FreeCodeCamp/HelpJavaScript

Get help on our basic JavaScript and Algorithms Challenges. If you are posting code that is large use Gist - https://gist.github.com/ paste the link here.

pablovvb

@pablovvb

thanks for the tip, @kumquatfelafel . I'll look into it :)

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Johnny O'Sullivan

@johnnyosullivan

@pablovvb on the same problem. finding it trickier than I thought.

function destroyer(arr) { 
 var args = arr.slice.call(arguments);
 for (var i = 1; i < args.length; i++)
 var seek = args[i];
 var destroyed = args[0].filter(function(val){
   return val !== seek;
 });
 return destroyed;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Any advice would be helpful.

kumquatfelafel

@kumquatfelafel

@pablovvb Also note, as @moigithub points out, you can pass values into a function. Or rather, more importantly, you can provide that function with a parameter which enables you to reference a certain value...

pablovvb

@pablovvb

oooh!! that gets me way closer!

@johnnyosullivan in my humble review, I don't get that args[0]. What does destroyed return?

Moisés Man

@moigithub

@johnnyosullivan what value will destroyed have after run this code...

destroyed = 1;
destroyed = 2;
destroyed = 3;

@pablovvb args is a copy of arguments... which is this [[1, 2, 3, 1, 2, 3] , 2 , 3]
soo args[0] is the first element [1, 2, 3, 1, 2, 3]
which is the same as arr

Johnny O'Sullivan

@johnnyosullivan

@moigithub @pablovvb
[1,2,1,2] is what it's returning right now.

Moisés Man

@moigithub

@johnnyosullivan u not answering the question :)
:point_up: 27 de junio de 2017 20:13 1, 2 or 3

Johnny O'Sullivan

@johnnyosullivan

Am I not? Sorry. Let me revisit.

kumquatfelafel

@kumquatfelafel

@johnnyosullivan what value will destroyed have after run this code...
destroyed = 1;
destroyed = 2;
destroyed = 3;
^this bit. Will destroyed be 1?

pablovvb

@pablovvb

@moigithub @johnnyosullivan man, that's cleaner than mine :P I like it!! (and @johnnyosullivan , I'm exactly in the same place)

Johnny O'Sullivan

@johnnyosullivan

@kumquatfelafel @moigithub oh man, I'm having one of those moments...I don't understand the question.

georgebatton

@georgebatton

jnbjk

kumquatfelafel

@kumquatfelafel

@johnnyosullivan If one were to say

var destroyed = 1;
destroyed = 2;
destroyed = 3;
console.log(destroyed);

What would show up in console?

georgebatton

@georgebatton

Why can't I use for Stand in Line: arr.push(item);
var remove=arr.shift(item);

pablovvb

@pablovvb

@johnnyosullivan I think moi is into something with mine as well. I may be replacing once and again the value I want to get

Saif Ur Rahman

@saifsmailbox98

@georgebatton vvv return remove.

kumquatfelafel

@kumquatfelafel

@georgebatton ^^^ Shift doesn't require an argument.

georgebatton

@georgebatton

why does push require one but shift doesn't?

Saif Ur Rahman

@saifsmailbox98

@georgebatton push adds that to the array, shift is used to remove element.

kumquatfelafel

@kumquatfelafel

@georgebatton Shift just removes first element from array. Doesn't really care what we lowly humans and/or rodents have to say. :p
There's no need for any kind of special input in order to remove an element.

Johnny O'Sullivan

@johnnyosullivan

Wouldn't destroyed just be equal to the number you assign it in those cases?

Moisés Man

@moigithub

@johnnyosullivan code runs from top to bottom

@johnnyosullivan but it WONT have all 3 values

it can be 1 OR 2 OR 3... soo what value will be after the code is executed ?

Johnny O'Sullivan

@johnnyosullivan

Moisés Man

@moigithub

yep only last value prevails

kumquatfelafel

@kumquatfelafel

aye

Kent Saeteurn

@sansae

Hi all,
I am working on the "Arguments Optional" challenge. I have tested all 5 cases. The returned results are exactly what FreeCodeCamp wants, however, when click submit, only the top two cases are marked as correct. The last 3, which expects "undefined" to be returned, are marked incorrect. When testing for all 3 undefined cases in FCC's editor window, the returned result is "undefined" (It shows on the left hand column).

Does anyone know why FCC won't recognize the returned values of "undefined"?

kumquatfelafel

@kumquatfelafel

@sansae post code

(if you're doing something like return "undefined"; lose the "")

Johnny O'Sullivan

@johnnyosullivan

ok. so my problem is with the variable seek.

it's only taking the last item in the args array.

Kent Saeteurn

@sansae

@kumquatfelafel https://repl.it/JEqA/67

Moisés Man

@moigithub

@johnnyosullivan soo another concept
a loop repeat code

for (var x=1; x<= 3; x++){
    doSomething(x);
}

will do
doSomething(1)
doSomething(2)
doSomething(3)

kumquatfelafel

@kumquatfelafel

@sansae :point_up_2: see my reply. "undefined" != undefined.
"undefined" is a string that happens to be the word "undefined". undefined, on the other hand, is... well... undefined.

Johnny O'Sullivan

@johnnyosullivan

Thanks @moigithub and @kumquatfelafel . I have to retire for the evening, but you've set me straight.

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Johnny O'Sullivan

@johnnyosullivan

Or on the right path at least.

Kent Saeteurn

@sansae

@kumquatfelafel yikes. i just returned a string didn't I? lol Oops

@kumquatfelafel i fixed it

Moisés Man

@moigithub

@johnnyosullivan soo on ur code.. on each iteration u replacing destroyed values reassigning it
only last filter result prevail

var destroyed = [1, 2, 3, 1, 2, 3].filter() // when seek is 2
var destroyed = [1, 2, 3, 1, 2, 3].filter() // when seek is 3
last one return [1,2,1,2]

Kent Saeteurn

@sansae

@kumquatfelafel thank you!

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