Hey - that it! lol
Thanks:)
function reverseString(str) {
var array=str.split(" ");
for(i=0;i<array.length;i++){
array[i]=array[i].reverse();
}
str=array.join(" ");
return str;
}reverseString("Greetings from Earth");
@dhcodes Thanks:)
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what is wrong with these codes
you're welcome! great job getting it mostly on your own
that's a hard challenge @krittiyaclark
function reverseString(str) {
var array=str.split(" ");
for(i=0;i<array.length;i++){
array[i]=array[i].reverse();
}
str=array.join(" ");
return str;
var array=str.split(" ");
for(i=0;i<array.length;i++){
array[i]=array[i].reverse();
}
str=array.join(" ");
return str;
@alimily you are splitting on the spaces
I think you want to split on
""
which means split every character
what challenges is that
no every word
Reverse a String
i want to splitting every word ,and reverse every word
then join them to a string again
gotcha
yes
@alimily
array[i] is a string
why is a string
i can undetstand
because it's the first word in the array you made
function reverseString(str) {
var array=[];
array=str.split(" ");
for(i=0;i<array.length;i++){
array[i]=array[i].reverse();
}
str=array.join(" ");
return str;
}reverseString("Greetings from Earth");
you cannot run
reverse() on a string
this will be ok?
you need to split array[i] on a
"" and then run reverse on that
i gotta go though. Good luck!
ok
thks
Challenge 161 Global Scope and Functions help
I have defined myGlobal variable, declared, it, and avoid declaring oopsGlobal. I am having a hard time assigning values to myGlobal and oopsGlobal. Where should I start reviewing?
@Krate2016 post your code here
@Manish-Giri // Declare your variable here
var myGlobal = [10];
function fun1() {var myGlobal = 10; return myGlobal;}
// Assign 5 to oopsGlobal Here
oopsGlobal = [5];
function fun2() {oopsGlobal = 5; return oopsGlobal;}
// Only change code above this line
function fun2() {
var output = "";
if (typeof myGlobal != "undefined") {
output += "myGlobal: " + myGlobal;
}
if (typeof oopsGlobal != "undefined") {
output += " oopsGlobal: " + oopsGlobal;
}
console.log(output);
}
@Krate2016 what's with the arrays?
var myGlobal = [10];
oopsGlobal = [5];
shouldn't it be just a plain number?
also, this is where your code goes
// Declare your variable here
//myGlobal here
function fun1() {
// Assign 5 to oopsGlobal Here
//your oopsGlobal assignment should be here
}
not sure what this is for
function fun1() {var myGlobal = 10; return myGlobal;}
// Assign 5 to oopsGlobal Here
oopsGlobal = [5];
function fun2() {oopsGlobal = 5; return oopsGlobal;}
@Manish-Giri That was my bad, thanks!
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function reverseString(str) {
var array=[];
array=str.split(" ");
array.reverse();
str=array.join(" ");
return str;
}reverseString("Greetings from Earth");
hello
everyone
please,help me
@alimily this is your expected output
reverseString("Greetings from Earth") should return "htraE morf sgniteerG".
this is your actual output -
"Earth from Greetings"
@alimily
str = str.split(" ");
no need for a new variable
@alimily you are just changing the order of the words -
1 2 3 becomes 3 2 1
but you need ro reverse each word too
hi, help to solve this challenge(chunkey monkey),
function chunkArrayInGroups(arr, size) {
// Break it up.
if(size<=arr.length){
return arr.slice(0,size);
}else
return "it's out of array";
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
Evening! Some assistance would be greatly appreciated! I'm getting a message saying break is unreachable after return.
var count = 0;
function cc(card) {
// Only change code below this line
switch(card){
case (2):
case (3):
case (4):
case (5):
case (6):
return count + 1;
break;
case (7):
case (8):
case (9):
return count;
break;
case (10):
case ('J'):
case ('Q'):
case ('K'):
case ('A'):
return count - 1;
break;
}
return "Change Me";
// Only change code above this line
}
// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
hey is there anyone to give me assistance on above posted challenge
@jothetraveler don't use return in the switch - just assing count a value
var myVar = 87;
// Only change code below this line
myVar = ++myVar;
what,s wrong with my code
@coolcoder007 what's the challenge
increment the number with javaScript
var myVar = 87;
// Only change code below this line
myVar = ++myVar;
@coolcoder007 myVar++;
@Ammy3165 h
@GregatGit thanks
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@Ammy3165 you are just returning on slice of the array - you have to return all the numbers
Hello. :)
@coolcoder007
var num = 5;
num = num + 1; // 6
num += 1; // 7
num++; // 8See how the one for getting num from 7 to 8 doesn't use the assignment operator (=)?
The lesson is requesting that you recreate that process so that you know how to increment and decrement a number with short notation.
@jothetraveler Counting Cards is a challenge where your function will receive a
If the value of the
If the value of the
Then the function will return a string with the current
The current
card parameter. You're supposed to increment or decrement the global count variable according to the card's valueIf the value of the
card parameter is 2, 3, 4, 5 or 6 you need to increment the global variable count.If the value of the
card parameter is 10, 'J', 'Q', 'K' or 'A' you need to decrement the global variable count.Then the function will return a string with the current
count and the string "Bet" if the count is positive, or "Hold" if the count is zero or negative.The current
count and the player's decision ("Bet" or "Hold") should be separated by a single space.
Need some help
How do you make a selectbox with the switch statement ?
<select>
<optgroup>Group 1</optgroup>
<option>1</option>
<option>2</option>
<option>3</option>
<optgroup>Group 2</optgroup>
etc
@revisualize Hey Joseph good timing :D
@Doegena No idea.
@Doegena If I was trying to create HTML entries like that .. I wouldn't use a switch at all.
@Doegena So, I have no idea how to do that with a switch statement.
I would use nested objects with properties that I wanted to define.
