Hello
I wonder if anyone could explain this code in C++/Arduino.
int led = 4;
int speed = 100;
void setup(){
pinMode(2, INPUT);
pinMode(12, INPUT);
pinMode(4, OUTPUT);
pinMode(5, OUTPUT);
pinMode(6, OUTPUT);
pinMode(7, OUTPUT);
pinMode(8, OUTPUT);
}
void loop(){
if (digitalRead(2) == HIGH){
speed = 50;
}
else {
speed = 150;
}
if (digitalRead(12) == HIGH){
digitalWrite(led, HIGH);
} else {
digitalWrite(led, LOW);
led = led + 1;
if (led > 8) {
led = 4;
}
digitalWrite(led, HIGH);
delay(speed);
}
}
I do not understand about these speed set to 50 or 150 in the if statements
But I was typing this and I think I get it.. I did not see the 'delay(speed)' at the end. So if pin 2 is HIGH (on) and speed will contain 50 otherwise speed will contain 150. Then digitalWrite(led, HIGH) will be on depending on the speed (seconds).
If what ever is connected to pin 2 is high, then toggle the LED, and wait 50 milliseconds. If it is low, toggle the LED and wait 150 milliseconds
Oh ok I get it, I don't remember what pin 2 is but pin 12 is the push button, so if I push the button then the pin 4 will be high otherwise pin 4 will be low but only things that I am confused is why there is
led = led +1 if pin 4 is low. I understand that led increase by 1, between pin 4 to 8.
if pin 12 is low*
I assume you have 5 LEDs wired up to pins 4, 5, 6, 7, 8
Yeah
Every time it loops through the code, it accesses the next LED in the sequence.
After it talks to the LED on pin 8, it goes back to the LED on pin 4
Ok I understand that part
Ok, I am just guessing, if I press and hold the push button then not press then it randomly pick any led between 4 to 8 to be high?
I think the delay is on the wrong line.
If the button is pressed, it stops on an LED
oh yeah
It would probably look random
Is this like a skill tester or something?
Not really.. I think we are just playing around with the part, hold on I will link you about this part
You need to swap the digitalWrite(led, HIGH) and delay(speed) lines around
Otherwise the LED is transitioning from LOW to HIGH faster than you can see it
Assuming you want to see if flash
Sorry I can't tell if the code is wrong but I missed the class so I had to copy and paste the code in the Arduino IDE from oneNote.
I wish I have my own digital sandbox so I can play around with it
Pin 2 is the slide switch. That controls the flash speed.
Ah. Wait
I see what it's trying to do.
It just say on or off switch, I'm assuming if the switch is off, speed will contain 50 otherwise 150
The LEDs will chase at the selected speed, unless you hold do the push button in which case they will stop.
Oh, this does make sense
So depending on the switch, LEDS will chase at the selected speed.
So the basic flow: Turn off the last LED that was turned on, increment the LED counter (If it is bigger than 8, set it to 4), then turn on the next LED. Sleep for some time (depending on the slide switch). Keep doing that. If the use holds the push button, keep the current LED on.
about this line
if (digitalRead(12) == HIGH){
digitalWrite(led, HIGH);
}LEDs will chase at the selected speed depending on the switch, so if I press down the button (pin 12) then pin 4 will high. Correct?
Yup
Ok I am closer understanding this clearing
Okay this line is what confused me the most
} else {
digitalWrite(led, LOW);
led = led + 1;
if (led > 8) {
led = 4;
}
if pin 12 is not high, led increase by 4 and if led is greater than 8, it go back to 4. But what does this do exactly?
led increase by 1*
If pin 12 is low, then set the LED on pin $led to LOW. Add 1 to $led. If the value of $led is greater than 8 (Which is the last pin with an LED on it), set $led to 4 (Which is the first pin with an LED on it).
So none of the led will be high?
Might be easier if you think about it this way. Say LED 4 is high (led = 4). This code turns off LED 4, then adds one to the led variable. The next line then turns on LED 5 (because led now = 5)
On the next run, the code turns off LED 5, adds on to the led variable (so it is now 6) then turns on LED 6
I get what you are saying but how is each led turned on?
If LED 8 was on, first we turn off LED 8. Adding one to it will make it 9. There is no LED on pin 9 - so, instead, it sets the led variable to 4, turning on LED 4.
digitalWrite(led, HIGH); on the next line
oh facepalm
@madpilot I was just reviewing the code, now I understand clearly. Thank you!
No worries
Not sure if it was a cut/paste issue, but if you indent the code a bit better, it'll be easier to read and understand what is going on
Oops, I forgot to ask you a question
Why is speed set to 100? Does it matter?
It doesn't matter - it gets set to 50 or 150 on the first run on the loop anyway.
Ah, I understand
Thanks again
No worries!