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Has anyone used the npm husky package??
What is that?
@megma_jj_twitter This package: https://www.npmjs.com/package/husky
Hi all, anyone know what is point free style?
@padunk It is a style where you use composition (combining functions) rather than parameters.
It is more common in functional languages, but you can adapt js to the style
http://lucasmreis.github.io/blog/pointfree-javascript/
It is more common in functional languages, but you can adapt js to the style
http://lucasmreis.github.io/blog/pointfree-javascript/
i need help with this challenge. I keep getting the original collection in return
function whatIsInAName(collection, source){
// What's in a name?
var arr = [];
// Only change code below this line
for(var key in source){
for(var x = 0; x < collection.length; x++){
if(collection[x].hasOwnProperty(key)){
arr.push(collection[x]);
}
}
}
// Only change code above this line
return arr;
}what could be the problem?
@tundeiness The outer loop needs to be over collection, and inner through source's keys.
Then you need some loop logic to keep those objects that have matching property values with source, for all the source's keys.
@Masd925 okay...let me tweak that a bit..but why? I should be comparing the source with the elements in the collection No?
@tundeiness You need to check if the looped object (from array collection) has all the keys that source has and also that property values match. If they do, you keep the object.
@Masd925 I tried it right now, still the same result.
@tundeiness Post the code please.
@Masd925
for(var x = 0; x < collection.length; x++){
for(var key in source){
if(collection[x].hasOwnProperty(key)){
arr.push(collection[x]);
}
}
}
@tundeiness If you express it in english then maybe it makes more sense
for each value in collection
keep that value if for every key in source
the value has the key and the property values match
@tundeiness You are pushing the object if it has one source key. You should be pushing if it has all the source's keys and also the property values match.
@tundeiness you aren't checking the value of the properties
@sjames1958gm hmmm..okay
As @Masd925 says you should push only if Every key/value from source is in collection[x]
@tundeiness i'm a bit confused on which to use though.. ".hasOwnProperty" or Object.keys()
@tundeiness A loop solution needs a flag variable. Another way would be to use a suitable array iterator instead of the inner loop.
@sjames1958gm hasOwnProperty yields a boolean
@Masd925 how?
@sjames1958gm the Object.keys() only returns keys and not values...I have even seen index as well.
@tundeiness that only checks one property - you need to check all properties.
The use of a flag works like this
The use of a flag works like this
var all = true;
for (var key in source) {
if key not in collection[x] or values don't match
all = false
}
if (all) push value
@tundeiness What @sjames1958gm posted is the basic loop logic for testing if many conditions hold.
@sjames1958gm okay...now I know about flagging.
Because all is outside the loop it can hold meaning about multiple values (the keys from source) rather than a single one
@Masd925 new lesson learnt on how to test if many conditions hold...(flagging)
@sjames1958gm nods slowly...never knew about flagging though.
@sjames1958gm
for(var key in source){
for(var x = 0; x < collection.length; x++){
if( key !== collection[x]){
all = false;
}else{
arr.push(collection[x]);
}
}
}got an empty array instead....i'm surely doing something the wrong way
@tundeiness The outer loop still needs to be over collection and inner through source's keys.
@Masd925 yeah, I did. but i was still getting empty array instead
@tundeiness Just make the two loops as I told and initialize the flag variable inside outer loop but before the inner loop.
Also, you need to test the flag after the inner loop (inside outer loop).
@Masd925 okay. so with the above for loop am I in the clear? just wanted to know if that's where the problem is..
@tundeiness That is not correct at all. Make the two loops and initialize the flag. Then we can go further.
@Masd925 okay...will show you the codes soon.
@Masd925
for(var x = 0; x < collection.length; x++){
var all = true;
for(var i = 0; i < source.length; i++){
if( source[i] !== collection[x]){
all = false;
}else{
arr.push(collection[x]);
}
}
}
@tundeiness Now
collection[x] is the looped object and source[i] is the looped source key.
@Masd925 okay
@tundeiness You need to check if the looped object doesn't have the property key OR the property values don't match. Use hasOwnProperty and
!==.
@Masd925 okay
@Masd925
source[i] !== collection[x].hasOwnProperty()
@tundeiness The syntax is
obj.hasOwnProperty(key). What is the object and what is the key here?