@revisualize me neither, but need to make it with a switch statement, if i can do this and some other random tests/projects (drawing application, basic chatserver), i will graduate in 1 or 2 years instead of 3. well if i pass the test
@GregatGit @revisualize Thank you. I think I see where I went wrong now
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@revisualize but i have currently no idea how to make a chatserver with javascript
function caseInSwitch(val) {
var answer = "";
switch (val) {
case 1:
answer = "alpha";
break;
var answer = "";
switch (val) {
case 1:
answer = "alpha";
break;
is there some obvious reason I don't know about that I can't use .toUpperCase() ?
function caseInSwitch(val) {
var answer = "";
switch (val) {
case 1:
answer = "alpha";
break;
Can anyone explain what i'm doing wrong here?
@Doegena You have no idea how to make a chat server with JavaScript. Well neither do I. Nor do I care to learn.
@barrystepp You haven't finished it?
```function myReplace(str, before, after) {
var newStr = str.split(' ');
var index = newStr.indexOf(before);
if (index !== -1) {
if (index[0] === index[0].toUpperCase())
newStr[index] = after[0].toUpperCase() + after.slice(1);
}
//capitalization
return newStr.join(' ');
}
myReplace("A quick brown fox jumped over the lazy dog", "jumped", "leaped");
```
@sperrye Strings are immutable.
function caseInSwitch(val) {
var answer = "";
// Only change code below this line
switch (val) {
case 1:
answer = "alpha";
break;
case 2:
answer = "beta";
break;
case 3:
answer = "gamma";
break;
case 4:
answer = "delta";
// Only change code above this line
return answer; }
}
@barrystepp Does that work?
@barrystepp OH!
@barrystepp
is inside of your switch case for 4
return answer; }is inside of your switch case for 4
@barrystepp It should be outside of your switch.
@revisualize THANK YOU!!!!
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I hate it when its something so simple as that... but at least i know i got the general concept.... just messed up on that little curly guy.
@sperrye
index is a number.
@revisualize Thanks, I did figure it out :)
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Oh look, another algorithm challenge..
@sperrye Did you solve it?
@sperrye Did you ever go to that meetup thing?
I am stuck on this challenge.
@kayvanote Which?
profile Lookup
@kayvanote How can I help?
@revisualize OOOhh, misunderstood the question, if the user CLICKS a genre the user needs to see the movies of that genre :laughing:
example
case '0':
document.getElementById('v').innerHTML ='<ul><li>example<li></ul>';
break;
@kayvanote What is the current state of your
function?
should paste it?
@kayvanote Just the function. Not the large array of object. Just the function.
function lookUpProfile(firstName, prop){
// Only change code below this line
if (contacts.hasOwnProperty(firstName) === false) {
return "No such contact";}
else if (contacts.hasOwnProperty(prop) === false) {
return "No such property";}
else if (contacts.hasOwnProperty(firstName) === true && contacts.hasOwnProperty(prop) === true) {
return contacts[prop];}
// Only change code above this line
}
// Only change code below this line
if (contacts.hasOwnProperty(firstName) === false) {
return "No such contact";}
else if (contacts.hasOwnProperty(prop) === false) {
return "No such property";}
else if (contacts.hasOwnProperty(firstName) === true && contacts.hasOwnProperty(prop) === true) {
return contacts[prop];}
// Only change code above this line
}
@kayvanote Okay.
First issue.
@kayvanote We have an array of objects representing different people in our contacts lists.
Example:
Example:
var contacts = [ { ... } , { ... } , { ... } , { ... } ];
okay
yes true
@kayvanote So, you're not accessing the array element correctly. Nor are you iterating across the array elements
@kayvanote Do you understand what I mean?
I tried iterating with a for loop.
It is okay to say no. I can help you understand.
yes
@kayvanote Well, you need one for this lesson.
@kayvanote This may be easier: Gist by revisualize / FreeCodeCamp - Profile Lookup.js
if I used for (var i = 0; i < contacts.length ; i++ )
and then maybe an inner loop
@kayvanote Why would you need an inner loop?
Objects don't have .lengths
Esacpe Sequences are not working in JS possible bug/
?
Hi everyone, I often get stuck at 'why only looping once' problem...like this twitch project
https://jsfiddle.net/k456czcm/
though it logs every stram IDs i set up, it just can't return all the streams IDs into HTML
wonder anyone could help me? thanks.
I encountered similar problems lots of time while doing other projects, but I just couldn't figure out ... /_\
This is my code
var myStr = "FirstLine\n\SecondLine\\n\rThirdLine";
thank you for the hints and the link, appreciated!
though it logs every stram IDs i set up, it just can't return all the streams IDs into HTML
var myStr="FirstLine\n\SecondLine\\n\rThirdLine";
output : var myStr = "FirstLine\n\SecondLine\\n\rThirdLine";
Hey guys I'm stuck in "Using Objects for Lookups" can someone help me
@Vizij Every this is returned as it is even If I try this
myStr ="Firstline\nString2";
I will get output: "Firstline\nString2";
@revisualize hi, I am stuck here, Pls look into,
function chunkArrayInGroups(arr, size) {
// Break it up.
var newArray= [];
for(var i=0; i<arr.length; i++){
newArray.push(arr.slice(0,size));
arr= arr.slice(size); }
return newArray;
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
@sharang108 Why are you escaping a newline after SecondLine?
@sharang108 There isn't a bug. You aren't doing it correctly.
how to?
FirstLine
\SecondLine\
ThirdLine
\SecondLine\
ThirdLine
@Ammy3165 may I recommend using www.pythontutor.com/javascript.html
@moist17 I don't think you want to create a new get request with each streamer
@arkosingh How do you escape a newline in a string?
var myStr="FirstLine \"SecondLine\" \rThirdLine";
// Change this line
// Change this line
you should just append to the page you have using jQuery, that would be my suggestion
does anyone know how to solve "Using Objects for Lookups"?
