FreeCodeCamp/HelpJavaScript

Get help on our basic JavaScript and Algorithms Challenges. If you are posting code that is large use Gist - https://gist.github.com/ paste the link here.

Manish Giri

@Manish-Giri

@JLuboff that looks like it works, but I can't think coz of the flu, ugh

@JLuboff ty

CamperBot

@camperbot

manish-giri sends brownie points to @jluboff :sparkles: :thumbsup: :sparkles:

:star2: 2187 | @jluboff |http://www.freecodecamp.com/jluboff

Jason Luboff

@JLuboff

my syntax was wrong... should be regex.test(string)

Manish Giri

@Manish-Giri

worked

Jason Luboff

@JLuboff

:+1:

Manish Giri

@Manish-Giri

Jason Luboff

@JLuboff

const alphanumeric = s => { /[A-Za-z\d]+/.test(s) && !/[\s*_!]/.test(s)

Manish Giri

@Manish-Giri

damn ppl have solved it with just one .test

Jason Luboff

@JLuboff

I believe it. My regex aint that strong though so I wouldn't be able to

Manish Giri

@Manish-Giri

s => /^[a-z\d]+$/i.test(s);

so this

Andrew Kay

@andrewjkay

Does anyone know of a way to get around a No 'Access-Control-Allow-Origin' header is present error? Trying to query an API from vanilla JS, don't want to have to use jquery or implement a back end

Jason Luboff

@JLuboff

@Manish-Giri Ya I'd have to look all that up to see what it does lol

Manish Giri

@Manish-Giri

I think this bit - ^[a-z\d]+ - matches start of the input

and this matches the end - [a-z\d]+$

since it doesn't leave scope for anything else in between

maybe that's why it passes?

@JLuboff

Jason Luboff

@JLuboff

...sure!

Addison

@addisonday

More Regex help!! XD.

I am not sure why this matches the last test. It passes all the others. I thought the syntax {num1, num2} matched a range? Is it a bug? Here is my regex:

let ohStr = "Ohhh no";
let ohRegex = /h{3,6}/;
let result = ohRegex.test(ohStr);

\*Your regex should use curly brackets.
Your regex should not match "Ohh no"
Your regex should match "Ohhh no"
Your regex should match "Ohhhh no"
Your regex should match "Ohhhhh no"
Your regex should match "Ohhhhhh no"
Your regex should not match "Ohhhhhhh no"*/

Nick Cleary

@Hijerboa

question: is there a more efficient way to determine if a number is a prime than through a for loop?

Manish Giri

@Manish-Giri

@addisonday link to challenge?

Andrew Kay

@andrewjkay

@Hijerboa a for loop without checking even numbers or numbers that are multiples of those already checked

or a hash of some kind

Nick Cleary

@Hijerboa

@andrewjkay hmm thats not a bad idea

luccifer00

@luccifer00

hi there!

Ronique Ricketts

@RoniqueRicketts

Sup

luccifer00

@luccifer00

 var rank1=[];
  var file1=[];

    for(var i=0;i<input;i++){
      rank1+= String.fromCharCode(i+65);
    file1+= parseInt(i+1);
  }

how can i get file1 return a [1,2,3,4,5....] , only can get a string as "12345..."

i use parseInt to change the number in string to a number... but i also return the "12345...."string

Nick Cleary

@Hijerboa

@luccifer00 use .split("");

that will divide it at each number

luccifer00

@luccifer00

yep, but still divide as string ["1","2","3","4"...]

anyways i was cheking the console.log wrong, so i can try new posibilities... i was a mistake as console.log(file1).Split("); lol thanks @Hijerboa

CamperBot

@camperbot

:cookie: 285 | @hijerboa |http://www.freecodecamp.com/hijerboa

luccifer00 sends brownie points to @hijerboa :sparkles: :thumbsup: :sparkles:

Nick Cleary

@Hijerboa

@camperbot np mate

Hey can anyone explain to me how this has an infinite loop?

function sumPrimes(num) {
    var isPrime = true;
    var counter = 1;
    var sum = 0;
    while(counter <= num){
      if(counter >= 3){
        for(i=3; i<=(counter/2); i+2){
          if(Number.isInteger((counter/i))){
            isPrime = false;
            i = ((counter/2)+1);
          } else {
            isPrime = true;
          }
        }
      } else if(counter >= 2){
        isPrime = false;
      }
      if(isPrime){
        sum += counter;
        counter++;
      }else{
        counter++;
      }
    }
    return sum;
  }

FCC says there's an infinite loop at the if(counter >= 3) part

Coy Sanders

@coymeetsworld

your for loop has a bug

@Hijerboa

Nick Cleary

@Hijerboa

@coymeetsworld does it have to do with the statement i<=(counter/2) ?

Coy Sanders

@coymeetsworld

the logic looks complicated though, i don't like that you are modifying i in other places, it opens yourself to bugs

Nick Cleary

@Hijerboa

ohhhhh its the i+2

it should be i+=2... corrrect?

Coy Sanders

@coymeetsworld

yes

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