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`hint [1/8]`

Make sure you've tried to hard to solve it yourself before proceeding. :construction:

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [2/8]`

You will need to gather all the **Fibonacci** numbers and then check for the odd ones. Once you get the odd ones then you will add them all. The last number should be the number given as a parameter if it actually happens to be an off Fibonacci number.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [3/8]`

To get the next number of the series, you need to add the current one to the previous and that will give you the next one.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [4/8]`

To check if a number is even all you have to check is if that number % 2 == 0.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [5/8]`

As you get the next odd one, don't forget to add it to a global variable that can be returned at the end. `result += currNumber;`

Will do the trick.

type

`hint`

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`hint [6/8]`

**Solution ahead!**

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [7/8]`

```
function sumFibs(num) {
var prevNumber = 0;
var currNumber = 1;
var result = 0;
while (currNumber <= num) {
if (currNumber % 2 !== 0) {
result += currNumber;
}
currNumber += prevNumber;
prevNumber = currNumber - prevNumber;
}
return result;
}
```

- Create a variable to keep record of the current and previous numbers along with the result that will be returned.
- Use a while loop to make sure we do not go over the number given as parameter.
- We use the modulo operand to check if the current number is odd or even. If even add it to the result.
- Complete the Fibonacci circle by rotating getting the next number and swapping values after.
- Return the result.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [8/8]`

```
function sumFibs(num) {
// create an array of fib numbers till num
var arrFib = [1];
for (var i = 1; i <=num;) {
arrFib.push(i);
i = arrFib[arrFib.length - 1] + arrFib[arrFib.length - 2];
}
// return the sum of odd numbers from the array
var res = arrFib.reduce(function(prev, curr) {
if (curr%2 !== 0) return prev + curr;
else return prev;
});
return res;
}
```

- See comments

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`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [1/8]`

Make sure you've tried to hard to solve it yourself before proceeding. :construction:

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [2/8]`

You will need to gather all the **Fibonacci** numbers and then check for the odd ones. Once you get the odd ones then you will add them all. The last number should be the number given as a parameter if it actually happens to be an off Fibonacci number.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [3/8]`

To get the next number of the series, you need to add the current one to the previous and that will give you the next one.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [4/8]`

To check if a number is even all you have to check is if that number % 2 == 0.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [5/8]`

As you get the next odd one, don't forget to add it to a global variable that can be returned at the end. `result += currNumber;`

Will do the trick.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [1/8]`

Make sure you've tried to hard to solve it yourself before proceeding. :construction:

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [2/8]`

You will need to gather all the **Fibonacci** numbers and then check for the odd ones. Once you get the odd ones then you will add them all. The last number should be the number given as a parameter if it actually happens to be an off Fibonacci number.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [3/8]`

To get the next number of the series, you need to add the current one to the previous and that will give you the next one.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [4/8]`

To check if a number is even all you have to check is if that number % 2 == 0.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [5/8]`

As you get the next odd one, don't forget to add it to a global variable that can be returned at the end. `result += currNumber;`

Will do the trick.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [6/8]`

**Solution ahead!**

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [7/8]`

```
function sumFibs(num) {
var prevNumber = 0;
var currNumber = 1;
var result = 0;
while (currNumber <= num) {
if (currNumber % 2 !== 0) {
result += currNumber;
}
currNumber += prevNumber;
prevNumber = currNumber - prevNumber;
}
return result;
}
```

- Create a variable to keep record of the current and previous numbers along with the result that will be returned.
- Use a while loop to make sure we do not go over the number given as parameter.
- We use the modulo operand to check if the current number is odd or even. If even add it to the result.
- Complete the Fibonacci circle by rotating getting the next number and swapping values after.
- Return the result.

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [1/1]`

Make sure you've tried to hard to solve it yourself before proceeding. :construction:

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]

`hint [1/1]`

Make sure you've tried to hard to solve it yourself before proceeding. :construction:

type

`hint`

for next hint :pencil: [Contribute at the FCC Wiki]