@Gameruler1 I do.
@arkosingh Why are you escaping quotes?
how to do?
@revisualize can you please help me
"-(
@Gameruler1 Can you please post your code? Instead of just asking for help?
@arkosingh
FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
val = {
"alpha": "Adams",
"bravo": "Boston",
"charlie": "Chicago",
"delta": "Denver",
"echo": "Easy",
"foxtrot": "Frank",
"": undefined
};
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("alpha");
@arkosingh Replace the words with the escape characters.
@Gameruler1 Your object should NOT be overwriting the
val parameter
@Gameruler1 It tells you what your object should be called in the instructions.
@arkosingh How do you escape a newline?
@arkosingh How do you escape a backslash?
@arkosingh How do you escape a carriage-return?
hi, I am stuck here, Pls look into,
function chunkArrayInGroups(arr, size) {
// Break it up.
var newArray= [];
for(var i=0; i<arr.length; i++){
newArray.push(arr.slice(0,size));
arr= arr.slice(size);
}
return newArray;
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
@Ammy3165 Did you use pythontutor.com like I suggested?
@Ammy3165 Because I think you should be adding size to your
i as you iterate across your array (arr).
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var i=0; i < arr.length; i++) {
for (var j=0; j< arr[i].length; j++) {
product = product * arr[i][j]*arr[i++][j++];
}
}
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
@revisualize I haven't learn to code in python yet.
@Ammy3165 www.pythontutor.com/javascript.html has NOTHING to do with python.
@tanpaopao remove
*arr[i++][j++];
As I understanding, arr[i][j] is only a element of an array.
someone mind helping me w/ a codewars challenge?
anybody knows how to pass this challenge
@revisualize Could you explain it? Thank you again.
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Convert Celsius to Fahrenheit
@coolcoder007 yes what do you need
i need a code
@coolcoder007 You do need code.
do you have any code you can provide?
What is your code? Have you done anything?
lol @revisualize
function convertToF(celsius) {
var fahrenheit;
// Only change code below this line
farenheit=(celsius *(9/5))+32;
// Only change code above this line
return fahrenheit;
}
// Change the inputs below to test your code
convertToF(0);
convertToF(-30);
convertToF(-10);
convertToF(0);
@coolcoder007
farenheit is misspelled.
fahrenheit
Solved.
NEXT!
Can someone help me with 152 ... This is where I am:
function wordBlanks(myNoun, myAdjective, myVerb, myAdverb) {
var result = "";
// Your code below this line
var myNoun = "dog";
var myStr = "Hello my name is" + myNoun + "i am a" + wordBlanks[wordBlanks.length -3] + "that" + wordBlanks[wordBlanks.length -2] + "very" + wordBlanks[wordBlanks.length -1] + "HOWS THAT?";
// Your code above this line
return result;
}
// Change the words here to test your function
wordBlanks("dog", "big", "ran", "quickly");
@revisualize you are excellent, thank you so much.
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@coymeetsworld thanks! but sorry i don't quite understand...you mean this part
if (data.stream === null) {
showName = channelName;
showOnline = 'Offline';
showLogo = 'http://s.jtvnw.net/jtv_user_pictures/hosted_images/GlitchIcon_PurpleonWhite.png';
showUrl = 'https://www.twitch.tv/'+channelName+'';
} else if (data.stream === undefined) {
showName = 'Accnount Closed';
showOnline = 'Account Closed'
showLogo = 'http://s.jtvnw.net/jtv_user_pictures/hosted_images/GlitchIcon_PurpleonWhite.png';
showUrl = 'Account Closed';
} else {
showName = data.stream.channel.status;
showOnline = 'Online';
showLogo = data.stream.channel.logo;
showUrl = data.stream.channel.url;
}
console.log(showName, showOnline, showLogo, showUrl);
renderHTML();should move out from request.onload function?
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@EzraPlato Gist by revisualize / FreeCodeCamp - Word_Blanks.js
The function declaration was set up as...
and with four parameter of
There is more that I could go into (if you want I can) but, I'll sum it up with:
Parameters are variable-like objects that represent the values that get passed into your function from the function call (arguments). (You basically treat them like variables.)
The function declaration was set up as...
function wordBlanks(myNoun, myAdjective, myVerb, myAdverb) giving the function name as wordBlanksand with four parameter of
myNoun, myAdjective, myVerb and myAdverb`.There is more that I could go into (if you want I can) but, I'll sum it up with:
Parameters are variable-like objects that represent the values that get passed into your function from the function call (arguments). (You basically treat them like variables.)
@revisualize still not working i think my logic is not right
Hello guys
@coolcoder007 show me.
thanks @revisualize i figured it out -
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// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
var lookup = {
"alpha": "Adams",
"bravo": "Boston",
"charlie": "Chicago",
"delta": "Denver",
"echo": "Easy",
"foxtrot": "Frank",
"": undefined
};
result = lookup[val];
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
no @moist17 i meant the request object:
var url = 'https://wind-bow.gomix.me/twitch-api/streams/'+channelName+'';
var request = new XMLHttpRequest();
request.open('GET', url, true);
request.onload = function() {
@Gameruler1 Grats.
how to?
@revisualize thank you. I will try to figure it out with the hint. Thanks again.
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FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine
@arkosingh How do you escape a newline?
@arkosingh How do you escape a backslash?
@arkosingh How do you escape a carriage-return?
@arkosingh How do you escape a backslash?
@arkosingh How do you escape a carriage-return?
by using \ @revisualize
@arkosingh I have same problem
@revisualize i have done thank you
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:-) @sharang108
:|
@revisualize pls help me
struggling here
@arkosingh And you're not answering my questions.
@arkosingh I'm asking what are you drinking.
And you're replying with: "A liquid."
I'm sitting here like.. No shit man you don't drink solids.
And you're replying with: "A liquid."