@Masd925 key is collection[x] sorry...i didn't know I could use this variant as well
@tundeiness
collection[x] is the object and source[i] is the key.
Isn't
source an object, and you need to iterate its properties?
@Blauelf He had a for...in loop that was changed into a (wrong) for loop at some point.
But
source[i] isn't the key even then. Some source_props[i], with var source_props = Object.keys(source); at the beginning would.
@Blauelf That is true, but for...in loop was one way to go. Looping over source_props is another.
Sure. That last code is just confusing and I don't know what's the thought behind.
@Masd925 okay
@tundeiness As @Blauelf spotted, the inner loop needs to be over
Object.keys(source), and not over source which is not an array.
@Blauelf @Masd925 that was my approach earlier on though..I recognise that the confusion is coming from being able to access the property and value of an object separately and that's what I have not mastered
@Masd925 however @Blauelf said something like this yesterday and I was thinking would I not require a for loop for that or what exactly
@tundeiness If you did
for (key in source){...} then key would be the looped source key. That is another way.
Using array iterators is the third way.
You need two loops, an outer over the collection and an inner over the properties. Those two can be implemented in various ways. As I said, I used higher order functions
filter and every instead of for loops. Many ways, you just have to pick one.
@Masd925 @Blauelf the idea behind var source_props = Object.keys(source) is what I don't know. why the source_props when I will still do source_props[i]? that would connote requiring a for loop.
@Masd925 which was what I started with initially...
This would create an array of property names, which you can iterate using a regular for loop.
@tundeiness Yes.
@Masd925 now the comparison part is where the issue was....key !== collection[x]? which is wrong.
@tundeiness It needs to be
collection[x][key]!==source[key]
Combine that with the hasOwnProperty check (
||)
@Blauelf meaning 2 for loops for the collection right? ...i'm now just getting it..so what I now have in the inner for loop is what I will compare with the source using Object.keys() right?
@Masd925 okay...I now get the whole idea...2 for loop for the collection not one for the source and one for the collection like I earlier thought.
@tundeiness Outer loop for collection, inner loop source properties. So for each element of the
collection, you test it for all of source's properties.
And after the inner loop you decide whether to push (if you go the push route). Don't push in the inner loop.
@Blauelf okay...permit me to go back to the drawing board again...let me put it in codes :)
@sjames1958gm thank you. Quite confusing with all that arrow functions :smile:
padunk sends brownie points to @sjames1958gm :sparkles: :thumbsup: :sparkles:
:star2: 9235 | @sjames1958gm |http://www.freecodecamp.org/sjames1958gm
@padunk I am reading and re-reading that article
:wave:
Greetings ladies and gents.
Morning :wave:
whats up bruv.
Just getting into work..you?
here at work. Remote in my machine at home and trying to build up my project.
Psh.. I just build my shit on my work computer lol
@JLuboff face palm. I can't bother will the annoyance from my team lead. He is a slave driver.
Tell him to chill brah
Morning
sup?
workin man
you?
I am here working on my little school app.
@cmccormack Morning
@RoniqueRicketts not done with that yet??
@JLuboff heya :D
What up
Working on a master template for work so I no longer have to build templates, any engineer can use it to build their own. Less work for me!
Template for networking device..?
for our software-defined stuff, yeah
Ah. Neat!
yeah it's been a pain working on creating standards for everything globally but I think we're finally close so I can start working on more fun projects like a frontend for our sdwan controllers
what's up with you?
Accomplished my three tasks of the morning, so happy about that lol. Still working on creating an image for WDS but.. getting closer on that I think
dang three tasks and it's only 09:20, nice work :D
Luckily they were quick tasks haha (create a new user/send email to supervisor, add users to two different all-in-ones for scanning (damn office moves), and setup a computer)
Any other day I'd probably have been a little lazier about it... :P
Hopefully can get some programming in today too
Man you do so much different stuff
Thats what happens when you're in a small team. Only 4 of us for a company of ~250? It might be 200 now.. not sure. But ya...all of us (except our network guy) are sort of jack of all trades
yeah I bet. Ever want something more consistent?
