Where communities thrive


  • Join over 1.5M+ people
  • Join over 100K+ communities
  • Free without limits
  • Create your own community
People
Repo info
Activity
  • Jan 31 2019 22:17
    CrossEye commented #2779
  • Jan 31 2019 21:04
    ArturAralin commented #2779
  • Jan 31 2019 20:08
    CrossEye commented #2779
  • Jan 31 2019 18:56
    buzzdecafe commented #2631
  • Jan 31 2019 18:09
    ArturAralin commented #2779
  • Jan 31 2019 16:18
    CrossEye commented #2779
  • Jan 31 2019 16:10
    CrossEye commented #2631
  • Jan 31 2019 16:06
    CrossEye commented #2777
  • Jan 31 2019 14:44
    ArturAralin opened #2779
  • Jan 31 2019 07:39
    inferusvv commented #2631
  • Jan 31 2019 03:07
    sespinozj commented #2771
  • Jan 31 2019 02:33
    machad0 commented #2771
  • Jan 31 2019 02:26
    JeffreyChan commented #2777
  • Jan 30 2019 14:30
    CrossEye closed #2777
  • Jan 30 2019 12:13
    vanyadymousky updated the wiki
  • Jan 30 2019 01:42
    JeffreyChan commented #2777
  • Jan 29 2019 21:06
    vanyadymousky updated the wiki
  • Jan 29 2019 16:28
    CrossEye commented #2777
  • Jan 29 2019 15:50
    mbostock commented #2772
  • Jan 29 2019 15:48
    CrossEye commented #2772
David Chase
@davidchase
interesting name translates to pliers ?
Denis Stoyanov
@xgrommx
yes)
Dave Keen
@ccapndave
Is there a function like R.nth, but that takes an array of indexes and returns an array of values?
R.multiNth([0, 2])([1, 2, 3, 4, 5]) => [1, 3]
Kevin Wallace
@kedashoe
@ccapndave R.props can help you there
@maintainers maybe an @see from R.nth to R.props would help?
Dave Keen
@ccapndave
Oh, perfect
Yes a @see would be cool
I have just spent about three hours writing a long complicated Ramda algorithm, only to discover that I can do it in 5 lines
argh
Danielle McLean
@00dani
http://ramdajs.com/0.17/docs/#set and http://ramdajs.com/0.17/docs/#over appear to have exactly the same description and probably shouldn't.
David Chambers
@davidchambers
Thanks, @00Davo. This was fixed in ramda/ramda#1337.
Dave Keen
@ccapndave
Is there a R.mapWithIndex or equivalent function somewhere that I am missing?
Currently I am doing some monstrosity with converge and range
Ludwig Magnusson
@TheLudd
check out addIndex
Dave Keen
@ccapndave
Thanks
That's really higher-order
I like it
Ludwig Magnusson
@TheLudd
Genreal question: What do I need to do to control the text in this view on gihub. I.e where it says "See the upgrade guide for a description of the changes"
David Chambers
@davidchambers
GitHub releases are still mysterious to me. @CrossEye knows his way around them.
Simon Friis Vindum
@paldepind
@TheLudd I think it's controlled by git tags. You make a tag to do a release.
Jakub Korzeniowski
@kujon
just wondering - is lens composition possible in Ramda?
Jakub Korzeniowski
@kujon
  • just figured out the answer, it is left-to-right for lenses as explained here: ramda/ramda#1288
Ludwig Magnusson
@TheLudd
@paldepind But if you look at the tag messages of ramda, they don't contain that text
Scott Sauyet
@CrossEye
I have simply been editing the tag, including the text and making it as a prerelease. No magic.
Kevin
@kevinwshin
Why does
R.compose(R.map(R.__, [1,2,3]), R.add)(1)
not work? And what is the difference between that and
R.compose(R.map(R.__, [1,2,3]), R.identity)(R.add(1))?
Scott Sauyet
@CrossEye

This would work:

R.compose(R.map(R.__, [1,2,3]))(R.add(1));  //=> [2, 3, 4]

The original is trying to map the binary function add over [1, 2, 3], which doesn't make sense, then assuming the result is a function, and calling it with value 1.

map needs a unary function.
Scott Sauyet
@CrossEye

I'm exaggerating when I say that doesn't make sense. It returns a list of functions, essentially equivalent to [add(1), add(2), add(3)];

R.map(R.flip(R.call)(5), R.map(R.add, [1, 2, 3])); //=> [6, 7, 8]

But I don't think that's the sort of behavior you're looking for.

Kevin
@kevinwshin
I thought compose would give 1 to add, then give add(1) to map. Am I misunderstanding?
Scott Sauyet
@CrossEye
Sorry, I misread. You're right, it should, in my opinion.
I believe we broke compose in v16 or v17. I'm planning on writing up a proposal to reverse that. I was planning on doing it days ago, but life got in the way.
Kevin
@kevinwshin
Oh, good to know. Thanks for taking a look. If it helps, I think pipe is also behaving the same way.
Scott Sauyet
@CrossEye
Yes, it was the same check-in.
We're having lots of discussions right now about compose/pipe, and we need to figure out how to deal with this.
This did work in v15: http://bit.ly/1O0uEki
But it broke in 16.
ramda/ramda#1318 discusses some of the problems.
Matthew Steedman
@knubie
Hi, I'm wondering, is there a variadic version of R.concat?
Matthew Steedman
@knubie
i was attempting to write R.converge(R.concat, fn1, fn2, fn3) but instead had to write R.converge(R.concat, R.converge(R.concat, fn1, fn2), fn3)
Scott Sauyet
@CrossEye
Ramda doesn't have one. You could probably define one as:
var concatAll = R.unapply(R.reduce(R.concat, []));
And then:
R.converge(concatAll, 
           R.map(R.add(1)),
           R.map(R.multiply(3)), 
           R.map(R.flip(R.divide)(2)) 
          )([2, 4, 6]);
//=> [3, 5, 7, 6, 12, 18, 1, 2, 3]
Matthew Steedman
@knubie
I see, thanks!
trbrc
@trbrc
so. i've been using ramda for a couple of months now.
and I'm really in love with the idea. but I don't know, maybe I'm alone in feeling this... it feels like whenever I try to do anything real by composing ramda functions, i always go down a rathole.
like i'm spending hours doing something that would take minutes with some plain old imperative code.
and when I return to my code later, it seems completely incomprehensible.
is this normal? have I just not reached zen yet?
trbrc
@trbrc
i asked a question here two weeks ago or so about the best way to do something, and solved it with some help from the channel. but then it turns out... i hadn't solved it at all. the solution just randomly happened to work for the one test case i used as an example.