I'm sitting here like.. No shit man you don't drink solids.
function convertCF(num, scale){
if (scale === "c") {
return (num - 32) * 5 / 9;
} else if (scale === "f") {
return (num * 9/5) + 32
} else if (scale === null || scale === '') {
return (num - 32) * 5 / 9;
} else {
throw Error;
}
}
@arkosingh How do you escape a newline?
@arkosingh How do you escape a backslash?
@arkosingh How do you escape a carriage-return?
@arkosingh How do you escape a backslash?
@arkosingh How do you escape a carriage-return?
@arkosingh 3 questions. ... 3 different answers.
by // for backslash
Incorrect.
@revisualize
@arkosingh Is the '\n' printing as it is for you/
?
@sharang108 He hasn't used any of the correct escape sequences.
@revisualize Why does this not work
myNoun = wordBlanks[wordBlanks.length -4].
myStr = "Hello my name is" + myNoun + "i am a" + myAdjective + "that" + myVerb + "very" + myAdverb + "HOWS THAT?";
@EzraPlato Because this
myNoun = wordBlanks[wordBlanks.length -4]. is nothing.
And you're overwriting
myNoun with nothing.
@EzraPlato Also, you don't have spaces between your variables parameters.
@EzraPlato Peopledon'twritelikethis.
People write like this.
@revisualize Okay But I I have used correct sequences and still I don't get the correct output, possibility of a bug?
@sharang108 Show me.
pkay
@revisualize Input : var myStr ="FirstLine\r\SecondLine\r\ThirdLine"; // Change this line
@sharang108 You don't have the correct sequence.
FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine
@sharang108 You're escaping a carriage-return where you should be escaping a newline.
@sharang108 You're escaping a carriage-return before backslash after SecondLine.
@revisualize I don't understand where I don't have spaces
O NOW I DO
"Hello my name isdogI am a
@revisualize output: var myStr ="FirstLine\r\SecondLine\r\ThirdLine"; // Change this line
@revisualize Okay thanks that works! :D
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@sharang108 That isn't correct either.
@revisualize is anything right
previously, by using getElementsByTagName i'd get a node list, but after I've replaced the content on my file with a handlebars template the same getElements is giving me a HTMLcollection. Is this something that happens or am I just connecting two separate instances?
You have to assign 'FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine' to the variable myStr.
But, you have to replace the words with the proper escape sequences.
How do you escape a newline? With:
How do you escape a backslash? With:
How do you escape a carriage-return? With
So, you have break the problem down.
And you assign that to myStr as a string.
But, you have to replace the words with the proper escape sequences.
How do you escape a newline? With:
\nHow do you escape a backslash? With:
\\How do you escape a carriage-return? With
\rSo, you have break the problem down.
FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLineFirstLine\nbackslashSecondLinebackslashcarriage-returnThirdLineFirstLine\n\\SecondLinebackslashcarriage-returnThirdLineFirstLine\n\\SecondLine\\carriage-returnThirdLineFirstLine\n\\SecondLine\\\rThirdLineAnd you assign that to myStr as a string.
whats wrong with my code?
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
for (var p = 0; p < arr.length; p++) {
for (var i = 0; i < arr.length[i]; i++) {
}
arr = product * arr[i];
} // Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
You need to learn how to use escape sequences in JS.
@revisualize The problem was with the incorrect mapping of escaping newline etc, thanks again
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@dsillydude You're not accessing the child array elements.
@revisualize how ?
@dsillydude Why are you creating
p but not using it?
@dsillydude
what is:
var nArr = [ ["b1" , "d1"] , ["f2" , "h2"] , ["j3" , "l3"] ];what is:
nArr[1];?
@revisualize oh should be the first array right
@dsillydude I am looking for an exact answer here. That is ambiguous.
nArr1 = [b1 , d1]
Incorrect.
oh wait
[f2 ,h2] that was zero lol
function getIndexToIns(arr, num) {
arr = arr.sort();
for (var i = 0; i< arr.length; i++){
if (arr[i] >= num) {
return i;
}
else if (arr[i] == num) {
return i;
}
}
}
getIndexToIns([2, 5, 10], 15);
@dsillydude How do you access:
"j3" ?
@revisualize pls see what's the problem now,
function chunkArrayInGroups(arr, size) {
// Break it up.
var newArray= [];
for(var i=0; i<arr.length; i+=size){
newArray.push(arr.slice(0,size));
arr= arr.slice(size); }
return newArray;
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
can anyone help me in this where do i belong challenge?
function getIndexToIns(arr, num) {
arr = arr.sort();
for (var i = 0; i< arr.length; i++){
if (arr[i] >= num) {
return i;
}
else if (arr[i] == num) {
return i;
}
}
}
getIndexToIns([2, 5, 10], 15);
@revisualize by using this code [2]
@bigyankarki arr.sort() will not sort the array numerically
how will sort then?
@dsillydude I'm sorry. That isn't an answer I can work with.
@bigyankarki The answer is on the help page for
.sort()
@revisualize this one nArr2;
@dsillydude Incorrect.
@dsillydude What is
nArr[2] ?
getElementsByTagName is returning an html collection. isn't it supposed to return a node list? I was getting a node list, but when I replace content on my file with handlebars template i've been getting an htmlCollection
@revisualize thats actually doesnt exist
@dsillydude Yes it does.
@dsillydude
var nArr = [ ["b1" , "d1"] , ["f2" , "h2"] , ["j3" , "l3"] ];
pls see what's the problem now,
function chunkArrayInGroups(arr, size) {
// Break it up.
var newArray= [];
for(var i=0; i<arr.length; i+=size){
newArray.push(arr.slice(0,size));
arr= arr.slice(size);
}
return newArray;
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
@Ammy3165 I'm looking.
Can anyone help with Stand in Line? It says arr.push is not a function.
@revisualize how i thought i only got one array and many sub array or am i forgetting sumn here..
