FreeCodeCamp/HelpJavaScript

Get help on our basic JavaScript and Algorithms Challenges. If you are posting code that is large use Gist - https://gist.github.com/ paste the link here.

Brittani

@Carowyn

thanks @kumquatfelafel

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@camperbot

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Brittani

@Carowyn

Finally got my head wrapped around it. :)

kumquatfelafel

@kumquatfelafel

so... what if we started at the end and tried going towards 0? @Shadilix

Julianne Cho

@jucho893

Hi guys,

are multiple if statements allowed?

Max

@maxiwer

@imRadioactive thank you but I'm still don't understand

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Ahmed Ramy

@Shadilix

@kumquatfelafel like 0!=1 ?

Sai Chand Duppala

@saichandd

@maxiwer what is that you didnt understand

@Shadilix yes 0! = 1

Julianne Cho

@jucho893

function fizzBuzz(number) {    
    var results = [];

    for(var i = 1; i <= number; i++) {

        if((i % 3 !== 0) && (i % 5 !== 0)) {
            results.push(i);

        } else if (i % 3 === 0) {
            results.push("FIZZ");

         } if (i % 5 === 0){
         results.push("BUZZ");

     }  if((i % 3 === 0) && (i % 5 === 0)){
        results.push("FIZZBUZZ");
    }
    return results;
}

Ahmed Ramy

@Shadilix

easy , an if statement where if num == 0 , return 1

@kumquatfelafel

kumquatfelafel

@kumquatfelafel

@Shadilix nothing to do with that. The value num is changing as you go through your for loop, right? But does the value of 0 ever change?

Ahmed Ramy

@Shadilix

ummm ... no

kumquatfelafel

@kumquatfelafel

currently, you're trying to start 5! with 1 and going up. What if we started 5! with 5 and went down?

Ahmed Ramy

@Shadilix

i tried that but here is the problem

its setting i

like in a for loop

for ( var i ; ?? <= num ; i--)

am stuck with this one so thats why i tried the other way around which is a definite infinite loop

Nick Cleary

@Hijerboa

quick question: is there a way to use .replace() in order to replace any non-alphanumberic character with null, or must I use .replace() for each and every one seperately?

Manish Giri

@Manish-Giri

@Hijerboa you can use a regex

kumquatfelafel

@kumquatfelafel

@Shadilix
With regards to starting point: Say we're doing 5!. What is num?
With regards to condition (when to stop): For the factorial of anything, do we multiply by 0? How about 1?

Nick Cleary

@Hijerboa

@Manish-Giri ok thank you

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Ahmed Ramy

@Shadilix

num is the number we want to factoralize in case of 5! , num = 5
and no we dont multiply any factorial by 0 but 1 is viable but expendable

kumquatfelafel

@kumquatfelafel

1 is viable but expendable

good. Not everyone might catch that ;)

@Shadilix So if we're starting at end and working backwards, could num give us our starting point?

Joseph

@revisualize

Hey hey.

Ahmed Ramy

@Shadilix

thanks :D
i am trying something , will show u in a bit

kumquatfelafel

@kumquatfelafel

Ahmed Ramy

@Shadilix

function factorialize(num) {
  if (num === 0)
    {
      return 1;
    }
  for (var i = num ; i >=2 ; i--)
    {
      num *= i;
    }
}

ohh that also didnt work

kumquatfelafel

@kumquatfelafel

@Shadilix
1.where's your return?
2.what happens when num = 1?

Joseph

@revisualize

@Shadilix You know.. It's actually better to count up than to count down.

Saif Ur Rahman

@saifsmailbox98

@Shadilix you are not returning after the for loop and you can put the for loop inside an else.

Joseph

@revisualize

@Shadilix If you count down you could end up with a problem where you break below the loop.

@Shadilix You also don't have a return statement for your function.

@Shadilix You have one if the value of num is 0. But, you don't have one for anything else.

Ahmed Ramy

@Shadilix

opps yea i forgot the return

but when i used the counting "up" ... i ended up with an infinite loop

Stephen James

@sjames1958gm

@Shadilix And you are multiplying by num twice

@Shadilix Did you grow num and try to stop at num?

Ahmed Ramy

@Shadilix

@Shadilix Did you grow num and try to stop at num?
what ? XD

Saif Ur Rahman

@saifsmailbox98

@Shadilix you are also multiplying num with num in the first run

Stephen James

@sjames1958gm

@sjames1958gm i < num while also doing num *= i

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