pywinauto/pywinauto

Windows GUI Automation with Python (64-bit Py3 compatible)

Vasily Ryabov

@vasily-v-ryabov

Sorry for delayed replies on the issues. A hot week.

Sripad Sahu

@sripad96_gitlab

hey,

if i use thi line i am getting error

dlg.Project.print_control_identifiers()

error is : raise ElementNotFoundError(kwargs)
pywinauto.findwindows.ElementNotFoundError: {'title_re': '.* Pix4Ddiscovey Non - Commercial', 'backend': 'uia', 'process': 2944}

any suggestions???

i am working on a project to automate a thirdparty app made on qt

but unable to use : dlg.File_tab.click(); dlg.child_window(title='Open', control_type='MenuItem', found_index=0).invoke(); etc like commands

any suggestions on where i might be going wrong or how to automate a 3rd party app made from QT using pywinauto

Vasily Ryabov

@vasily-v-ryabov

Hi @sripad96_gitlab for the first error it's not clear how dlg was defined. This is important, because it looks like dlg specification produced this error, not dlg.Project. For dlg.Project it would be something like ElementNotFoundError: {'best_match': 'Project', 'backend': 'uia', 'process': 2944}.

Menu item in a drop down submenu has some differences for Qt apps. It is often child of top-level window. Example for WireShark (which is Qt5 app): wireshark.py, line 58. Maybe .select() is more proper action for this menu item.

Sripad Sahu

@sripad96_gitlab

okay.. thank you....

I will look into the examples and try to solve it

one more doubt i had

how to switch tabs ????

Vasily Ryabov

@vasily-v-ryabov

I need to take a look. I have seen many cases for Qt apps where tabs are owner drawn. It might be a problem.

Vasily Ryabov

@vasily-v-ryabov

For WireShark it works this way: app.Wireshark_Capture_Interfaces.child_window(title="Input", control_type="TabItem").click_input() (not obvious, can be improved for Qt5 apps).

Vasily Ryabov

@vasily-v-ryabov

@sripad96_gitlab I've submitted an issue to keep it in mind for the future: pywinauto/pywinauto#561

Sripad Sahu

@sripad96_gitlab

@vasily-v-ryabov thank you. Yes few of the tab items are owner drawn so i have to use the click() function to access them, personally which i dont like. It would be very helpful if we can get some function to access the owner drawn items.

Vasily Ryabov

@vasily-v-ryabov

It’s very hard to work with owner drawn items. Some of them may need DLL injection with some Qt-specific stuff or other deep investigation. The result is not guaranteed anyway. The easiest workarounds are (1) image recognition (using “lackey” in Python) or click_input by coordinates relative to nearest recognized window/element on the same form which should be more reliable than screen-wide click.

Sripad Sahu

@sripad96_gitlab

okay

and is there any way i can get a list of all the options(items) available in the particular window?

Vasily Ryabov

@vasily-v-ryabov

There is parameter .click_input(coords=(x, y), absolute=False)

Sripad Sahu

@sripad96_gitlab

My aim is to create a JSON or config file with all the parameters as in the settings so that the automation becomees easy and versatile.

There is parameter .click_input(coords=(x, y), absolute=False) : i have tried this function only for the tab items

Vasily Ryabov

@vasily-v-ryabov

For the window specification there is method .print_control_identifiers(). It prints the whole hierarchy or by depth parameter.

If you need to walk the hierarchy programmatically, use .children() and .descendants().

Sripad Sahu

@sripad96_gitlab

print_control_identifiers() function only gives the control name and the class, i also want to know the state. for example : if there are few checkboxes and drip downs and radio buttons , i want to know which of them are selected and what are the options selected. My main motive is to automate it instead of manually writing the json or config file for the entire setting of the program

Vasily Ryabov

@vasily-v-ryabov

OK, then .children() is your choice. States can be retrieved by different methods of every control. It’s good idea to provide unified methods like .state() and/or .capabilities() returning dictionaries of properties. You’re always free to submit a pull request or issue about this. I can’t promise to assign high priority for now though.

Sripad Sahu

@sripad96_gitlab

i have a list of all the descendants in a list, now i want to segregate them according to their type, i.e: store them in different lists /tuple. But i am unable to access them since they are UIAwrapper object. Any idea how to achieve this?