@richafig your code?
@dsillydude You haven't answered my question yet.
function nextInLine(arr, item) {
arr.push(item);
arr.unshift();// Your code here
return arr[0]; // Change this line
}
// Test Setup
var testArr = [1,2,3,4,5];
// Display Code
console.log("Before: " + JSON.stringify(testArr));
console.log(nextInLine(testArr[4], 10)); // Modify this line to test
console.log("After: " + JSON.stringify(testArr));
@dsillydude I'm trying to help you but, I don't know where your knowledge is lacking.
@richafig How do you remove the first element from an array?
@richafig
arr.unshift()?
.unshift, right?
@richafig Incorrect.
@revisualize i see im trying to put things together lemme answer your qn now
@dsillydude I'm trying to help you put things together.
@dsillydude But, I need exact answers from you to help.
Guys , anybody did exercise 217 ?
@richafig
.unshift() is like .push(), to the front.
@Zerka1982 Lessons don't have numbers. What is the name of the lesson?
Testing Objects for Properties
@Manish-Giri So, I'm actually adding a number, right?
@dsillydude
var nArr = [ ["b1" , "d1"] , ["f2" , "h2"] , ["j3" , "l3"] ];
How do you access "j3"?
@richafig yes, that's what you're doing. But that's not what you're supposed to do.
but the syntax is wrong, anyway.
Oh, ok. @Manish-Giri Thanks for the hint. I guess I have to try something else.
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Ok I know what this means addTogether(2,3)
What does this mean though addTogether(2)(3)?
@Manish-Giri How, or what, is wrong?
@grantknaver Currying.
@richafig
How do you add a number (item) to the end of an array (arr)? What does this method return?
How do you remove the first element from an array (arr)? What does this method return?
The push() method adds one or more elements to the end of an array and returns the new length of the array.
The pop() method removes the last element from an array and returns that element.
The shift() method removes the first element from an array and returns that element.
The unshift() method adds one or more elements to the beginning of an array and returns the new length of the array.
I am trying to convert a htmlCollection into an array, but I am receiving an empty array. @Manish-Giri
@revisualize okay by going with the nArr = [1]
try this nArr[2,0]
@revisualize thanks I am reading about it now
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@revisualize i think i forgot array challenges
Hello wise js gurus - ive written addTogether so that when addTogether(2)(3); is invoked, it will return a function which should then take 3 as an argument, which i think is the point of the assignment. But get an error: addTogether... is not a function. addTogether(2,3) works fine, but the other is also a requisite scenario.
guys any help with with Testing Objects for Properties
@Zerka1982 That's incorrect.
@Zerka1982 What does your code look like?
@Ammy3165 I'm looking I'm confused. I'm sorry. I can't help with that one.
// Setup
var myObj = {
gift: "pony",
pet: "kitten",
bed: "sleigh"
};
function checkObj(checkProp) {
// Your Code Here
myObj.hasOwnProperty(chechProp);
}
// Test your code by modifying these values
checkObj("gift");
@Zerka1982 Okay.
@revisualize I am waiting for your response
@Manish-Giri yes I've looked into it, but i'm still receiving an empty array.
var elements = document.getElementsByTagName('li');
console.log("before click");
console.log(elements);
pullData();
var arr = [].slice.call(elements);
console.log(arr);
@Ammy3165 I'm looking on pythontutor. and I can't figure out why you're not pushing.
@Zerka1982 The hasOwnProperty() method returns a boolean indicating whether the object has the specified property.
@Ammy3165 OH!
@Ammy3165 TRY
@Ammy3165
i<=arr.length;
function getIndexToIns(arr, num) {
arr = arr.sort(function (a, b) {
return a-b;
});
for (var i = 0; i< arr.length; i++){
if (arr[i] >= num) {
return i;
}
}
}
getIndexToIns([2, 5, 10], 15);
@relentless-coder is
elements being returned correctly?
can somoeone let me know how can i write the code if the num is grater than all the elements in the array?
@Manish-Giri yes, me send in a snapshot of it.
@bigyankarki what's the challenge name?
@Manish-Giri
@Ammy3165 the challenge name is where do i Belong
@Ammy3165 That doesn't quite work.
@Ammy3165 Here are the notes that I wrote for that lesson:
need to create a new array.
need to .push elements to the new array.
need to slice elements off of the array as they are added to the new array
need to create a new array.
need to .push elements to the new array.
need to slice elements off of the array as they are added to the new array
@Manish-Giri Just to let you know, I wasn't facing this issue before I replaced content on my html with a handlebars template. does it have something to do with that?
@Ammy3165 I know what your problem is!
@bigyankarki What if none of the
arr[i]'s are greater than num? Maybe you should check if num is greater than arr[i] and use a variable to get the index instead of returning in the for loop
thanks for the reference for pythonTutor.com, ,@revisualize
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@Ammy3165 Okay. I know what is going on.
@Ammy3165 Here's what you're doing.
var myStr = "FirstLine \n Second line \r Third Line"; // Change this line
need help
@coolcoder007 You're not escaping any of the backslashes.
@coolcoder007
Second line is not the same as SecondLine
@coolcoder007
Third Line is not the same as ThirdLine
where to put \ backslash
@coolcoder007 'FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine'
@relentless-coder might be, I've not worked much with Handlebar to say for sure..
Hi, I am having two issues with my Wikipedia viewer. 1) The search results aren't being added to the page 2) I can't run a 2nd search query after the 1st. I was wondering if anyone help me figure out what is wrong with my logic, and point me in the right direction? http://codepen.io/tiffanymakes/pen/egzmdP
@Ammy3165 Sorry, I'm distracted. I'm getting work emails at 10pm.
