I hope VB and C# allow for each to handle this so we don't have to make the code that unnecessary verbose!
Public Overloads Property Children As UIElementCollection Get Return MyBase.Children End Get Set(value As UIElementCollection) MyBase.Children.Clear() For Each child In value MyBase.Children.Add(child) Next End Set End Property
To test to see if a value is within a range of numbers, we can use a simple expression like
min <= value and value <= max.
Is there an equivalent expression to test if a value is within a range that uses a stepping.
I think the following function would suffice, for ascending range. Not too sure about descending ranges.
<extension> function IsBewteen( value As Integer, min As Integer, max As Integer, stepping As Integer) As Boolean If min <= max Then If stepping <= 0 Then Throw New ArgumentOutOfRangeException(NameOf(stepping), "Must have a non-zero positive value.") Return ((min <= value) And (value <= max)) AndAlso ( (value Mod stepping) = (min Mod stepping) ) Else If stepping >=0 Then Throw New ArgumentOutOfRangeException(NameOf(stepping), "Must have a non-zero negative value.") Return value.IsBewteen(max, min, -stepping) End IF End Function
There is still an issue around the
Integer.MaxValue, any suggestion on how to manage them with out resorting to enclosing it in a
try ... catch block?
I want to fairly efficiently to check if a value, is within two bounds but that range isn't continuous but has a regular stepping.
start := 0, finish := 10, stepping:= 2' Ifvalue:=2
then return true. Ifvalue=7` return false.
The following works, assuming we if pass in arguments that satisfies the for loop conditions.
Function IsBetween(value as Integer, start As Integer, finish As Integer, stepping As Integer ) As Boolean For index = start To finish Step stepping If index = value Then Return True Next Return False End Function
But it is rather inefficient, since we could check if a value is within some bounds simply using
Math.Min(start, finish) <= value and value<=Math.Max(start, finish). But this doesn't take into account a stepping. My question is, "Is there an efficient way to do that?"
(value - start) % step == 0?