I'm being tailored into the programming/database role..and I'd like for that to be my standard role..but most likely would still be doing everything i currently do.. so.. yes I would like for it to be consistent but I also know that position isn't always busy (if that all makes sense) @cmccormack
yeah totally makes sense at your company
@cmccormack not yet I am working slowly because Its also a learning moment for me please work is distracting me
At one point we were a team of 5, but I don't think they would do that again unless they got someone cheap for helpdesk (I was hired on for helpdesk at what I would say is a much higher than normal helpdesk pay)
that should be fairly easy - get an intern or something straight out of uni
Or something out of uni? What else comes out besides people? :P
oops someone haha
Ya.. well.. they probably still don't want to do that. Not until oil is back at 90+ a barrel
long drive?
long drive where?
your office? You mentioned oil
oh wait isn't your company oil based?
Lol ya, we're an oil and gas company
hah duh sorry
All good
time to code :D
@bradtaniguchi Right there with you!
:+1:
Actually..trying to figure out some code I have....it doesn't quite make sense...
Ah! Figured it out
Thats what happens when you copy and paste code from another section :P
I try to never copy paste code cuse half the time I forget to change something :/
Time to write some tests before the code, this time ;D
@bradtaniguchi Only reason I did is becuase it does the same thing only difference is the user who submitted the post request. If its a regular individual, it only processes their portion of the form. If it's the user who can modify anyone (stupid..I know) than it processes everyones portion of the form so I have to handle the data slightly different
beware, copy pasting code is a path to the dark side
hehe Im just kidding
Oh but it is. I still need to figure out a way to keep the modifications in check on Database side too (I'm auditing by changing who modified the data last but if the data hasn't changed, no reason to change that person)
I need an if or case statement but have to actually write the code for that
Hmm Im probably to far from the use case to help haha
Ya no worries. Something I have to figure out, which will make me stronger
Im just trying to figureout how to get data from the back XD
You're smarter than me...I'm sure you can figure that out
Oh fancy... Microsoft Word can now read my documents aloud lol
Guys can you tell me how I can filter my
items by date/name ? Found few articles but nothing that really works..
@dbsimeonov what does the data kinda look like?
@bradtaniguchi umm the
items contain names/prices/etc so have not started but just trying to understand the logic. its kind of online shopping website that has the options to put them in those orders. Hope it makes sence
It really depends on your data structure
But you would need to have a date field
If using a database, its pretty simple to order or filter by date or name
Id assume your datas coming back from some database right? So youd probably want to sort them in the DB query, and return just the top few, not all of them
not really, coming from the html :(
Well you could use
.sort() with either name or date but you need to change date into a more useable format like UNIX time
Or just ms I guess
Then do a comparison in the sort
I've done that in the past. Used
moment.js to convert a date into unix (or it may have been just regular ms, can't remember) and did a comparison in my sort
I will start with the easiest I guess which will be price, so the steps are to store all of the values to an array? sort it and then give the order to their parrent elements?
Ya something like that. Keep in mind to give
.sort() an actual callback as let arr = [10, 5, 1, 20];
console.log(arr.sort()); // result: [1, 10, 20, 5]
Versus with a callback
let arr = [10, 5, 1, 20];
console.log(arr.sort((a,b) => a > b)); // result: [1, 5, 10, 20]
amazing man thanks!
Good luck
Or, go with a while loop ;)
let arr = [10, 5, 1, 20];
let swap = true;
while (swap) {
swap = false;
for (let i = 0; i < arr.length - 1; i++) {
if (arr[i] > arr[i + 1]) {
[arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
swap = true;
}
}
}
console.log(arr);
ew for loop barfs
wait, that sorting algo looks terrible :0
I should probably not loop through the entire array again on every loop
let arr = [10, 5, 1, 20];
let swap = true;
let len = arr.length
while (swap) {
len--;
swap = false;
for (let i = 0; i < len; i++) {
if (arr[i] > arr[i + 1]) {
[arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
swap = true;
}
}
}
console.log(arr);
better :)
(still awful, I know) O(n^2)
dont re-invent the wheel, especially if it comes out as a square :P (No offence hehe)
I wonder what algo .sort() uses internally
I heard it uses a special merge-sort internally, but then I might actually be different on different browsers. (but this is only what I heard, could be wrong)
What type of sort is it do you know? @bradtaniguchi (i.e bubble, etc)
Off the top of my head none of them, I forget XD, I got spoiled with
.sort(), but I personally liked heap sort for no other reason than I studied it the most. But if you asked me to make it right now, Id be screwed
Heh
I'd think .sort() would choose an algo based on what's being sorted
@JLuboff Oh I read your question wrong sorry
I think ?