@Ammy3165 You're iterating across your array. But, you're constantly making your array smaller.
thanks for your response @revisualize
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@Ammy3165 Sorry. For my distractions. I'm trying to help people and looking at all of my work emails. You shouldn't be overwriting
arr
@tiffanymakes if you use a submit button and a form, you're going to need to prevent the default behavior of those which is to send a request out
@tiffanymakes you sure
action="query" is the best way to go?
@coymeetsworld so maybe I should use an input button instead of a submit button?
@Ammy3165 I SOLVED IT USING YOUR CODE!
@tiffanymakes you can still use form-submit if you fix this
prevent the default behavior
@Ammy3165 I had to delete a bunch of stuff.
but, I solved it.
LOL!
you could @tiffanymakes, or just prevent default behavior. It would probably be simpler to just omit the form and submit button though and just use a regular button
guys need ur help with exercise 216 (Javascript)
you then would give that button an onclick handler in jQuery to get the search text and put it into your API call
@revisualize where is the fix ?
and then use jQuery to modify the page locally
@Ammy3165 So, first off you need to stop overwriting
arr as your i variable counts up.
@Ammy3165 Then you need to use
i and size in your .slice()
@Manish-Giri I'm not sure, the other method I tried was action="opensearch", but it gave me an array that was hard to do a for loop with.
@Ammy3165 That isn't exactly the answer but, damn it is really close.
@coymeetsworld by a regular button, do you mean type="button"?
yes
@Ammy3165 I could give you the exact answer but.. I kind of don't want to.... :P ?
@Ammy3165 I would if you really want me to.
@revisualize var myStr="FirstLine\r\SecondLine\\rThirdLine";
@revisualize I am really frustated?
still not working
@tiffanymakes it's quite easy, you just need to loop through the array, pick the item from the current index from each of the arrays, and combine the three things (title, text and link) to form the result..
@coolcoder007 You went from escaping a newline before SecondLine to now escaping a carriage-return where you should be escaping a newline.
@Ammy3165
newArray.push(arr.slice(i,i+size));
@coolcoder007 You have to assign 'FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine' to the variable myStr.
But, you have to replace the words with the proper escape sequences.
How do you escape a newline? With:
How do you escape a backslash? With:
How do you escape a carriage-return? With
So, you have break the problem down.
And you assign that to myStr as a string.
But, you have to replace the words with the proper escape sequences.
How do you escape a newline? With:
\nHow do you escape a backslash? With:
\\How do you escape a carriage-return? With
\rSo, you have break the problem down.
FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLineFirstLine\nbackslashSecondLinebackslashcarriage-returnThirdLineFirstLine\n\\SecondLinebackslashcarriage-returnThirdLineFirstLine\n\\SecondLine\\carriage-returnThirdLineFirstLine\n\\SecondLine\\\rThirdLineAnd you assign that to myStr as a string.
@coymeetsworld thank you, the search results are now showing. I didn't realize it was because of the "submit". I need to read up on how button submit works.
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nice @tiffanymakes yeah look it up for HTML not JavaScript
@revisualize problem fixed again thanks
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hey someone mind helping me w/ a problem on code wars
newArray.push(arr.slice(i,i+size)); I did this too @revisualize But didn't worked.
@coolcoder007 Do you understand why you do that?
@Ammy3165 Show me.
function chunkArrayInGroups(arr, size) {
// Break it up.
var newArray= [];
for(var i=0; i<=arr.length; i+=size){
newArray.push(arr.slice(i,i+size));
arr= arr.slice(size); }
return newArray;
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
@Ammy3165 You're still overwriting arr.
@Ammy3165 You can't overwrite array.
@Ammy3165 You can't make arr get smaller as you grow
i
@revisualize yes i figured it out :+1:
okk that's good
@Ammy3165
<= should be <
@revisualize finally lots off of thanks
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@Ammy3165 You should really look that over to understand it. It's quite confusing.
@BrianCodes33 I could try. I don't know how well I'd do.
@BrianCodes33 Should I get a shot of Captain before I travel down this rabbit hole?
@tiffanymakes yes that link
okk I was doing one more iteration, but now I have this one, still confusing;function chunkArrayInGroups(arr, size) {
// Break it up.
var newArray= [];
for(var i=0; i<arr.length; i+=size){
newArray.push(arr.slice(i,i+size));
arr= arr.slice(size); }
return newArray;
}
chunkArrayInGroups(["a", "b", "c", "d"], 2);
@tiffanymakes
Create a function called convertCF() that accepts 2 arguments, an integer of the temperature, and a string of length 1 ("c" or "f") denoting which scale the integer should be converted to (Celsius and Fahrenheit, respectively). The function should return a number, which is the conversion from one scale to the other.
function convertCF(num, scale){
if (scale === "c") {
return (num - 32) * 5 / 9;
} else if (scale === "f") {
return (num * 9/5) + 32
} else if (scale !== "c" && scale !== "f"){
throw Error;
} else {
return (num - 32) * 5 / 9;
}
}
can someone tell me why the first part of this code isn't executing correctly?
if (val > 5) {
result = "Bigger than 5";
} else {
result = "5 or Smaller";
// Only change code above this line
return result;
}
if (val > 5) {
result = "Bigger than 5";
} else {
result = "5 or Smaller";
// Only change code above this line
return result;
}
@devlikesramen close your else block
with a closing bracket
@BrianCodes33 Can you show me a function call?
convertCF(32, "c")
@BrianCodes33 you need to check if
scale(the second) argument was passed in, as I was saying.
it is closed
@Manish-Giri c
@BrianCodes33 Okay so, those are in order.
@devlikesramen No it isn't.
and then rearrange your conditions accordingly.
i didn't paste my closing bracket but its there and still not working
@BrianCodes33 Let's see.
so the way i do that is to check if scale is null?
Guys please tell me why "Not Found" does not return
// Setup
var myObj = {
gift: "pony",
pet: "kitten",
bed: "sleigh",
};
function checkObj(checkProp) {
// Your Code Here
if (myObj.hasOwnProperty("checkProp")); {
return myObj[checkProp]; }
return "Not Found" ; }
// Test your code by modifying these values
checkObj("gift");
@BrianCodes33 I think you can use the
arguments object
make an array out of it, check if the length is 1.
