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`hint [3/8]`

You will need to keep track of the array with the answer and the largest number of each sub-array.

type

`hint`

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`hint [4/8]`

You can work with multidimensional arrays by `Array[Index][SubIndex]`

type

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`hint [1/8]`

Make sure you've tried to hard to solve it yourself before proceeding. :construction:

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`hint [2/8]`

You will get an array that contains sub arrays of numbers and you need to return an array with the largest number from each of the sub arrays.

type

`hint`

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`hint [3/8]`

You will need to keep track of the array with the answer and the largest number of each sub-array.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [4/8]`

You can work with multidimensional arrays by `Array[Index][SubIndex]`

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [5/8]`

Pay close attention to the timing of the storing of variables when working with loops

type

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`hint [6/8]`

**Solutions ahead!**

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`hint [7/8]`

```
function largestOfFour(arr) {
var results = [];
for (var n = 0; n < arr.length; n++) {
var largestNumber = 0;
for (var sb = 0; sb < arr[n].length; sb++) {
if (arr[n][sb] > largestNumber) {
largestNumber = arr[n][sb];
}
}
results[n] = largestNumber;
}
return results;
}
```

- Create a variable to store the results as an array.
- Create an outer loop to iterate through the main array.
- Before going into the inner loop, create a variable to hold the largest number. This must be outside the inner loop.
- Create another for loop to work with the sub-arrays.
- Check if the element of the sub array is larger than the current largest number. If so, then save the number.
- After the inner loop, save the largest number in the variable for the results.

type

`hint`

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actually I guess it's setting each iteration of [n] to largest number after all the other work has been done

function largestOfFour(arr) {

return arr.map((v)=>v.sort()[v.length-1]);

}

return arr.map((v)=>v.sort()[v.length-1]);

}