I think I remember them mentioning for smaller arrays .sort() does something simplier
Seems Chrome uses Insertion Sort if the array is less than 10 elements. QuickSort otherwise. Safari uses selection sort, Mozilla uses merge sort.
That code above is bubble sort, which I don't think is useful anywere
I guess it's good if the array is already sorted :laughing:
Interesting
Merge Sort :one:
Bucket sort is the best, can't beat the O(1) runtime :sunglasses:
hey @JLuboff
@tiagocorreiaalmeida Yo
is it today that we are going to fight for the most nasty lines of code?
Ya.. give me like an hour?
sure, let me know
:+1:
does anyone have some example of authentication using react + nodejs with passport on te server in this situatuion using social network strategies, im looking at an example just trying to figure out if there are more possible ways
@tiagocorreiaalmeida i did that and it didn't go well lol
I have an example for you though
@tiagocorreiaalmeida I think @cmccormack has used react and passport?
yeah
but not with a social network
Oh.. you used local auth?
yeah
Ah. Nevermind then
fff, something as simple as doing some checks before I save = death :/
@tiagocorreiaalmeida Alright.. I'm ready a little earlier than I thought
ups sorry want around
@megma_jj_twitter I got it working thanks either way
tiagocorreiaalmeida sends brownie points to @megma_jj_twitter :sparkles: :thumbsup: :sparkles:
api offline
this is my only issue good old facebook doesnt let people turn the api on at the localhost
@JLuboff
Good evening,
I am trying to push all the items of the sorted 2d-array to arr1 if there are none of the same items in arr1.
The problem is that I get this weird result, when logging to the console, where "Hair-Pin" gets added but "Bowling Ball" doesn't. Can someone explain to me what's happening here?
in other words push the values that doesnt exist on the arr1 into it?
@tiagocorreiaalmeida exactly :)
I think I found your issue
if (arr1[k].includes(sorted[l][1]) == false){
@tiagocorreiaalmeida got stuck looking at a printer give me a few (not sure where the timers at)
I think you mean
arr1[k][1] @bradley1492
2min @JLuboff but I can set it to 5 again maybe its better, take your time
I regreated immediately removing that break @bradley1492 :D
@tiagocorreiaalmeida sorry for that crash
@tiagocorreiaalmeida I forgot to mention DON'T REMOVE THE BREAK
either way It seems to be working?
@tiagocorreiaalmeida I dealt with your tip before. It doesn't make a difference becuase the includes method checks on every element in the array anyway I think. I don't have to tell it to look for the first position here specifically... I hope it's clear what I am trying to say
@tiagocorreiaalmeida holy hell. This printer takes forever to warm up
Few more minutes haha
sure np :D
in this case include wont work @bradley1492
sorry I was sleeping on it
@tiagocorreiaalmeida Hm what a pity include seemed like the perfect solution for my needs here
I just don't get it. Why does it seem to work with "Bowling-Ball" but not with "Hair-Pin"
@tiagocorreiaalmeida Alright I'm, in. @cmccormack codefight?
@bradley1492
for (let k = 0; k < arr1.length; k++){
for (let l = 0; l < sorted.length; l++){
if (arr1[k][1].includes(sorted[l][1]) == false){
arr1.push(sorted[l]);
}
}
break;
}
cause
it will check value by value
and it will return that the current position doesnt includes the value sometimes
so it will push it to there
imagine
you are on arr[2]
arr1[2] and you are checking for Bowling Ball
it will return false
im not sure if im being clear :\
console.log(arr1[1].includes(sorted[2][1]));
try this will give you an idea why its not working
so is the printer alive or you just used the hammer method @JLuboff ?