@Zerka1982 "checkProp" this is a string. Not a variable.
@devlikesramen did you set your variable result so it knows to check what result is
@revisualize hmmmm
@Manish-Giri sorry, I'm still experimenting; I can't seem to get it to work. Thank you for checking up on me!
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I'm having trouble with the "escape sequences in strings" exercise.
@Mac33d What does your string look like?
var myStr ="FirstLine\n\SecondLine\r\ThirdLine";
no matter where i put my \ it doesent show up
backslash i mean
@BrianCodes33 i just had to move my return statement outside of the if/else statement, thanks!
@Mac33d Because you aren't escaping a backslash correctly.
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@Mac33d How do you escape a backslash?
just two \
@Mac33d Yes.
it doesent show up when i enter it tho
@Mac33d Fix your order:
SecondLinebackslashcarriage-return
SecondLinebackslashcarriage-return
@Mac33d You're escaping a carriage-return before the backslash.
@Mac33d Show me.
ok
@Manish-Giri seems like your way is complete different than mine
@tiffanymakes sure thing, holler if you need help with that approach
holler back!
var myStr ="FirstLine\n\\SecondLine\r\ThirdLine";
@Mac33d You're escaping a carriage-return before the backslash.
@Mac33d Fix your order:
SecondLinebackslashcarriage-return
@Manish-Giri yes i do
@Mac33d You're not escaping the backslash before SecondLine correctly. Why do you have
\\\?
<p>how can I do this??</p>
It said to enter backslash "\" newline "\n" and carriage return "\r"
@Mac33d No.
@Mac33d You have to assign 'FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine' to the variable myStr.
But, you have to replace the words with the proper escape sequences.
But, you have to replace the words with the proper escape sequences.
@BrianCodes33 https://jsbin.com/lusahasezu/edit?js,console
oh
how long does the basic algorith scripting take? just curious how long it took whoever finished it
@Mac33d FirstLine then newline then backslash then SecondLine then backslash then carriage-return then ThirdLine
Without all of the thens nor spaces
@Manish-Giri did you fix it?
ill try that out
@BrianCodes33 no I'm showing you what the problem is
you call
convertCF(50) and you wrongly get the error
@BrianCodes33 I'm pretty sure I want to solve the challenge. LOL
hah @revisualize
@BrianCodes33 here's how I fixed it - https://jsbin.com/baporewego/edit?js,console
ah i see
ok
though I'd probably keep that as the very last case
i was so close
yep
finally got the title case question right
function convertCF(num, scale = "c") {
if (scale === "c") return (num - 32) / 9 * 5
if (scale === "f") return num / 5 * 9 + 32
throw new Error()
}
that looks cleaner
i like those default args in es6
@BrianCodes33
function convertCF(degree, scale) {
if (scale == "f") {
return degree * 9/5 + 32;
}
if (scale == "c") {
return (degree - 32) * 5/9;
}
return undefined;
}
it's from here
undefinedisn't an option, probably.
var myStr ="FirstLine\n\SecondLine\rThirdLine";
still not working
@BrianCodes33 yeah default args is pretty neat, I used it in my Simon game
What's wrong with this lookup table?
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
val={
"alpha":result="Adams" ,
"bravo":result="Boston",
"charlie":result="Chicago",
"delta":result="Denver",
"echo":result="Easy",
"foxtrot":result="Frank"
};
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
@LicheeLiu Lots of things.
@LicheeLiu Your overwriting the parameter
val with an object.
@LicheeLiu The object should be named
lookup as per the instructions.
@LicheeLiu Objects are key value pairs.
@BrianCodes33 Passed: 43 Failed: 1 Errors: 1
@LicheeLiu Your function has declared and initialized the variable
result to "". You are not modifying result and your function is returning result. Ergo, you're returning "". You need to modify result to be the value of the property from the object that you created.
HEY! I got it!
Time: 467ms Passed: 45 Failed: 0
@Manish-Giri @BrianCodes33 :muscle:
Time: 311ms Passed: 45 Failed: 0
You have passed all tests! :)
lol
@revisualize thanks!Letme try
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I don't like that code.
Let's make it better!
var myStr ="FirstLine\n\SecondLine\rThirdLine";
I went word by word and this is what i got
Time: 323ms Passed: 45 Failed: 0
@revisualize still don't know what should I do with the "result"?
var lookup={
"alpha":"Adams" ,
"bravo":"Boston",
"charlie":"Chicago",
"delta":"Denver",
"echo":"Easy",
"foxtrot":"Frank"
};
function convertCF(num, scale="c"){
//code here
if (scale === "c") {
return (num - 32) * 5 / 9;
} else if (scale === "f") {
return (num * 9/5) + 32
} else {
//console.log("ERROR");
throw Error;
}
}
How to return "result"?
@revisualize oh hey, gz on reaching 3K!
:tada:
@Mac33d If you went word by word and got this:
var myStr ="FirstLine\n\SecondLine\rThirdLine";
You didn't go word by word.
@LicheeLiu Your return statement is already written.
@LicheeLiu make it so that it equals the info in the table that you have named lookup
@Mac33d
FirstLine
newline
backslash
SecondLine
backslash
carriage-return
ThirdLine
FirstLine
newline
backslash
SecondLine
backslash
carriage-return
ThirdLine
@LicheeLiu You should assign result to be the value from your lookup object.
@Mac33d You're still not escaping backslashes correctly.