Sripad Sahu

@sripad96_gitlab

dont bother got it

using descendants().get_element_info.name

what is the difference between children and descendants

???

Vasily Ryabov

@vasily-v-ryabov

children() are immediate children (1 level below). .descendants() is a whole sub tree as a plain list.

Sripad Sahu

@sripad96_gitlab

okay... thnak

Sripad Sahu

@sripad96_gitlab

top_window() function doesn't always return the top window ... so is there any other way to get that ... maybe a workaround

Vasily Ryabov

@vasily-v-ryabov

top_window() is not recommended since it creates window specification by handle of first top level window at the moment of creation.

Good way is app.window(active_only=True), but it assumes the window should be in focus.

Also for “uia” backend top window can be child of main form. In this case it should look like app.MainFormTitle.child_window(control_type=“window”, active_only=True).

Sripad Sahu

@sripad96_gitlab

that means i need to create a workaround to replace top_window()

Also for “uia” backend top window can be child of main form. In this case it should look like app.MainFormTitle.child_window(control_type=“window”, active_only=True).

wouldnt app.MainFormTitle.child_window() will return all the handles of the windows active in the screen??

I am currently facing problem in getting the top active window. My problem statement is to deal with the following situation: if i click a button and nothing happens i.e no window or dialog box is generated, then who to continue the flow so that it doesnt breaks the entire script.

Vasily Ryabov

@vasily-v-ryabov

You can check that some window didn’t open by app.MainWindowTitle.SubwindowTitle.wait_not(“exists”, timeout=10) during 10 seconds. Or use method .exists(timeout=10) which returns True/False instead of raising exception.

.child_window() creates window specification (to find automatically or to apply .wait()/.wait_not()), it doesn’t list all children. Method .children() or .descendants() is what you need to list child controls.

You can find section “Waiting for long operations” in the docs after reading the Getting Started Guide.

amursa

@amursa

Здравствуйте, в UIA прошелся инспектором по меню. отрыть 2го уровня меню удалось, но никак не может нажать на кнопку. Использовал, click, invoke, select , - падает просто указывая на строку вызова. app.UntitledNotepad.menu_select("File -> Exit") - работает, в другом приложении не работает - main_window.MenuSelect('Setup->Securities & Parties->Securities').click() - не работает. Cмог открыть меню, не не позволяет нажать на поледий отрытый елемент:
main_window.window(control_type="MenuBar", title="CrdMenuStrip").child_window(control_type="MenuItem", title="Setup").select()
main_window.window(control_type="MenuBar", title="CrdMenuStrip").child_window(control_type="MenuItem", title="Setup").\
child_window(control_type="MenuItem", title="Securities & Parties").select()
main_window.window(control_type="MenuBar", title="CrdMenuStrip").child_window(control_type="MenuItem", title="Setup"). \
child_window(control_type="MenuItem", title="Securities & Parties").child_window(control_type="MenuItem", title="Securities").click()

вегда вылетает ошибка:
def init(self, errors='strict'):
IncrementalDecoder.init(self, errors)

    # undecoded input that is kept between calls to decode()
    self.buffer = b""

amursa

@amursa

All i did id is to change main_window.MenuSelect('Setup->Securities & Parties->Securities').click() to this main_window.menu_select('Setup->Securities & Parties->Securities') and it worked.

Roman Isakov

@Xcqcr_gitlab

Здравствуйте, Василий.

Кажется, что print_control_identifiers() обходит далеко не все объекты, если backend='uia'

Например, Inspect.exe в режиме UI Automation находит гораздо больше "детей", когда print_control_identifiers() от основного окна находит только "родителя".

python:
[IN]
import pywinauto

a = pywinauto.application.Application(backend='uia')
a.connect(process=3936)
p = a.window()
p.print_control_identifiers()

[OUT]
Control Identifiers:

Dialog - '1С:Предприятие - ERP' (L551, T144, R1460, B764)
['1С:Предприятие - ERPDialog', 'Dialog', '1С:Предприятие - ERP']
child_window(title="1С:Предприятие - ERP", control_type="Window")

Where communities thrive

People

Repo info

Activity