It's alive! Had to power cycle it for it to tell me there was a stuck piece of paper. But it takes a couple minutes to shut down and then even longer to "warm up"
It's a Canon ImageRunner. Great All-In-One device but this particular one is always giving us trouble
did you pet it? some say it helps
:joy:
@tiagocorreiaalmeida ohhh I think I understand. Does include only result in true if in my case both of the item-names are on an identical position in each of the arrays?
includes works on 1d array not 2d :\
@tiagocorreiaalmeida did you just find that out?
nah I knew it but I wasn't thinking about it
the way of doing the exercise you have to do is t ocheck that if every element on the arr1 is differentt from the one you are trying to see if exists
if so then push it
@tiagocorreiaalmeida ah ok hm I thought about that, but then I thought because I am looping through the 2d array, that I am sort of dealing with 1d arrays.... :)
I would reverse things
loop the second array
and for each value check if it doesnt exists on the second one if it exists you can break and avoid the loop from going on
you could also use the method .every
@tiagocorreiaalmeida I also thought about using filter on the sorted array to filter out all the double-listed items, but I then didn't know any further.
Thanks in the meanwhile I'll check out your advice!
Thanks in the meanwhile I'll check out your advice!
bradley1492 sends brownie points to @tiagocorreiaalmeida :sparkles: :thumbsup: :sparkles:
:cookie: 525 | @tiagocorreiaalmeida |http://www.freecodecamp.org/tiagocorreiaalmeida
@JLuboff the first one might sound confusing at first
but the only thing you need to check is that if the next letter on the string is the next letter on the alphabet
@tiagocorreiaalmeida ya got the first one but ran out of time for the last
np, still always good to code one or two ;)
And my co-worker was talking to me lol
charcodeat was definitely the better and qicker way to do that one
does that mean it was 2vs1 ? :|
:D
He doesn't know shit about programming...unless its a cisco switch. He'll run circles around me when it comes to that
I fixed my issue ive been working on for 2 hours by saying screw it :P
Thats a good fix
Best and worse part of using strict typing, when you refactor you turn something off/change it and everything explodes :D
Grr... I hate when my node app hangs for no reason
@JLuboff
no reason...
There was no reason!
None! Ziltch. Zero. Negative reasons!
Maybe a solar flare?
I'll go with that
those things are no joke, we used to have to send out emails when there was a solar flare because our SatCom would be highly impacted
We have issues with your ethernet radios on particular clear sunny days due to I guess refraction off the water
2.4GHz I bet
Correct. We have a few 5 GHz but the majority are 2.4
We moved to higher density, lower power 5Ghz mainly, vast improvement
quite a bit pricier though
We use Ubiquity radios exclusively. They're pretty good and not very expensive. The 2.4's (Rocket M5) were I think $300? for the set (two radios, two dishes). The 5 ghz's models I can't remember but still I think around the same price for the set
Yeah they make good stuff - when oil prices go back up you guys should definitely get some more 5GHz AC Wave 2 APs :D
That'd be cool
Ah... these are the 5GHz radio's we have https://www.ubnt.com/airmax/nanobeam-ac-gen2/ super easy to mount and small which is nice
Their stuff looks so nice
@NikolaNbgd you may enjoy thsse: :fallen_leaf:
@cmccormack They are and super inexpensive in comparison to other options out there. Rarely go down. You can monitor multiple radios from a single web app (unfortunately does not work across all platforms)
@JLuboff i'll take 10!
Do ittt
@cmccormack Don't you have two houses? You could link them up with a pair of radios and then only pay for one internet connection!
Haha it's like 150 miles apart, think they have that range?
Nah...at least the ones I showed dont
I think up to 30 miles
still pretty good
although only as a backhaul
True
Whooo. Think I figured out my SQL query. It's ugly..but..so are most of my queries lol
aaaand all of your tables were dropped
Hahahaha luckily that wouldn't be the worst thing ever but it would be a pain
good man has backups
Meh. Just a development database. I have all my creation steps and what not technically backed up
Once the database is live, it will be backed up though
make sure you also write it out on paper with pen just in case
My hand writing is atrocious. Wouldn't be able to read it (I have my creation steps in a sql file which is part of my git repo)
maybe you should have been a doctor!
I don't think I'm smart enough lol
Everyone is very smart, it's how much we apply ourselves to something that makes it happen
...Fine...I don't like blood
Everyone has blood in them, it's how much we apply ourselves to playing with blood that makes it happen
... or something
:P
When I get blood taken I start to histarically laugh if I look at it, and feel like fainting
I only recently semi-conquered my fear of needles. Still can't look
Just use a knife instead!
Well I'm off for the night, see you all later!
See ya