@LicheeLiu heres my completed code
// Setup
function phoneticLookup(val) {
var result = "";
// Only change code below this line
var lookup = {
"alpha": "Adams",
"bravo": "Boston",
"charlie": "Chicago",
"delta": "Denver",
"echo": "Easy",
"foxtrot": "Frank",
"": undefined
};
result = lookup[val];
// Only change code above this line
return result;
}
// Change this value to test
phoneticLookup("charlie");
@Mac33d
You have to assign 'FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine' to the variable myStr.
But, you have to replace the words with the proper escape sequences.
How do you escape a newline?
How do you escape a backslash?
How do you escape a carriage-return?
You have to assign 'FirstLinenewlinebackslashSecondLinebackslashcarriage-returnThirdLine' to the variable myStr.
But, you have to replace the words with the proper escape sequences.
How do you escape a newline?
How do you escape a backslash?
How do you escape a carriage-return?
@Gameruler1 Giving people answers doesn't help them learn.
@Gameruler1 Studies have shown that giving people answers to problems instills an illusionary sense of learning. Because, it only puts information into short-term memory. Of which people think they are learning. Only through a little struggle and repetition that the human brain puts things into long-term memory. I don't know what your end goal. I don't know if you want to do this as a personal project, hobby, or if you want to move into industry. Because of this, I strongly feel that working with people to allow them to solve problems on their own is a far better outcome than giving away answers. But, others clearly don't agree with my methods for helping people learn.
Write a function called "transformEmployeeData" that transforms some employee data from one format to another.
The argument will look something like this:
[
[
['firstName', 'Joe'], ['lastName', 'Blow'], ['age', 42], ['role', 'clerk']
],
[
['firstName', 'Mary'], ['lastName', 'Jenkins'], ['age', 36], ['role', 'manager']
]
]
Given that input, the return value should look like this:
[
{firstName: 'Joe', lastName: 'Blow', age: 42, role: 'clerk'},
{firstName: 'Mary', lastName: 'Jenkins', age: 36, role: 'manager'}
]
Note that the input may have a different number of rows or different keys than the given sample.
For example, let's say the HR department adds a "tshirtSize" field to each employee record. Your code should flexibly accommodate that.
Starter Code :
function transformEmployeeData(array) {
// your code here
}
anyone feel confident they could help me solve this one?
Look at the time!
so far my code is :
function transformEmployeeData(array){
var x = {}
for(var i =0; i<data.length; i++){
x[i]=data[i];
console.log(x)
}
}
transformEmployeeData(data)
when I run it it's nothing close though
Never learned how to transform an array into an object so I'm a little irritated it's even asking me
@johnnunns
for(var i =0; i<data.length; i++)
what is
data?
sorry, above my code I've declared data as the information above
[
[
['firstName', 'Joe'], ['lastName', 'Blow'], ['age', 42], ['role', 'clerk']
],
[
['firstName', 'Mary'], ['lastName', 'Jenkins'], ['age', 36], ['role', 'manager']
]
]
[
['firstName', 'Joe'], ['lastName', 'Blow'], ['age', 42], ['role', 'clerk']
],
[
['firstName', 'Mary'], ['lastName', 'Jenkins'], ['age', 36], ['role', 'manager']
]
]
@joseph Jesus. I need to read more carefully. Ty!
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I've come close to solving it using the reduce method, but as far as I know it's not wanting me to use reduce
@revisualize I'm showing her what i did because sometimes the wording of the explanation can be, as well as the fact that some people are more visual learns than they are reading an explanation which i think is a reason why each problem comes with an example to show the learner more or less what the end result should look like. Thats why I chose to tell her how its done and than give her my solution at it so she may see exactly what I was trying to explain. Whether she chooses to copy it and not learn it is up to her. Personally if I find a solution to a problem (whether handed to me or by researching it) I like to reverse engineer it and figure out how the end goal was achieved and how it all connects.
Hi.... I am not able to understand why this code does not push the input values 2,3 and 6,7 into the 2D array. Here's the code below:
function chunkArrayInGroups(arr, size) {
var arrGrouped = [];
for (var i = 0; i < arr.length; i+=2) {
arrGrouped.push(arr.slice(i,i+=size));
}
return arrGrouped;
}
chunkArrayInGroups([0,1,2,3,4,5,6,7,8], 2);
@Muzaffarhssn5 I get incrementing
i+=size but why i+=2 ?
、、、
can anyone tell me what does the 'strict' button has to do in simon says game?
、、、
var c=9;
、、、
var c=9;
、、、
@Masd925 @Vizij Thanks Bro.... Got it.....
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@Muzaffarhssn5 You should increment by
i+=size in the for loop definition and use arguments (i,i+size) on the slice.
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@johnnunns I'm done with the code for your challenge, I think
@Masd925 Yep... Got it....
var count=0;
'''
'''
:bulb: to format code use backticks! ``` more info
var count=0;
How are people getting a conditional to detect a value of NaN? I've tried using the isNaN() method but it doesnt seem to work?
Hello all. how to code in"stand in line"? thanks!
Can any one help me with task 216
@LowCountry
Number.isNaN()?
Iteration over array of objects
Counting Cards
@FlyingFish195 did you understand the instructions?
Why is not pushing? :@@
function whatIsInAName(collection, source) {
var arr = [],b;
for (var i=0;i<collection.lenght;i++){
if(collection[i].last===source.last){
arr.push(collection[i]);
}
}
return arr;
}
whatIsInAName(
[{ first: "Romeo", last: "Montague" },
{ first: "Mercutio", last: null },
{ first: "Tybalt", last: "Capulet" }],
{ last: "Capulet" }
);
Please help me with profile lookup task
@mayank1101 your code?
counting card solution @FlyingFish195
switch(card){
case 2:
case 3:
case 4:
case 5:
case 6:
count += 1;
break;
case 7:
case 8:
case 9:
count += 0;
break;
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count -= 1;
break;
}
if(count > 0){
return count + " Bet";
}
else if(count <= 0){
return count + " Hold";
}
Teaching someone isn't the same as giving them the answer.
@mayank1101 pls, no direct answers.