this is probably everything that'll go in 0.1.8 (except for documentation) so feedback would be appreciated
@nrinaudo I'm looking at Scala(-friendly) tools for transforming XSDs. For starters, I just want to be able to remove a list of xpaths from a document (in this case, those XPaths would just happen to be XPaths in an XSD). Is there an API to do this in Kantan? would it be reasonable to add something like
"<users><user id='1'/><user id='2'/></users>".removeXPath(xp"//user/@id")? Related, I guess having an API for writing to an XML document would be good: val newDoc = "<users><user id='1'/><user id='2'/></users>".setXPath[Int](xp"//user/@id", 2), perhaps
Maybe that's out of scope for Kantan, but just wanted to check here first
I'll plan to implement a separate, small library that is Kantan-friendly
I suppose that, if you're familiar with Java DOM, you could get some of your use cases to work. Do you know, for example, how to remove a set of
Nodes from an existing Document?
because if so, you can absolutely execute an xpath query on a
Document and get the result(s) as Nodes. If you know how to do the rest, you're set.
by the same token, if you know how to modify the content of a
Node, you could get an xpath query running that'd return your target Node and update that
looks like it's possible:
oh thanks, I found another SO link with some suggestions along those lines, I think - https://stackoverflow.com/questions/6124239/how-to-update-xml-using-xpath-and-java - but haven't had a chance to go through it in detail yet
Have just found this, looks great so far. Am a bit stuck with doing fall-back resolutions on case classes, I want to be able to do an orElse, something like:
case class Example(a: String, b: String)
NodeDecoder.decode(
xp”//a”,
xp”//b”.orElse(xp”//c”)
)(Example.apply)Is there a neat way to do something like that?
(haven't tried it, it's something I vaguely seem to remember from when I did a lot more xpath than nowadays)
From what I can see
| is a union operator in XPath - selects these nodes OR those nodes
do you know what version of XPath is supported by kantan.xpath?
not entirely sure, whatever is supported by the JVM
Looks like it’s XPath 1.0: https://docs.oracle.com/javase/8/docs/api/javax/xml/xpath/package-summary.html
I guess I could use
.orElse(…) and another query if I wanted
I couldn’t work out why the
Compiler.xpath1 call was needed - in other places it looks as if it acts as an implicit conversion
Xml isn’t a thing that happens much in Scala world
well, feel free to ask questions you might have about the project here, that's what it's made for. I try to keep the documentation comprehensive and up to date, so I encourage you to have a look if you'd like to learn more and see if it fits your needs
(and to have a look at its sister projects, kantan.regex and kantan.csv, for basically the same library, but for regular expressions and csv)
hey I am interested in doing somewhat user-friendly XML diff of two documents programmatically. I found a number of useful references on the Java side and before I use them, I am curious as to whether some or much of it is already available in kantan.xpath. The input XML documents are created with a PrettyPrinter and thus have newlines in reasonable places. So the input to diff is pretty-printed XML docs (an assumption I can make that one would normally not make). I am looking at setting client data of line number with each node in the 2 XML documents I am comparing (I found this: https://eyalsch.wordpress.com/2010/11/30/xml-dom-2/). And finally XMLUnit for Java 2.x seems to have sufficient flexibility for what I am trying to do, namely order of child nodes is not important for comparison (something called DifferenceEvaluators.downgradeDifferencesToEqual(ComparisonType.CHILD_NODELIST_SEQUENCE)))
The general gist of what I am trying to do is something similar to Unix diff but accounting for some of the above requirements, showing what is different on both sides, what exists only one side and the line numbers associated with the nodes that appear in the report.